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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#565092 | #9310. Permutation Counting 4 | red_jiu | WA | 104ms | 7704kb | C++23 | 1004b | 2024-09-15 20:13:14 | 2024-09-15 20:13:14 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6+7;
int n;
int l[N],r[N];
vector<int> g[N];
int ru[N];
void solve()
{
cin>>n;
for(int i=1;i<=n;i++) cin>>l[i]>>r[i];
for(int i=1;i<=n + 1;i++) ru[i] = 0 , g[i].clear();
for(int i=1;i<=n;i++) {
g[l[i]].push_back(r[i] + 1);
ru[r[i] + 1] ++;
}
for(int i=1;i<=n;i++)
{
if(ru[l[i]]) continue;
queue<int> q;
vector<int> siz(n+2);
q.push(l[i]);
while(!q.empty())
{
int x = q.front(); q.pop();
siz[x] ++;
if(siz[x] >= 2)
{
cout<<0<<"\n";
return ;
}
for (auto y: g[x]) {
q.push(y);
}
}
}
cout<<1<<"\n";
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr); cout.tie(nullptr);
int T = 1;
cin>>T;
while(T--) solve();
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 7676kb
input:
4 5 1 2 1 5 1 2 1 2 2 2 5 1 1 2 4 2 3 5 5 3 4 5 3 5 1 2 3 4 3 5 3 3 5 1 5 1 4 4 5 5 5 1 2
output:
0 1 0 0
result:
ok 4 tokens
Test #2:
score: -100
Wrong Answer
time: 104ms
memory: 7704kb
input:
66725 14 7 7 4 6 7 8 8 13 2 13 6 13 6 10 14 14 1 10 9 11 7 9 3 8 4 12 5 12 12 2 6 3 6 7 11 2 5 1 1 6 12 8 12 2 3 7 9 7 8 1 10 1 4 10 4 8 4 4 6 10 9 10 2 3 2 7 1 3 3 4 2 2 3 10 20 3 12 10 14 19 20 19 20 1 9 7 9 13 16 17 17 16 18 2 11 5 19 6 17 11 17 3 6 3 11 7 20 8 17 3 18 10 15 9 20 16 5 10 2 10 2 1...
output:
1 1 0 0 1 0 1 1 0 1 1 0 0 0 0 0 1 0 1 0 0 1 0 0 1 1 0 1 0 0 0 1 1 0 1 1 1 1 1 0 1 0 1 1 1 1 1 1 1 1 0 1 1 1 0 1 0 1 0 1 0 1 1 0 1 1 1 0 1 1 1 0 0 0 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 0 0 1 1 0 0 1 1 0 0 1 1 1 1 1 1 0 0 1 1 1 0 1 1 1 0 0 1 0 1 0 1 0 1 1 0 0 1 0 1 0 0 1 1 1 1 1 0 0 0 1 0 0 1 0 1 1 ...
result:
wrong answer 25th words differ - expected: '0', found: '1'