QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#565042#9319. Bull FarmegretTL 123ms19616kbC++142.2kb2024-09-15 20:00:472024-09-15 20:00:48

Judging History

你现在查看的是最新测评结果

  • [2024-09-15 20:00:48]
  • 评测
  • 测评结果:TL
  • 用时:123ms
  • 内存:19616kb
  • [2024-09-15 20:00:47]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int inf = 0x3f3f3f3f;
const int maxn = 2000 + 10;
struct node{
	node() {
	}
	node(int y, int val) {
		this->y = y;
		this->val = val; 
	}
	int y, val;
};
vector<node> e[maxn];
int n, l, Q;
char s[maxn * 2];
int t[maxn];
int deg[maxn];
int getnum(char a, char b)
{
	return (a - 48) * 50 + b - 48; 
}
void check_p(int id)
{
	for (int i = 1; i <= n; i++)
		deg[i] = 0;
	for (int i = 1; i <= n; i++)
		deg[t[i]]++;
	int deg0 = -1, deg2 = -1;
	for (int i = 1; i <= n; i++)
	{
		if (deg[i] == 0)
		{
			if (deg0 != -1) return;
			deg0 = i;
		}
		if (deg[i] == 2)
		{
			if (deg2 != -1) return;
			deg2 = i;
		} 
		if (deg[i] > 2) return;
	}
	if (deg0 != -1 && deg2 != -1)
	{
		for (int i = 1; i <= n; i++)
			if (t[i] == deg2)
				e[i].push_back(node(deg0, id));
	}
	else
	{
		for (int i = 1; i <= n; i++)
			e[i].push_back(node(t[i], id));
	}
}
typedef pair<int, int> pii;
priority_queue<pii> q;
int dis[maxn][maxn];
bool vis[maxn];
void getdis(int st)
{
	for (int i = 1; i <= n; i++)
		dis[st][i] = inf, vis[i] = false;
	dis[st][st] = 0;
	while (!q.empty()) q.pop();
	q.push({0, st});
	while (!q.empty())
	{
		pii tmp = q.top();
		int x = tmp.second;
		q.pop();
		if (vis[x]) continue;
		vis[x] = true;
		for (auto edge : e[x])
		{
			int y = edge.y, val = edge.val;
			if (dis[st][y] > max(dis[st][x], val))
			{
				dis[st][y] = max(dis[st][x], val);
				q.push({-dis[st][y], y});
			}
		}
	}
} 
void getAllDis()
{
	for (int i = 1; i <= n; i++)
		getdis(i);
}
void sol()
{
	scanf("%d%d%d", &n, &l, &Q);
	for (int i = 1; i <= n; i++)
		e[i].clear();
	for (int i = 1; i <= l; i++)
	{
		scanf("%s", s);
		int len = strlen(s);
		for (int i = 0; i < len; i += 2)
			t[i / 2 + 1] = getnum(s[i], s[i + 1]); 
		check_p(i);
	}
	getAllDis();
	for (int i = 1; i <= Q; i++)
	{
		scanf("%s", s);
		int len = strlen(s);
		int a, b, c;
		a = getnum(s[0], s[1]);
		b = getnum(s[2], s[3]);
		c = getnum(s[4], s[5]);
		if (dis[a][b] <= c)
			printf("1");
		else
			printf("0");
	}
	printf("\n");
}
int main()
{
	int T;
	scanf("%d", &T);
	while (T--) sol();
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3936kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3860kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 59ms
memory: 3944kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 123ms
memory: 19616kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: