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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#572865 | #9319. Bull Farm | EricW | TL | 400ms | 18972kb | C++20 | 4.1kb | 2024-09-18 16:37:02 | 2024-09-18 16:37:06 |
Judging History
answer
// Program written by EricWu ~~~
#include <bits/stdc++.h>
#define lowbit(x) (x & -x)
using namespace std;
inline char gc(void) {
static char buf[100000], *p1 = buf, *p2 = buf;
return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 100000, stdin), p1 == p2) ? EOF : *p1++;
}
#define gc() getchar()
template <class T> inline void read(T &x) {
T f = 1; x = 0; static char c = gc();
for (; !isdigit(c); c = gc()) if (c == '-') f = -f;
for (; isdigit(c); c = gc()) x = x * 10 + (c & 15);
if (f == -1) x = -x;
}
inline void readstr(char *s) {
do *s = gc(); while ((*s == ' ') || (*s == '\n') || (*s == '\r'));
do *(++s) = gc(); while ((~*s) && (*s != ' ') && (*s != '\n') && (*s != '\r'));
*s = 0; return;
}
inline void readch(char&x) { while (isspace(x = gc())); }
char pf[100000], *o1 = pf, *o2 = pf + 100000;
#define ot(x) (o1 == o2 ? fwrite(pf, 1, 100000, stdout), *(o1 = pf) ++= x : *o1 ++= x)
template <class T>
inline void println(T x, char c = '\n') {
if (x < 0) ot(45), x = -x;
static char s[15], *b; b = s;
if (!x) *b ++= 48;
for (; x; * b ++= x % 10 + 48, x /= 10);
for (; b-- != s; ot(*b)); ot(c);
}
template <class T> inline void write(T x) {
if (x < 0) x = -x, putchar('-');
if (x > 9) write(x / 10);
putchar(x % 10 + 48);
}
template <class T> inline void writeln(T x, char c = '\n') { write(x); putchar(c); }
template <class T> inline void chkmax(T &x, const T y) { x > y ? x = x : x = y; }
template <class T> inline void chkmin(T &x, const T y) { x < y ? x = x : x = y; }
#define Ms(arr, opt) memset(arr, opt, sizeof(arr))
#define Mp(x, y) make_pair(x, y)
#define endl '\n'
typedef long long ll;
typedef pair <int, int> pii;
typedef array<int, 3> piii;
using i64 = long long;
const int inf = 1e9;
struct DSU {
std::vector<int> f, siz;
DSU() {}
DSU(int n) {
init(n);
}
void init(int n) {
f.resize(n);
std::iota(f.begin(), f.end(), 0);
siz.assign(n, 1);
}
int find(int x) {
while (x != f[x]) {
x = f[x] = f[f[x]];
}
return x;
}
bool same(int x, int y) {
return find(x) == find(y);
}
bool merge(int x, int y) {
x = find(x);
y = find(y);
if (x == y) {
return false;
}
siz[x] += siz[y];
f[y] = x;
return true;
}
int size(int x) {
return siz[find(x)];
}
};
void solve() {
int n, l, q; cin >> n >> l >> q;
auto f = [](char ch1, char ch2) -> int {
cin >> ch1 >> ch2;
return 50 * (ch1 - 48) + (ch2 - 48);
};
DSU ds(n + 1);
vector adj(n + 1, vector<pair<int, int>>());
for (int i = 1;i <= l;i++) {
ds.init(n + 1);
vector<int> a(n + 1); map<int, int> mp;
for (int j = 1;j <= n;j++) {
char ch1, ch2;
a[j] = f(ch1, ch2); mp[a[j]] ++;
}
if (mp.size() == n) {
for (int j = 1;j <= n;j++) {
if (ds.merge(j, a[j])) {
adj[j].emplace_back(a[j], i);
adj[a[j]].emplace_back(j, i);
}
}
}
else if (mp.size() == n - 1) {
int x1, x2;
for (int j = 1;j <= n;j++) {
if (!mp.contains(j)) x1 = j;
else if (mp[a[j]] > 1) x2 = j;
}
adj[x2].emplace_back(x1, i);
}
}
vector dis(n + 1, vector<int>(n + 1, inf));
for (int s = 1;s <= n;s++) {
priority_queue<tuple<int, int>, vector<tuple<int, int>>,greater<>> q;
dis[s][s] = 0;
q.emplace(0, s);
vector<bool> vis(n + 1, false);
while (q.size()) {
auto [val, u] = q.top(); q.pop();
if (vis[u]) continue;
vis[u] = true;
for (auto &[v, w] : adj[u]) {
int newval = max(val, w);
if (dis[s][v] > newval) {
dis[s][v] = newval;
q.emplace(newval, v);
}
}
}
}
for (int i = 1;i <= q;i++) {
char ch1, ch2;
int a = f(ch1, ch2), b = f(ch1, ch2), c = f(ch1, ch2);
if (dis[a][b] <= c) cout << 1;
else cout << 0;
}
cout << endl;
}
int main() {
ios::sync_with_stdio(false);
int T = 1; cin >> T;
while (T--) solve();
// system("pause");
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3584kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3580kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: 0
Accepted
time: 308ms
memory: 3688kb
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...
result:
ok 200 lines
Test #4:
score: 0
Accepted
time: 400ms
memory: 18972kb
input:
1 2000 1 1000000 M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...
output:
000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...
result:
ok single line: '000101000101100010001000000010...0101000101000000000010101001000'
Test #5:
score: -100
Time Limit Exceeded
input:
1 2000 2000 1000000 FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...