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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#57780#4398. Luxury cruise shipqinjianbinAC ✓2ms3808kbC++17700b2022-10-22 21:31:312022-10-22 21:31:32

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-10-22 21:31:32]
  • 评测
  • 测评结果:AC
  • 用时:2ms
  • 内存:3808kb
  • [2022-10-22 21:31:31]
  • 提交

answer

#include<bits/stdc++.h>
#define rep(i, a, b) for(int i = (a); i < (b); i++)
#define _for(i, a, b) for(int i = (a); i <= (b); i++)
using namespace std;

typedef long long ll;
const int N = 1e3 + 10;
int f[N];

int main()
{
	memset(f, 0x3f, sizeof f);
	f[0] = 0;

	int w[] = {7, 31};
	_for(i, 1, 1e3)
		rep(j, 0, 2)
			if(i - w[j] >= 0)
				f[i] = min(f[i], f[i - w[j]] + 1);
	
	int T; scanf("%d", &T);
	while(T--)
	{
		ll x; scanf("%lld", &x);

		if(x <= 365) 
		{
			printf("%d\n", f[x] > 1e9 ? -1 : f[x]);
			continue;
		}

		if(f[x % 365] <= 1e9) printf("%lld\n", x / 365 + f[x % 365]);
		else printf("%lld\n", x / 365 - 1 + f[(x % 365) + 365]);
	}

	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 2ms
memory: 3808kb

input:

1000
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101...

output:

-1
-1
-1
-1
-1
-1
1
-1
-1
-1
-1
-1
-1
2
-1
-1
-1
-1
-1
-1
3
-1
-1
-1
-1
-1
-1
4
-1
-1
1
-1
-1
-1
5
-1
-1
2
-1
-1
-1
6
-1
-1
3
-1
-1
-1
7
-1
-1
4
-1
-1
-1
8
-1
-1
5
-1
-1
2
9
-1
-1
6
-1
-1
3
10
-1
-1
7
-1
-1
4
11
-1
-1
8
-1
-1
5
12
-1
-1
9
-1
-1
6
13
-1
3
10
-1
-1
7
14
-1
4
11
-1
-1
8
15
-1
5
12
-1
-...

result:

ok 1000 lines