QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#572063 | #9319. Bull Farm | AHU_Duck | ML | 1ms | 6572kb | C++17 | 4.3kb | 2024-09-18 11:36:56 | 2024-09-18 11:36:56 |
Judging History
answer
#include<bits/stdc++.h>
#define ri int
#define N 2050
#define LL long long
using namespace std;
int T, n, l, q, p[N][N], cnt[N], bad[N];
char s[N * 2];
bool ans[1000050];
int trans(char a, char b) {
a -= 48; b -= 48;
return a * 50 + b;
}
struct query {
int a, b, id;
};
vector<query> Q[N];
struct Graph {
int dfn[N], low[N];
int bel[N], ins[N], ru[N], clock;
vector<int> to1[N], to2[N], vec;
bitset<N> f[N];
stack<int> s;
void first_init() {
for (ri i = 1; i <= n; i++) {
to2[i].clear();
ins[i] = ru[i] = dfn[i] = low[i] = 0;
}
vec.clear();
for (ri i = 1; i <= n; i++) vec.push_back(i);
for (ri i = 1; i <= n; i++) bel[i] = i;
}
void add_edge(int a, int b) {
if (bel[a] != bel[b]) to2[bel[a]].push_back(bel[b]);
}
void tarjan(int x) {
low[x] = dfn[x] = ++clock;
s.push(x);
ins[x] = 1;
int i, l = to1[x].size(), t;
for (i = 0; i < l; i++) {
if (ins[to1[x][i]]) low[x] = min(low[x], dfn[to1[x][i]]);
else {
if (dfn[to1[x][i]] == 0) {
tarjan(to1[x][i]);
low[x] = min(low[x], low[to1[x][i]]);
}
}
}
if (dfn[x] == low[x]) {
do {
t = s.top();
bel[t] = x;
ins[t] = false;
s.pop();
if (t == x) break;
} while (1);
}
return;
}
void dp(int x) {
for (auto it = to2[x].begin(); it != to2[x].end(); it++) {
int y = *it;
dp(y);
f[x] |= f[y];
}
}
void init() {
/*
for (ri i = 1; i <= n; i++) {
dfn[i] = low[i] = ins[i] = 0;
sort(to1[i].begin(), to1[i].end());
to1[i].resize(unique(to1[i].begin(), to1[i].end()) - to1[i].begin());
}*/
for (auto it = vec.begin(); it != vec.end(); it++) {
ins[*it] = dfn[*it] = low[*it] = 0;
sort(to2[*it].begin(), to2[*it].end());
to2[*it].resize(unique(to2[*it].begin(), to2[*it].end()) - to2[*it].begin());
to1[*it] = to2[*it];
to2[*it].resize(0);
}
clock = 0; while (!s.empty()) s.pop();
for (auto it = vec.begin(); it != vec.end(); it++) if (!dfn[*it]) tarjan(*it);
vector<int> vec2; vec2.clear();
for (auto it = vec.begin(); it != vec.end(); it++) if (*it == bel[*it]) vec2.push_back(*it);
swap(vec, vec2);
for (auto it = vec.begin(); it != vec.end(); it++) f[*it] = 0, ru[*it] = 0;
for (auto it = vec2.begin(); it != vec2.end(); it++) f[bel[*it]][*it] = 1;
for (auto it = vec2.begin(); it != vec2.end(); it++) {
for (auto it2 = to1[*it].begin(); it2 != to1[*it].end(); ++it2) if (bel[*it] != bel[*it2]) {
to2[bel[*it]].push_back(bel[*it2]);
ru[bel[*it2]]++;
}
}
for (auto it = vec.begin(); it != vec.end(); it++) {
sort(to2[*it].begin(), to2[*it].end());
to2[*it].resize(unique(to2[*it].begin(), to2[*it].end()) - to2[*it].begin());
}
for (auto it = vec.begin(); it != vec.end(); it++) if (!ru[*it]) dp(*it);
}
} G;
int main() {
scanf("%d", &T);
while (T--) {
scanf("%d%d%d", &n, &l, &q);
for (ri i = 1; i <= l; i++) bad[i] = 0;
for (ri i = 1; i <= q; i++) ans[i] = 0;
for (ri i = 1; i <= n; i++) cnt[i] = 0;
for (ri i = 1; i <= l; i++) {
scanf("%s", s + 1);
for (ri j = 1, cc = 0; j <= 2 * n; j += 2) {
p[i][++cc] = trans(s[j], s[j + 1]);
}
for (ri j = 1; j <= n; j++) cnt[j] = 0;
for (ri j = 1; j <= n; j++) cnt[p[i][j]]++;
int cc = 0;
for (ri j = 1; j <= n; j++) {
if (cnt[j] > 2) bad[i] = 1;
else if (cnt[j] == 2) cc++;
}
if (cc >= 2) bad[i] = 1;
else if (cc == 1) {
int x = -1, y = -1;
for (ri j = 1; j <= n; j++) if (cnt[p[i][j]] == 2) {
if (x == -1) x = j; else y = j;
}
else {
p[i][j] = -1;
}
int wu;
for (ri j = 1; j <= n; j++) if (cnt[j] == 0) wu = j;
p[i][x] = wu; p[i][y] = wu;
}
}
for (ri i = 0; i <= l; i++) Q[i].clear();
for (ri i = 1; i <= q; i++) {
scanf("%s", s + 1);
int qa = trans(s[1], s[2]);
int qb = trans(s[3], s[4]);
int qc = trans(s[5], s[6]);
Q[qc].push_back((query){qa, qb, i});
}
G.first_init();
for (ri i = 0; i <= l; i++) {
if (i && !bad[i]) {
for (ri t = 1; t <= n; t++) if (t != p[i][t] && p[i][t] != -1) G.add_edge(t, p[i][t]);
}
G.init();
for (auto it = Q[i].begin(); it != Q[i].end(); ++it) {
ans[it->id] = G.f[G.bel[it->a]][G.bel[it->b]];
}
}
for (ri i = 1; i <= q; i++) printf("%d", ans[i]);
puts("");
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 6572kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 6324kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: -100
Memory Limit Exceeded
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110000101101110011101111111100101001111110110011110010010001011010101111110011111101001111011101110001011110111010011101001101110101010111010011110110001110001100111111011011011011111111011101001010111100111111101011111011100100001001011010100111110111111110011111100101011001110011110011100101110...