QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#576677 | #9310. Permutation Counting 4 | Dukerki | TL | 0ms | 7588kb | C++20 | 940b | 2024-09-19 21:32:33 | 2024-09-19 21:32:34 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxN = 1e6 + 5;
int fa[maxN];
int find(int x)
{
if (fa[x] == x)
{
return x;
}
else
{
return fa[x] = find(fa[x]);
}
}
bool unite(int x, int y)
{
int xf = find(x), yf = find(y);
if (xf == yf)
{
return true;
}
else
{
fa[yf] = xf;
return false;
}
}
void EachT()
{
for (int i = 0; i < maxN; i++)
{
fa[i] = i;
}
int n;
cin >> n;
int ans = 1;
for (int i = 0; i < n; i++)
{
int a, b;
cin >> a >> b;
if (unite(a, b + 1))
{
ans = 0;
}
}
cout << ans << endl;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int t;
cin >> t;
while (t--)
{
EachT();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 7588kb
input:
4 5 1 2 1 5 1 2 1 2 2 2 5 1 1 2 4 2 3 5 5 3 4 5 3 5 1 2 3 4 3 5 3 3 5 1 5 1 4 4 5 5 5 1 2
output:
0 1 0 0
result:
ok 4 tokens
Test #2:
score: -100
Time Limit Exceeded
input:
66725 14 7 7 4 6 7 8 8 13 2 13 6 13 6 10 14 14 1 10 9 11 7 9 3 8 4 12 5 12 12 2 6 3 6 7 11 2 5 1 1 6 12 8 12 2 3 7 9 7 8 1 10 1 4 10 4 8 4 4 6 10 9 10 2 3 2 7 1 3 3 4 2 2 3 10 20 3 12 10 14 19 20 19 20 1 9 7 9 13 16 17 17 16 18 2 11 5 19 6 17 11 17 3 6 3 11 7 20 8 17 3 18 10 15 9 20 16 5 10 2 10 2 1...
output:
1 1 0 0 1 0 1 1 0 1 1 0 0 0 0 0 1 0 1 0 0 1 0 0 0 1 0 1 0 0 0 0 1 0 1 1 1 1 1 0 1 0 1 1 1 1 1 1 1 1 0 1 1 0 0 0 0 0 0 1 0 1 1 0 1 1 1 0 1 0 1 0 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 0 1 0 0 1 1 0 0 1 1 0 0 1 1 1 1 1 1 0 0 1 1 1 0 0 1 1 0 0 1 0 1 0 1 0 1 0 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0 1 0 0 1 0 1 1 ...