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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#572472#9319. Bull FarmAHU_DuckTL 82ms17896kbC++174.9kb2024-09-18 14:48:232024-09-18 14:48:29

Judging History

你现在查看的是最新测评结果

  • [2024-09-18 14:48:29]
  • 评测
  • 测评结果:TL
  • 用时:82ms
  • 内存:17896kb
  • [2024-09-18 14:48:23]
  • 提交

answer

#include<bits/stdc++.h>
#define ri int
#define N 2050
#define LL long long
using namespace std;

int T, n, l, q, p[N][N], cnt[N], bad[N];
char s[N * 2];
bool ans[1000050];

int trans(char a, char b) {
    a -= 48; b -= 48;
    return a * 50 + b;
}

struct query {
    int a, b, id;
};
vector<query> Q[N];

struct Graph {
    int dfn[N], low[N], bel[N], ins[N], ru[N], clock;
    bool vis[N];
    vector<int> to1[N], to2[N], vec;
    bitset<N> f[N];
    stack<int> s;

    void clear() {
        for (ri i = 1; i <= n; i++) to1[i].clear();
        for (ri i = 1; i <= n; i++) to2[i].clear();
        for (ri i = 1; i <= n; i++) ins[i] = 0;
        while (!s.empty()) s.pop();
        vec.clear();
    }

    void add_edge(int a, int b) {
        to1[a].push_back(b);
    }

    void tarjan(int x) {
        low[x] = dfn[x] = ++clock;
        s.push(x);
        ins[x] = 1;
        int i, l = to1[x].size(), t;
        for (i = 0; i < l; i++) {
            if (ins[to1[x][i]]) low[x] = min(low[x], dfn[to1[x][i]]);
            else {
                if (dfn[to1[x][i]] == 0) {
                    tarjan(to1[x][i]);
                    low[x] = min(low[x], low[to1[x][i]]);
                }
            }
        }
        if (dfn[x] == low[x]) {
            do {
                t = s.top();
                bel[t] = x;
                ins[t] = false;
                s.pop();
                if (t == x) break;
            } while (1);
        }
        return;
    }

    void dp(int x) {
        if (vis[x]) return;
        for (auto it = to2[x].begin(); it != to2[x].end(); it++) {
            int y = *it;
            dp(y);
            f[x] |= f[y];
        }
        vis[x] = 1;
    }

    void init() {
        clock = 0;
        for (ri i = 1; i <= n; i++) {
            dfn[i] = low[i] = 0;
            sort(to1[i].begin(), to1[i].end());
            to1[i].resize(unique(to1[i].begin(), to1[i].end()) - to1[i].begin());
        }
        for (ri i = 1; i <= n; i++) if (!dfn[i]) tarjan(i);
        for (ri i = 1; i <= n; i++) if (i == bel[i]) vec.push_back(i);
        for (auto it = vec.begin(); it != vec.end(); it++) f[*it] = 0, ru[*it] = 0, vis[*it] = 0;
        for (auto it = vec.begin(); it != vec.end(); it++) f[*it][*it] = 1;
        for (ri i = 1; i <= n; i++) {
            for (auto it = to1[i].begin(); it != to1[i].end(); ++it) if (bel[i] != bel[*it]) {
                to2[bel[i]].push_back(bel[*it]);
                ru[bel[*it]]++;
            }
        }
        for (auto it = vec.begin(); it != vec.end(); it++) {
            sort(to2[*it].begin(), to2[*it].end());
            to2[*it].resize(unique(to2[*it].begin(), to2[*it].end()) - to2[*it].begin());
        }
        for (auto it = vec.begin(); it != vec.end(); it++) if (!ru[*it]) dp(*it);
    }
} G;

int main() {
    scanf("%d", &T);
    while (T--) {
        scanf("%d%d%d", &n, &l, &q);
        for (ri i = 1; i <= l; i++) bad[i] = 0;
        for (ri i = 1; i <= q; i++) ans[i] = 0;
        for (ri i = 1; i <= n; i++) cnt[i] = 0;
        for (ri i = 1; i <= l; i++) {
            scanf("%s", s + 1);
            for (ri j = 1, cc = 0; j <= 2 * n; j += 2) {
                p[i][++cc] = trans(s[j], s[j + 1]);
            }
            for (ri j = 1; j <= n; j++) cnt[j] = 0;
            for (ri j = 1; j <= n; j++) cnt[p[i][j]]++;
            int cc = 0;
            for (ri j = 1; j <= n; j++) {
                if (cnt[j] > 2) bad[i] = 1;
                else if (cnt[j] == 2) cc++;
            }
            if (cc >= 2) bad[i] = 1;
            else if (cc == 1) {
                int x = -1, y = -1;
                for (ri j = 1; j <= n; j++) if (cnt[p[i][j]] == 2) {
                    if (x == -1) x = j; else y = j;
                }
                else {
                    p[i][j] = -1;
                }
                int wu;
                for (ri j = 1; j <= n; j++) if (cnt[j] == 0) wu = j;
                p[i][x] = wu; p[i][y] = wu;
            }
        }
        for (ri i = 0; i <= l; i++) Q[i].clear();
        for (ri i = 1; i <= q; i++) {
            scanf("%s", s + 1);
            int qa = trans(s[1], s[2]);
            int qb = trans(s[3], s[4]);
            int qc = trans(s[5], s[6]);
            Q[qc].push_back((query){qa, qb, i});
        }
        for (ri i = 0; i <= l; i++) if (Q[i].size()) {
            G.clear();
            for (ri j = 1; j <= i; j++) if (!bad[j]) {
                for (ri t = 1; t <= n; t++) if (t != p[j][t] && p[j][t] != -1) 
                    G.add_edge(t, p[j][t]);
            }
            G.init();
            for (auto it = Q[i].begin(); it != Q[i].end(); ++it) {
                ans[it->id] = G.f[G.bel[it->a]][G.bel[it->b]];
            }
        }
        for (ri i = 1; i <= q; i++) printf("%d", ans[i]);
        puts("");
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 4840kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 4552kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 82ms
memory: 6704kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 77ms
memory: 17896kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: