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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#573791#7070. IsomerismlazyxAC ✓22ms3568kbC++203.3kb2024-09-18 20:00:122024-09-18 20:00:12

Judging History

你现在查看的是最新测评结果

  • [2024-09-18 20:00:12]
  • 评测
  • 测评结果:AC
  • 用时:22ms
  • 内存:3568kb
  • [2024-09-18 20:00:12]
  • 提交

answer

#include<bits/stdc++.h>
#include<array>
#define all(v) v.begin(),v.end()
//#pragma GCC optimize(3)
//#define __builtin_popcount __popcnt
using ll = long long;
using ull = unsigned long long;
using db = double;
using namespace std;
template<typename A>
A gcd(A a, A b) {
    return b ? gcd(b, a % b) : a;
}
template<typename A>
A lcm(A a, A b) {
    return a * b / gcd(a, b);
}
template<typename A>
bool isprime(A a) {
    if (a == 1) {
        return 0;
    }
    for (ll i = 2; i * i <= a; i++) {
        if (a % i == 0) {
            return false;
        }
    }
    return true;
}
template<typename A>
A max(A a, A b, A c) {
    return max(a, max(b, c));
}
template<typename A>
A min(A a, A b, A c) {
    return min(a, min(b, c));
}
/*void que(int x, int y) {
    cout << "? " << x << ' ' << y << '\n';
}
void ans(int x, int y) {
    cout << "! " << x << ' ' << y << '\n';
}*/
const ll MOD = 998244353;
ll ksm(ll a, ll b, ll p) {
    a %= p;
    ll res = 1;
    while (b) {
        if (b & 1)res = res * a % p;
        a = a * a % p;
        b >>= 1;
    }
    return res;
}
vector<int>par;
int find(int x) {
    return par[x] == x ? x : (par[x] = find(par[x]));
}
void merge(int x, int y) {
    par[find(y)] = find(x);
}
/*
const int N = 1e7;
bool p[N + 5];
int pr[N + 5];
int sg[N + 10];
bool vis[N + 10];
int cnt = 0;
void Euler() {
    memset(p, true, sizeof(p));
    p[0] = p[1] = true;    //特例
    for (ll i = 2; i <= N; ++i) {
        if (p[i]) pr[cnt] = i, sg[i] = ++cnt;    //选出素数
        for (int j = 0; j < cnt && pr[j] * i <= N; ++j) {
            p[pr[j] * i] = false;    //筛出非素数
            if (i % pr[j] == 0) break;    //重复筛选,跳出循环
        }
    }
}
auto mul = [](ll a, ll b) {
    if (a == -1 || b == -1) return -1ll;
    if (1e18 / b < a) return -1ll;
    else return a * b;
};
const int N = 1e6;
ll fact[N + 10], in_fact[N + 10];
ll C(ll n, ll m) {
    if (n < m || m < 0)return 0;
    return fact[n] * in_fact[m] % MOD * in_fact[n - m] % MOD;
}
void init() {
    fact[0] = 1;
    in_fact[0] = 1;
    for (int i = 1; i <= N; i++) {
        fact[i] = fact[i - 1] * i % MOD;
        in_fact[i] = ksm(fact[i], MOD - 2, MOD);
    }
}
*/
int exgcd(ll a, ll b, ll& x, ll& y) {
    if (!b) {
        x = 1, y = 0;
        return a;
    }
    ll d = exgcd(b, a % b, y, x);
    y -= (a / b * x);
    return d;
}
template<typename A>
A lowbit(A x) {
    return x & (-x);
}
string ss[8] = { "-F","-Cl","-Br","-I","-CH3","-CH2CH3","-CH2CH2CH3","-H" };
void solve() {
    string s1, s2, s3, s4;
    cin >> s1 >> s2 >> s3 >> s4;
    if (s1 == s3 || s2 == s4)cout << "None\n";
    else if (s1 == s2 || s3 == s4) cout << "Cis\n";
    else if (s1 == s4 || s2 == s3)cout << "Trans\n";
    else {
        int id1 = 0;
        while (ss[id1] != s1)id1++;
        int id2 = 0;
        while (ss[id2] != s2)id2++;
        int id3 = 0;
        while (ss[id3] != s3)id3++;
        int id4 = 0;
        while (ss[id4] != s4)id4++;
        if ((id1 < id3 && id2 < id4)|| (id1 > id3 && id2 > id4))cout << "Zasamman\n";
        else cout << "Entgegen\n";
    }
}
int main() {
    ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    int t = 1;
    cin >> t;
    while (t--) {
        solve();
    }
    return 0;
}

这程序好像有点Bug,我给组数据试试?

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3568kb

input:

2
-H -H -H -Cl
-F -F -Br -Cl

output:

None
Cis

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 22ms
memory: 3520kb

input:

100000
-Br -CH3 -H -CH2CH2CH3
-CH3 -I -Cl -Cl
-CH3 -Br -CH2CH3 -CH3
-H -CH3 -Cl -CH3
-H -F -CH2CH3 -CH2CH2CH3
-Br -Br -Cl -CH2CH2CH3
-F -Cl -H -CH2CH2CH3
-CH2CH2CH3 -CH3 -CH3 -H
-CH2CH2CH3 -CH3 -CH2CH2CH3 -Br
-CH3 -Cl -CH2CH2CH3 -CH3
-H -CH2CH3 -I -I
-CH3 -Cl -Br -I
-I -Cl -H -F
-CH2CH2CH3 -Cl -Br -...

output:

Zasamman
Cis
Trans
None
Entgegen
Cis
Zasamman
Trans
None
Trans
Cis
Entgegen
Entgegen
Cis
Cis
Entgegen
Trans
None
Cis
None
Cis
None
None
Zasamman
Cis
None
Entgegen
Entgegen
None
None
Cis
Trans
Zasamman
Entgegen
Zasamman
Trans
Entgegen
None
Zasamman
Trans
Cis
Trans
Zasamman
Trans
None
Zasamman
None
Tr...

result:

ok 100000 lines