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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#576677#9310. Permutation Counting 4DukerkiTL 0ms7588kbC++20940b2024-09-19 21:32:332024-09-19 21:32:34

Judging History

你现在查看的是最新测评结果

  • [2024-09-19 21:32:34]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:7588kb
  • [2024-09-19 21:32:33]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxN = 1e6 + 5;
int fa[maxN];
int find(int x)
{
    if (fa[x] == x)
    {
        return x;
    }
    else
    {
        return fa[x] = find(fa[x]);
    }
}
bool unite(int x, int y)
{
    int xf = find(x), yf = find(y);
    if (xf == yf)
    {
        return true;
    }
    else
    {
        fa[yf] = xf;
        return false;
    }
}
void EachT()
{
    for (int i = 0; i < maxN; i++)
    {
        fa[i] = i;
    }
    int n;
    cin >> n;
    int ans = 1;
    for (int i = 0; i < n; i++)
    {
        int a, b;
        cin >> a >> b;
        if (unite(a, b + 1))
        {
            ans = 0;
        }
    }
    cout << ans << endl;
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);
    int t;
    cin >> t;
    while (t--)
    {
        EachT();
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 7588kb

input:

4
5
1 2
1 5
1 2
1 2
2 2
5
1 1
2 4
2 3
5 5
3 4
5
3 5
1 2
3 4
3 5
3 3
5
1 5
1 4
4 5
5 5
1 2

output:

0
1
0
0

result:

ok 4 tokens

Test #2:

score: -100
Time Limit Exceeded

input:

66725
14
7 7
4 6
7 8
8 13
2 13
6 13
6 10
14 14
1 10
9 11
7 9
3 8
4 12
5 12
12
2 6
3 6
7 11
2 5
1 1
6 12
8 12
2 3
7 9
7 8
1 10
1 4
10
4 8
4 4
6 10
9 10
2 3
2 7
1 3
3 4
2 2
3 10
20
3 12
10 14
19 20
19 20
1 9
7 9
13 16
17 17
16 18
2 11
5 19
6 17
11 17
3 6
3 11
7 20
8 17
3 18
10 15
9 20
16
5 10
2 10
2 1...

output:

1
1
0
0
1
0
1
1
0
1
1
0
0
0
0
0
1
0
1
0
0
1
0
0
0
1
0
1
0
0
0
0
1
0
1
1
1
1
1
0
1
0
1
1
1
1
1
1
1
1
0
1
1
0
0
0
0
0
0
1
0
1
1
0
1
1
1
0
1
0
1
0
0
0
1
1
1
0
0
1
1
1
1
0
1
1
1
1
1
1
1
0
1
0
0
1
1
0
0
1
1
0
0
1
1
1
1
1
1
0
0
1
1
1
0
0
1
1
0
0
1
0
1
0
1
0
1
0
0
0
0
0
0
0
0
1
1
1
1
1
0
0
0
1
0
0
1
0
1
1
...

result: