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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#574516#9319. Bull FarmEBeasonTL 147ms44444kbC++202.8kb2024-09-18 22:30:432024-09-18 22:30:44

Judging History

你现在查看的是最新测评结果

  • [2024-09-18 22:30:44]
  • 评测
  • 测评结果:TL
  • 用时:147ms
  • 内存:44444kb
  • [2024-09-18 22:30:43]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define rep(it, ff, ee) for (int it = (ff); it <= (ee); ++it)
#define per(it, ff, ee) for (int it = (ff); it >= (ee); --it)
#define SZ(_x_) ((int) _x_.size())
#define all(_x_) (_x_).begin(), (_x_).end()
#define int long long

using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;
using tiii = tuple<int, int, int>;
using vi = vector<int>;

const int MAXN = 2e3 + 10;
const int MaxN = 2e3 + 10;
const int INF = 1e9;

#define MUT
int N, L, Q;
int a[MAXN][MAXN], dis[MAXN][MAXN];
vector<pair<int, int>> G1[MaxN];
inline void Solve() {
	cin >> N >> L >> Q;
	int NN = N;
	vector<int> ans(Q + 1);
	for (int i = 1; i <= N; i++) {
		G1[i].clear();
	}
	for	(int i = 1; i <= N; i++) {
		for (int j = 1; j <= N; j++) {
			dis[i][j] = INF;
		}
	}
	for (int i = 1; i <= L; i++) {
		string s1;
		cin >> s1;
		for (int j = 0; j < 2 * N; j += 2) {
			a[i][j / 2 + 1] = (s1[j] - '0') * 50 + (s1[j + 1] - '0') % 50;
		}
	}
	

	for (int i = 1; i <= L; i++) {
		map<int, int> mp;
		for (int j = 1; j <= N; j++) {
			mp[a[i][j]]++;
		}
		if (mp.size() == N - 1) {
			int id = 0, maxn = 0;
			for (auto [x, y] : mp) {
				if (y == 2) {
					maxn = x;
				}
			}
			for (int j = 1; j <= N; j++) {
				if (mp[j] == 0) id = j;
			}
			for (int j = 1; j <= N; j++) {
				if (a[i][j] == maxn) {
					auto x = j, y = id;
					G1[x].emplace_back(y, i);
					// cerr << x << ' ';
					// cerr << y << endl;
				}
			}

		} else if (mp.size() == N) {
			for (int j = 1; j <= N; j++) {
				auto x = j, y = a[i][j];
				G1[x].emplace_back(y, i);
				G1[y].emplace_back(x, i);
				// cerr << x << ' ';
				// cerr << y << endl;
			}
		}
	}

	for (int s = 1; s <= N; s++) {
		priority_queue<pii, vector<pii>, greater<pii> > q;
		q.emplace(0, s);
		vector<int> vis(N + 1);
		dis[s][s] = 0;
		while (!q.empty()) {
			auto [d, x] = q.top(); q.pop();
			if (vis[x]) continue;
			vis[x] = 1;
			for (auto [y, w] : G1[x]) {
				if (max(dis[s][x], w) < dis[s][y]) {
					dis[s][y] = max(dis[s][x], w);
					q.emplace(dis[s][y], y);
				}
			}
		}
	}


	// for (int i = 1; i <= N; i++) {
	// 	for (int j = 1; j <= N; j++) {
	// 		cerr << dis[i][j] << ' ';
	// 	}
	// 	cerr << endl;
	// }

	for (int i = 1; i <= Q; i++) {
		string s1;
		cin >> s1;
		int res[3];
		for (int j = 0; j < 6; j += 2) {
			res[j / 2] = (s1[j] - '0') * 50 + (s1[j + 1] - '0') % 50;
		}
		int x = res[0];
		int y = res[1];
		int z = res[2];
		int ans = dis[x][y];
		// cerr << ans << endl;
		cout << (ans <= z);
		
	}
	cout << endl;

}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.tie(nullptr);
#ifdef MUT
	int T;
	cin >> T;
	while (T--)
#endif
		Solve();	
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5724kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 5680kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 57ms
memory: 5720kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 147ms
memory: 44444kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: