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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#575426#5710. Solar Flightzlt0 0ms0kbC++144.8kb2024-09-19 14:11:132024-09-19 14:11:14

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你现在查看的是最新测评结果

  • [2024-09-19 14:11:14]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-09-19 14:11:13]
  • 提交

answer

#include <bits/stdc++.h>
#define pb emplace_back
#define fst first
#define scd second
#define mkp make_pair
#define mems(a, x) memset((a), (x), sizeof(a))

using namespace std;
typedef long long ll;
typedef __int128 lll;
typedef double db;
typedef unsigned long long ull;
typedef long double ldb;
typedef pair<ll, ll> pii;

bool Mst;

namespace IO {
    char ibuf[1 << 20], *iS, *iT, obuf[1 << 20], *oS = obuf;
#define writesp(x) write(x), pc(' ')
#define writeln(x) write(x), pc('\n')
#define gh() (iS == iT ? iT = (iS = ibuf) + fread(ibuf, 1, 1 << 20, stdin), (iS == iT ? EOF : *iS++) : *iS++)
	template<typename T = int>
	inline T read () {
		char ch = gh();
		T x = 0;
		bool t = 0;
		while (ch < '0' || ch > '9') t |= ch == '-', ch = gh();
		while (ch >= '0' && ch <= '9') x = (x << 1) + (x << 3) + (ch ^ 48), ch = gh();
		return t ? ~(x - 1) : x;
	}
	inline void flush () {
		fwrite(obuf, 1, oS - obuf, stdout), oS = obuf;
	}
	inline void pc (char ch) {
		if (oS == obuf + (1 << 20)) flush(); 
		*oS++ = ch;
	}
	template<typename T>
	inline void write (T x) {
		static char stk[64], *tp = stk;
		if (x < 0) {
			x = ~(x - 1);
			pc('-');
		}
		do {
			*tp++ = x % 10;
			x /= 10;
		} while (x);
		while (tp != stk) {
			pc((*--tp) | 48);
		}
	}
}

using IO::read;
using IO::write;
using IO::pc;
using IO::flush;

const int maxn = 2020;

ll n, m, K, id[maxn], a[maxn], b[maxn], c[maxn], d[maxn], p[maxn], q[maxn], h[maxn];

struct frac {
	ll x, y;
	frac(ll a = 0, ll b = 1) {
		if (b < 0) {
			a = -a;
			b = -b;
		}
		x = a;
		y = b;
	}
};

struct node {
	frac x;
	ll y, z;
} g[maxn];

frac f[maxn][maxn];
bool e[maxn][maxn];
int len[maxn];

inline bool operator < (const frac &a, const frac &b) {
	return (lll)a.x * b.y < (lll)a.y * b.x;
}

inline bool operator <= (const frac &a, const frac &b) {
	return (lll)a.x * b.y <= (lll)a.y * b.x;
}

inline bool operator == (const frac &a, const frac &b) {
	return (lll)a.x * b.y == (lll)a.y * b.x;
}

struct SGT {
	ll a[8200];
	
	inline void pushup(int x) {
		a[x] = max(a[x << 1], a[x << 1 | 1]);
	}
	
	void build(int rt, int l, int r) {
		if (l == r) {
			a[rt] = h[l];
			return;
		}
		int mid = (l + r) >> 1;
		build(rt << 1, l, mid);
		build(rt << 1 | 1, mid + 1, r);
		pushup(rt);
	}
	
	void query(int rt, int l, int r, int ql, int qr, ll &x) {
		if (ql > qr) {
			return;
		}
		if (ql <= l && r <= qr) {
			x = max(x, a[rt]);
			return;
		}
		int mid = (l + r) >> 1;
		if (ql <= mid) {
			query(rt << 1, l, mid, ql, qr, x);
		}
		if (qr > mid) {
			query(rt << 1 | 1, mid + 1, r, ql, qr, x);
		}
	}
} T[maxn];

inline int find(frac a[maxn], bool b[maxn], int l, int r, ll x) {
	int pos = -1;
	while (l <= r) {
		int mid = (l + r) >> 1;
		if (((b[mid] && a[mid].x < x * a[mid].y) || (!b[mid] && a[mid].x <= x * a[mid].y))) {
			pos = mid;
			l = mid + 1;
		} else {
			r = mid - 1;
		}
	}
	assert(pos != -1);
	return pos;
}

void solve() {
	m = read();
	ll X = read();
	n = read();
	K = read();
	map<pii, ll> mp;
	map< pii, vector<int> > pm;
	for (int i = 1; i <= n; ++i) {
		a[i] = read();
		b[i] = read();
		c[i] = read();
		mp[mkp(a[i], b[i])] += c[i];
		pm[mkp(a[i], b[i])].pb(i);
	}
	n = 0;
	for (auto p : mp) {
		a[++n] = p.fst.fst;
		b[n] = p.fst.scd;
		c[n] = p.scd;
		for (int i : pm[mkp(a[n], b[n])]) {
			id[i] = n;
		}
	}
	for (int i = 1; i <= n; ++i) {
		p[i] = i;
	}
	sort(p + 1, p + n + 1, [&](const ll &x, const ll &y) {
		return b[x] - a[x] < b[y] - a[y] || (b[x] - a[x] == b[y] - a[y] && a[x] > a[y]);
	});
	ll s = 0;
	for (int i = 1; i <= n; ++i) {
		d[p[i]] = s;
		s += c[p[i]];
		q[p[i]] = i;
	}
	for (int i = 1; i <= n; ++i) {
		int tot = 0;
		for (int j = 1; j <= n; ++j) {
			if (i == j) {
				continue;
			}
			frac k1(b[i] - a[i], m), k2(b[j] - a[j], m);
			if (k1 == k2) {
				continue;
			}
			frac x((a[j] - a[i]) * m, k1.x - k2.x);
			g[++tot].x = x;
			g[tot].y = (q[i] < q[j] ? c[j] : -c[j]);
			g[tot].z = (q[i] < q[j]);
		}
		sort(g + 1, g + tot + 1, [&](const node &a, const node &b) {
			return (lll)a.x.x * b.x.y < (lll)b.x.x * a.x.y;
		});
		g[0].x = frac(-4e18, 1);
		ll s = d[i];
		h[0] = s;
		for (int j = 1; j <= tot; ++j) {
			assert(!(g[j - 1].x == g[j].x));
			s += g[j].y;
			h[j] = s;
		}
		T[i].build(1, 0, tot);
		len[i] = tot;
		for (int j = 0; j <= tot; ++j) {
			f[i][j] = g[j].x;
			e[i][j] = g[j].z;
		}
	}
	while (K--) {
		ll x = read();
		ll l = read();
		ll r = l + X;
		x = id[x];
		int L = find(f[x], e[x], 0, len[x], l), R = find(f[x], e[x], 0, len[x], r);
		ll ans = -1e18;
		T[x].query(1, 0, len[x], L, R, ans);
		writeln(ans);
	}
}

bool Med;

int main() {
	fprintf(stderr, "%.2lf MB\n", (&Mst - &Med) / 1048576.);
	int T = 1;
	// scanf("%d", &T);
	while (T--) {
		solve();
	}
	flush();
	return 0;
}

詳細信息

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

1000 200 200 1000
657 836 23
962 796 47
497 305 25
837 161 23
220 575 33
697 109 37
401 221 43
883 211 46
727 461 26
681 209 28
413 14 49
664 986 27
431 222 47
307 121 38
638 560 45
801 149 24
878 61 36
761 356 43
839 413 32
931 573 35
218 195 46
201 697 25
951 778 21
705 905 42
861 391 23
582 718 2...

output:


result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%