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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#576134 | #7900. Gifts from Knowledge | sw7777 | WA | 4ms | 35668kb | C++17 | 3.4kb | 2024-09-19 18:43:41 | 2024-09-19 18:43:41 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define i64 long long
#define inf 0x3f3f3f3f3f3f3f3f
#define pii pair<int, int>
#define endl '\n'
const int N=1e6+10;
const int N1=1e3+10;
const int mod=1e9+7;
const int element=3;
int f[N];
string ch[N];
i64 ksm(i64 x,i64 y){
i64 re=1;
while(y){
if(y&1) re=re*x%mod;
x=x*x%mod,y/=2;
}
return re;
}
void init(int n){
for(int i=1;i<=n;i++){
f[i]=i;
}
}
int find(int x){
if(x!=f[x]) return f[x]=find(f[x]);
return f[x];
}
void join(int x,int y){
int fx=find(x);
int fy=find(y);
if(fx!=fy) f[fy]=fx;
}
void Atomatic_AC_machine(){
int n,m;cin>>n>>m;
init(2*n);
for(int i=1;i<=n;i++){
cin>>ch[i];
ch[i]=" "+ch[i];
}
int cnt=0;
//遍历每一列
for(int i=1;i<=m/2;i++){
int l=0,r=0,mid=0;
int cnt=0;
for(int j=1;j<=n;j++){
// cout<<i<<" "<<m-i+1<<endl;
if(ch[j][i]=='1'&&ch[j][m-i+1]=='1'){
if(l||r){
cout<<0<<endl;
return;
}else{
// join(j,j+n);
l=r=i;
}
cnt+=2;
}else if(ch[j][i]=='1'){//左侧为1
if(l){
if(find(l)==find(j)){//要翻转,但是已经有了不反转的关系
cout<<0<<endl;
return;
}else{
join(l,j+n);
join(l+n,j);
}
}
if(r){
if(find(r+n)==find(j)){//不翻转,但是有了要反转的关系
cout<<0<<endl;
return;
}else{
join(r,j);
join(r+n,j+n);
}
}
l=j;
cnt++;
}else if(ch[j][m-i+1]=='1'){
if(r){
if(find(r)==find(j)){//要反转,但是有了不反转的关系
cout<<0<<endl;
return;
}else{
join(r,j+n);
join(r+n,j);
// cout<<l<<endl;
}
}
if(l){
if(find(l+n)==find(j)){//不翻转,但是有了要反转的关系
cout<<0<<endl;
return;
}else{
join(l,j);
join(l+n,j+n);
}
}
r=j;
cnt++;
}
if(cnt>2){
cout<<0<<endl;
return;
}
}
}
if(m%2){
for(int j=1;j<=n;j++){
if(ch[j][m/2+1]=='1') cnt++;
}
}
if(cnt>=2){
cout<<0<<endl;
return;
}
int ans=0;
for(int i=1;i<=n;i++){
if(find(i)==i) ans++;
}
for(int i=1;i<=2*n;i++){
cout<<find(i)<<" ";
}cout<<endl;
cout<<ksm(2,ans)<<endl;
}
signed main(){
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int t=1;
cin>>t;
while(t--){
Atomatic_AC_machine();
}
return 0;
}
Details
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Test #1:
score: 0
Wrong Answer
time: 4ms
memory: 35668kb
input:
3 3 5 01100 10001 00010 2 1 1 1 2 3 001 001
output:
1 2 1 4 5 4 4 0 1 3 3 1 2
result:
wrong answer 1st numbers differ - expected: '4', found: '1'