#include <bits/stdc++.h>
/* Orther */
#define int long long
#define YES cout<<"YES\n"
#define NO cout<<"NO\n"
#define IOS ios::sync_with_stdio(false);cin.tie(0); cout.tie(0)
using namespace std;
/* Pair */
#define x first
#define y second
/* Data type */
using ll = long long;
using ull = unsigned long long;
using PII = pair<int,int>;
using VI = vector<int>;
/* STL */
#define eb emplace_back
#define ef emplace_front
#define pb push_back
#define pf push_front
#define mp make_pair
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define all1(x) x.begin()+1,x.end()
/* Random */
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define random(a,b) rng()%(b-a+1)+a
/* Contest */
const int INF = 0x3f3f3f3f ; // 1e9
const int MOD = 998244353 ;
const int N = 100005, M = 55;
#define Bob cout<<"Bob\n"
#define Alice cout<<"Alice\n"
int a[N] , b[N] ;
std::mt19937_64 rng {std::chrono::steady_clock::now().time_since_epoch().count()};
void Rainbow_()
{
int n ; cin >> n;
for (int i = 1; i <= n; i ++ ) {
cin >> a[i];
}
for (int i = 1; i <= n; i ++ ) {
cin >> b[i];
}
bool ok = false ;
int cnt1 = 0 , cnt2 = 0;
for (int i = 1; i <= n ; i ++ ) {
if (a[i] % 2 && b[i] == 2) {
// Alice 拿不了 这个 1
ok = true;
}
// Alice 会在这里用一次(交换先后手)
if ( a[i] > 1 && b[i] == 1 ) {
cnt1 ++ ;
}
// Alice 必定交换先后手 , 否则必输
if ( a[i] % 2 == 0 && b[i] == 2 ) {
cnt2 ++ ;
}
}
// 特殊点大于 1
if (cnt1 + cnt2 > 1 || ok) {
Bob ;
} else if (cnt1 == 0 && cnt2 == 0) { // 没有限制就是NIM游戏
int sum = 0;
for (int i = 1; i <= n; i ++ ) {
sum ^= a[i];
}
if (sum == 0) {
Bob ;
} else {
Alice ;
}
} else if ( cnt1 == 0 && cnt2 == 1 ) {
int sum = 0;
for (int i = 1; i <= n; i ++ ) {
if ( b[i] != 2 ) {
sum ^= a[i];
}
}
if (sum == 0) {
Alice ;
} else {
Bob ;
}
} else if (cnt1 == 1 && cnt2 == 0) {
int num = 0;
for (int i = 1; i <= n; i ++ ) {
if ( b[i] == 1 && a[i] > 1 ) {
if ( a[i] % 2 == 0 ) {
num ^= 1;
}
} else {
num ^= a[i];
}
}
if ( num == 0 ) {
Alice ;
} else {
Bob ;
}
}
return ;
}
signed main()
{
IOS;
int _ = 1;
cin >> _;
while ( _ -- )
Rainbow_();
return 0;
}