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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#565626#9319. Bull FarmmitthuTL 101ms24568kbC++143.2kb2024-09-15 21:54:332024-09-15 21:54:33

Judging History

你现在查看的是最新测评结果

  • [2024-09-15 21:54:33]
  • 评测
  • 测评结果:TL
  • 用时:101ms
  • 内存:24568kb
  • [2024-09-15 21:54:33]
  • 提交

answer

#include<bits/stdc++.h>
const int maxn=1e5+5;
const int maxm=2e3+5;
const int maxq=1e6+5;
using namespace std;
int T,n,l,Q,t[maxm][maxm],in[maxm];
int fa[maxm],ans[maxq];
char s[maxn];
queue<int>q; 
vector<pair<int,int> >edge;
vector<int>to[maxm];
bitset<maxm>f[maxm];
int find(int x){
    return (fa[x]==x)?x:fa[x]=find(fa[x]);
}
void merge(int x,int y){
    x=find(x);y=find(y);
    if(x==y)return;
    fa[x]=y;
}
int work(){
    int res=0;
    for(int i=1;i<=n;i++)res+=(in[i]==1);
    if(res==n)return 1;
    if(res==n-2){
        int res1=0;
        for(int i=1;i<=n;i++)res1+=(in[i]==2);
        if(res1==1)return 2;
    }
    return 0;
}
void suo(int u, int v) {
    u = find(u), v = find(v);
    for (int i = 1; i <= n; i++) {
        int x = find(i);
        if (f[u][x] && f[x][v]) merge(u, v), merge(x, u);
    }
}
struct node{
    int a,b,c,num;
    bool operator<(const node &x)const{
        return c<x.c;
    }
}p[maxq];
void solve(){
    scanf("%d %d %d",&n,&l,&Q);
    for(int i=0;i<=n;i++)f[i].reset(),to[i].clear(),in[i]=0;
    edge.clear();
    for(int i=1;i<=l;i++){
        scanf("%s",s+1);
        for(int j=1,k=1;j<=n+n;j+=2,k++)
            t[i][k]=(s[j]-'0')*50+(s[j+1]-'0');
    }
    for(int i=1;i<=Q;i++){
        scanf("%s",s+1);
        p[i].num=i;
        p[i].a=(s[1]-'0')*50+(s[2]-'0');
        p[i].b=(s[3]-'0')*50+(s[4]-'0');
        p[i].c=(s[5]-'0')*50+(s[6]-'0'); 
    }
    for(int i=1;i<=n;i++)fa[i]=i;
    sort(p+1,p+Q+1);
    int pos=1;
    while(p[pos].c==0){
        if(p[pos].a!=p[pos].b)ans[p[pos].num]=0;
        else ans[p[pos].num]=1;
        pos++;
    }
    for(int i=1;i<=l;i++){
        for(int j=1;j<=n;j++)in[j]=0;
        for(int j=1;j<=n;j++)in[t[i][j]]++;
        int res=work();
        if(res==2){
            int x=0,y=0;
            for(int j=1;j<=n;j++)
                if(in[j]==0)y=j;
                else if(in[j]==2)x=j;
            for (int j=1;j<=n;j++)
                if(t[i][j]==x&&y!=j) {
                    edge.push_back({j,y});
                    suo(j,y);
                }
        }
        if(res==1)
            for(int j=1;j<=n;j++)suo(j, t[i][j]), merge(j, t[i][j]);
        for (int j = 1; j <= n; j++) to[j].clear(), f[j].reset(),in[j]=0;
        for (auto E : edge) {
            int u = E.first, v = E.second;
            u = find(u), v = find(v);
            if (u != v) to[u].push_back(v),in[v]++;
        }
        for (int j = 1; j <= n; j++) f[find(j)][find(j)]=1;
        for(int j=1;j<=n;j++)if(!in[j])q.push(j);
        while(!q.empty()){
            int x=q.front();q.pop();
            for (auto v : to[x]){
                f[v] |= f[x];
                in[v]--;
                if(!in[v])q.push(v);
            }
        }
        while (p[pos].c == i&&pos<=Q){
            int x=find(p[pos].a),y=find(p[pos].b);
            // cout<<p[pos].a<<" "<<p[pos].b<<" "<<x<<" "<<y<<" "<<f[y][x]<<endl;
            if(f[y][x])ans[p[pos].num]=1;
            else ans[p[pos].num]=0;
            pos++;
        }
    }
    for(int i=1;i<=Q;i++)printf("%d",ans[i]);puts("");
}
int main(){
//freopen("1.in","r",stdin);
//    freopen("1.out","w",stdout);
    scanf("%d",&T);
    for(;T;T--)solve();
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 7924kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 7940kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 101ms
memory: 8296kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 100ms
memory: 24568kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: