QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#567340 | #9313. Make Max | guaguayu | WA | 633ms | 94616kb | Java11 | 3.3kb | 2024-09-16 11:15:09 | 2024-09-16 11:15:10 |
Judging History
answer
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Stack;
import java.util.StringTokenizer;
public class Main
{
static InputReader sc = new InputReader(System.in);
static PrintWriter out = new PrintWriter(System.out);
public static void main(String[] args)
{
int t = sc.nextInt();
while (t-- > 0)
{
int n = sc.nextInt();
int[] sz = new int[n + 2];
int c = 1;
for (int i = 1; i <= n; i++)
{
int x = sc.nextInt();
sz[i] = x;
}
Stack<Integer> st1 = new Stack<Integer>();
int[] right = new int[n + 2];
Stack<Integer> st2 = new Stack<Integer>();
int[] left = new int[n + 2];
sz[0] = Integer.MAX_VALUE;
sz[n + 1] = Integer.MAX_VALUE;
// (从左往右放入)当ai被放入单调递增栈时,如果有元素bi出栈,那么ai就是bi的右边第一个>=bi的数
for (int i = 0; i <= n + 1; i++)
{
// 单调递增 注意相等的也要叉出去
while (!st1.isEmpty() && sz[st1.peek()] <= sz[i])
{
right[st1.peek()] = i;
st1.pop();// 栈顶比当前大
}
st1.add(i);
}
// System.out.println("right[]=" + Arrays.toString(right));
// 反向求左边 同理
for (int i = n + 1; i >= 0; i--)
{
while (!st2.isEmpty() && sz[st2.peek()] <= sz[i])
{
left[st2.peek()] = i;
st2.pop();// 栈顶比当前大
}
st2.add(i);
}
// System.out.println("left[]=" + Arrays.toString(left));
long sum = 0;
for (int i = 1; i <= n; i++)
{
sum += right[i] - left[i] - 1 - 1;
}
System.out.println(sum);
}
out.flush();// 最后输出
}
static class InputReader
{
public BufferedReader reader;
public StringTokenizer tokenizer;
public InputReader(InputStream stream)
{
reader = new BufferedReader(new InputStreamReader(stream), 32768);
tokenizer = null;
}
public String next()
{
while (tokenizer == null || !tokenizer.hasMoreTokens())
{
try
{
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e)
{
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
boolean hasNext()
{
while (tokenizer == null || !tokenizer.hasMoreTokens())
{
try
{
tokenizer = new StringTokenizer(reader.readLine());
} catch (Exception e)
{
return false;
}
}
return true;
}
public String nextLine()
{
String str = null;
try
{
str = reader.readLine();
} catch (IOException e)
{
e.printStackTrace();
}
return str;
}
public int nextInt()
{
return Integer.parseInt(next());
}
public long nextLong()
{
return Long.parseLong(next());
}
public Double nextDouble()
{
return Double.parseDouble(next());
}
public BigInteger nextBigInteger()
{
return new BigInteger(next());
}
public BigDecimal nextBigDecimal()
{
return new BigDecimal(next());
}
}
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 58ms
memory: 51088kb
input:
4 2 1 2 2 2 2 7 1 1 1 2 2 2 2 3 1 2 3
output:
1 0 3 3
result:
ok 4 number(s): "1 0 3 3"
Test #2:
score: 0
Accepted
time: 633ms
memory: 94616kb
input:
2 198018 875421126 585870339 471894633 383529988 625397685 944061047 704695631 105113224 459022561 760848605 980735314 847376362 980571959 329939331 644635272 326439858 752879510 837384394 175179068 182094523 397239381 1199016 185143405 279638454 252374970 822030887 860312140 137248166 993229443 164...
output:
4084978 4130372
result:
ok 2 number(s): "4084978 4130372"
Test #3:
score: -100
Wrong Answer
time: 547ms
memory: 92516kb
input:
2 195768 3086 1582 7854 5577 5243 2734 8054 4805 5686 7065 5555 2410 6240 7589 2889 3745 8094 9147 9438 1252 5497 5786 6655 4437 3933 2579 5722 9512 3117 1742 5362 2068 1853 4069 9231 1126 3991 420 2571 5517 3063 7279 8085 6111 5503 5980 50 6003 244 9684 6343 6517 1598 5223 5520 982 3932 1093 1149 7...
output:
3358939 3247917
result:
wrong answer 1st numbers differ - expected: '3061429', found: '3358939'