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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#575884 | #7895. Graph Partitioning 2 | user10086 | TL | 0ms | 3600kb | C++17 | 966b | 2024-09-19 17:11:28 | 2024-09-19 17:11:28 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 25;
int n, k, vis[N];
vector<array<int, 2>> el;
vector<int> g[N];
int dfs(int x)
{
assert(0 < x && x < N);
if (vis[x]) return 0;
vis[x] = true;
int res = 1;
for (int y : g[x]) res += dfs(y);
return res;
}
void solve()
{
cin >> n >> k;
el.clear();
for (int i = 1, u, v; i <= n - 1; i++) cin >> u >> v, el.push_back({u, v});
int cnt = 0;
for (int i = 0; i < (1 << n - 1); i++)
{
for (int j = 1; j <= n; j++) vis[j] = false, g[j].clear();
for (int j = 0; j < n - 1; j++)
if (i & (1 << j)) g[el[j][0]].push_back(el[j][1]), g[el[j][1]].push_back(el[j][0]);
bool flag = true;
for (int j = 1; j <= n; j++)
{
if (vis[j]) continue;
int res = dfs(j);
if (res != k && res != k + 1)
{
flag = false;
break;
}
}
cnt += flag;
}
cout << cnt << '\n';
}
signed main()
{
int t; cin >> t;
while (t--) solve();
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3600kb
input:
2 8 2 1 2 3 1 4 6 3 5 2 4 8 5 5 7 4 3 1 2 1 3 2 4
output:
2 1
result:
ok 2 lines
Test #2:
score: -100
Time Limit Exceeded
input:
5550 13 4 10 3 9 1 10 8 3 11 8 5 10 7 9 6 13 5 9 7 2 7 5 12 4 8 8 2 4 1 3 4 7 8 2 5 6 7 4 8 2 3 11 1 11 10 1 4 9 10 8 4 3 6 5 7 6 1 10 2 11 7 11 1 17 2 14 16 13 15 17 3 15 11 1 6 13 2 13 17 4 8 14 10 8 14 14 5 9 12 14 2 12 17 17 6 15 7 14 6 2 14 2 13 2 4 8 4 3 11 7 3 14 1 11 9 13 3 5 10 6 8 3 10 14 ...
output:
0 3 112 0 1 0 1 0 0 0 1 0 1 0 0 1 0 140 0 0 0 814 1 6 1 1 2 2 0 612 0 1 0 0 0 1 1 0 0 121 4536 0 0 1718 0 0 1 0 444 1 1908 1813 3 74 0 1 0 46 0 0 0 0 0 0 0 0 0 1 0 1 1 1 239 0 0 0 1 0 0 0 1 0 1 0 0 1 1 0 0 0 1 0 0 0 48 0 2 0 0 0 1 364 0 206 0 0 76 0 1 0 0 2 0 1 2 0 0 1 0 0 4 0 1 1 0 0 1 1 1 0 0 1 1 ...