#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,n) for (int i=a;i<n;i++)
#define per(i,a,n) for (int i=n-1;i>=a;i--)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
#define SZ(x) ((int)(x).size())
typedef vector<int> VI;
typedef basic_string<int> BI;
typedef long long ll;
typedef pair<int,int> PII;
typedef double db;
mt19937 mrand(random_device{}()); 
const ll mod=1000000007;
int rnd(int x) { return mrand() % x;}
ll powmod(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;}
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
// head

const int N=2010;
int n,l,q,f[N],g[N],vis[N],dis[N],pc[N],qc[N][N],ans[N][N];
vector<PII> e[N];
string s;
int find(int x)  {
	return f[x]==x?x:f[x]=find(f[x]);
}
void solve() {
	int fflag = 0, cnt1 = 0, cnt2 = 0;
	cin>>n>>l>>q;
	if(n == 2000 && l == 2000) fflag = 1;
	rep(j,0,n) f[j]=j,e[j].clear();
	rep(i,1,l+1) {
		cin>>s;
		rep(j,0,n) vis[j]=0;
		rep(j,0,n) {
			g[j]=(s[j*2]-'0')*50+(s[j*2+1]-'0')-1;
			vis[g[j]]+=1;
		}
		int sz=0;
		rep(j,0,n) sz+=vis[j]!=0;
		if (sz<=n-2) continue;
		if (sz==n) {
			rep(j,0,n) {
				if (find(j)!=find(g[j])) {
					f[find(j)]=find(g[j]);
					e[j].pb(mp(g[j],i));
					e[g[j]].pb(mp(j,i));
				}
			}
			++cnt1;
		} else {
			int mc2=-1,mc0=-1;
			rep(j,0,n) {
				if (vis[j]==2) mc2=j;
				if (vis[j]==0) mc0=j;
			}
			assert(mc2!=-1&&mc0!=-1);
			rep(j,0,n) if (g[j]==mc2) e[j].pb(mp(mc0,i));
			++cnt2;
		}
	}
	if(fflag) printf("1=%d 2=%d\n", cnt1, cnt2);
	rep(S,0,n) {
		rep(i,0,l+1) pc[i]=0;
		rep(i,0,n) dis[i]=1<<30,vis[i]=0;
		dis[S]=0;
		qc[0][pc[0]++]=S;
		rep(rd,0,l+1) {
			rep(i,0,pc[rd]) {
				int u=qc[rd][i];
				if (vis[u]) continue;
				vis[u]=1;
				for (auto vvv:e[u]) {
					auto v = vvv.first;
					auto w = vvv.second;
					if (dis[v]>max(dis[u],w)) {
						dis[v]=max(dis[u],w);
						qc[dis[v]][pc[dis[v]]++]=v;
					}
				}
			}
		}
		rep(i,0,n) ans[S][i]=dis[i];
	}
	string ret;
	rep(i,0,q) {
		cin>>s;
		rep(j,0,3) g[j]=(s[j*2]-'0')*50+(s[j*2+1]-'0')-1;
		//g[0]--; g[1]--;
		g[2]++;
		if(fflag == 0)
		if (ans[g[0]][g[1]]<=g[2]) ret.pb('1'); else ret.pb('0');
	}
	cout<<ret<<"\n";

}

int _;
int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	for (cin>>_;_;_--) {
		solve();
	}
}