QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#577700#9136. Exponent CalculatorMiniLongAC ✓0ms3872kbC++173.0kb2024-09-20 14:10:302024-09-20 14:10:32

Judging History

你现在查看的是最新测评结果

  • [2024-09-20 14:10:32]
  • 评测
  • 测评结果:AC
  • 用时:0ms
  • 内存:3872kb
  • [2024-09-20 14:10:30]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const double e = 2.718281828459045;
typedef long double lb;
double a[25];
double t = log10(e);
int main(){
    int t = 10;
    lb h = (1 << t);
    lb x = 0;
    // scanf("%Lf", &x);
    lb ans = expl(x);
    puts("25");
    printf("$1 = $1 * %.10Lf\n", ((lb)1.00 / h));
    puts("$0 = $1 + 1");
    puts("$2 = $1 + 0");
    x = x * ((lb)1.00 / h);
    lb a = x + 1, b = x;
    _rep(i, 2, 5){
        b = b * x;
        b = b * (1.00 / (lb)i);
        a = a + b;
        puts("$2 = $2 * $1");
        printf("$2 = $2 * %.20Lf\n", 1.00 / (lb)i);
        puts("$0 = $0 + $2");
    }
    _rep(i, 1, t) puts("$0 = $0 * $0"), a = a * a;
    // printf("%.20Lf\n", a);
    // printf("%.15Lf\n", abs((a - ans) / ans));
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3872kb

input:

input

output:

25
$1 = $1 * 0.0009765625
$0 = $1 + 1
$2 = $1 + 0
$2 = $2 * $1
$2 = $2 * 0.50000000000000000000
$0 = $0 + $2
$2 = $2 * $1
$2 = $2 * 0.33333333333333333334
$0 = $0 + $2
$2 = $2 * $1
$2 = $2 * 0.25000000000000000000
$0 = $0 + $2
$2 = $2 * $1
$2 = $2 * 0.20000000000000000000
$0 = $0 + $2
$0 = $0 * $0
$...

result:

ok max relative diff is 8.04772e-11. Checker runtime is 159 ms

Extra Test:

score: 0
Extra Test Passed