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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#565924#9319. Bull FarmqdsdsyTL 1239ms28192kbC++143.0kb2024-09-15 22:38:232024-09-15 22:38:26

Judging History

你现在查看的是最新测评结果

  • [2024-09-15 22:38:26]
  • 评测
  • 测评结果:TL
  • 用时:1239ms
  • 内存:28192kb
  • [2024-09-15 22:38:23]
  • 提交

answer

#include<cstdio>
#include<queue>
#include<algorithm>
using namespace std;
#define MAXN 2010
#define MAXQ 1000010

int n,l,q;
int t[MAXN][MAXN];
struct node{
	int a,b,c,id;
	friend bool operator < (node a,node b){
		return a.c<b.c;	
	}
} op[MAXQ];
bool ans[MAXQ];

struct edge{
	int v,nxt;
} e1[MAXN*MAXN];
int head[MAXN],cnte=0;
void ad(int u,int v){
	e1[++cnte].v=v;
	e1[cnte].nxt=head[u];
	head[u]=cnte;
}

bool e[MAXN][MAXN];
int bel[MAXN],belp[MAXN],cnt=0;
bool vis[MAXN];
int typ[MAXN];
char s[MAXN*2];
queue <int> qu;
bool bfs(int s,int t){
	for(int i=1;i<=n;i++)
		vis[i]=false;
	queue <int> qu;
	while(!qu.empty()) qu.pop();
	qu.push(s);
	vis[s]=true;
	while(!qu.empty()){
		int u=qu.front();
		if(u==t) return true;
		qu.pop();
		for(int i=head[u];i;i=e1[i].nxt){
			int v=e1[i].v;
			if(v==t) return true;
			if(vis[v]) continue;
			vis[v]=true;
			qu.push(v);
		}
	}
	return false;
}

void solve(){
	scanf("%d%d%d",&n,&l,&q);
	for(int i=1;i<=n;i++)
		for(int j=1;j<=n;j++)
			e[i][j]=false;
	for(int i=1;i<=n;i++){
		e[i][i]=true;
		bel[i]=head[i]=0;
	}
	cnte=0;
	while(cnt) belp[cnt--]=0;
	for(int i=1;i<=l;i++){
		scanf("%s",s+1);
		for(int j=1;j<=n;j++)
			t[i][j]=(s[2*j-1]-'0')*50+(s[2*j]-'0');
	}
	for(int i=1;i<=q;i++){
		scanf("%s",s+1);
		op[i].a=(s[1]-'0')*50+(s[2]-'0');
		op[i].b=(s[3]-'0')*50+(s[4]-'0');
		op[i].c=(s[5]-'0')*50+(s[6]-'0'); 
		op[i].id=i;
		ans[i]=0;
	}
	sort(op+1,op+1+q);
	int now=0;
	for(int i=1;i<=q;i++){
		int a=op[i].a,b=op[i].b,c=op[i].c,id=op[i].id;
		while(now<c){
			now++;
			typ[now]=0;
			for(int j=1;j<=n;j++)
				vis[j]=false;
			for(int j=1;j<=n;j++){
				if(!vis[t[now][j]]) vis[t[now][j]]=true;
				else {
					if(!typ[now]) typ[now]=t[now][j]; 
					else typ[now]=-1;
				}
			}
			if(typ[now]==-1) continue;
			if(typ[now]){
				int id1=0,id2=0,id3=0;
				for(int j=1;j<=n;j++) vis[j]=false;
				for(int j=1;j<=n;j++){
					if(t[now][j]==typ[now])
						if(!id1) id1=j;
						else id2=j;
					vis[t[now][j]]=true; 
				}
				for(int j=1;j<=n;j++)
					if(!vis[j]) id3=j;
				if(!e[id1][id3]) ad(id1,id3);
				if(!e[id2][id3]) ad(id2,id3);
				e[id1][id3]=e[id2][id3]=true; 
			}else {
				for(int j=1;j<=n;j++)
					vis[j]=false;
				for(int j=1;j<=n;j++){
					if(!vis[j]){
						int nowj=j;
						if(!bel[j]){
							bel[j]=++cnt;
							belp[cnt]=j;
						}
						do{
							vis[nowj]=true;
							if(nowj!=j){
								if(bel[nowj]){
									int u=belp[bel[nowj]],v=j;
									if(!e[u][v]) ad(u,v);
									if(!e[v][u]) ad(v,u); 
									e[u][v]=e[v][u]=true;
								}else {
									bel[nowj]=bel[j];
									if(!e[nowj][j]) ad(nowj,j);
									if(!e[j][nowj]) ad(j,nowj);
									e[nowj][j]=e[j][nowj]=true;
								}
							}
							nowj=t[now][nowj];
						} while(nowj!=j);
					}
				}
			}
		}
		ans[id]=bfs(a,b);
	}
	for(int i=1;i<=q;i++)
		printf("%d",(int)ans[i]);
	printf("\n");
}

int main()
{
	int t;
	scanf("%d",&t);
	while(t--)
		solve();
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 10024kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 9956kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 152ms
memory: 14060kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 1239ms
memory: 28192kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: