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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#563942 | #3853. Lines in a grid | Fortitude# | WA | 784ms | 163900kb | C++23 | 2.2kb | 2024-09-14 17:33:25 | 2024-09-14 17:33:25 |
Judging History
answer
#include <bits/stdc++.h>
#define pb push_back
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define f first
#define s second
using namespace std;
using ll = long long;
using pii = pair <int, int>;
const int mod = 1e6 + 3;
inline void add(int& x, int y){
x += y;
if(x >= mod) x -= mod;
}
const int N = 1e7;
int s[N + 1];
int ans[N + 1];
int lp[N + 1];
int phi[N + 1];
int ps[N + 1];
int duka[N + 1];
int solve(int n){
if(n == 1) return 0;
int res = n % mod;
int cnt = 1 + phi[n - 1] + phi[n - 1];
cnt %= mod;
add(res, 1ll * cnt * (n + n - 1) % mod);
int sub = duka[n - 1];
/* for(int i = 2; i < n; i++){
add(sub, ans[i]);
add(sub, 1ll * i * (mod + phi[i] - phi[i - 1]) % mod);
}*/
add(sub, sub);
add(sub, 2);
add(res, mod - sub);
/* for(int i = 1; i < n; i++){
for(int j = 1; j < n; j++){
if(__gcd(i, j) > 1) continue;
add(res, (mod + mod + mod - i - j) % mod);
}
}*/
add(res, res);
return res;
}
int get(int x){
return x * 1ll * (x + 1) / 2 % mod;
}
main() {
ios :: sync_with_stdio(false);
cin.tie(nullptr);
for(int i = 1; i <= N; i++)
phi[i] = i;
for(int i = 2; i <= N; i++)
if(phi[i] == i)
for(int j = i; j <= N; j += i)
phi[j] -= phi[j] / i;
phi[1] = 0;
for(int i = 2; i <= N; i++) phi[i] %= mod;
for(int i = 2; i <= N; i++){
if(lp[i]) continue;
for(ll j = i; j <= N; j += i) lp[j] = i;
}
// cerr << "OK\n";
ans[1] = 1;
for(int i = 2; i <= N; i++){
int res = 1, cnt = 0;
int x = i;
while(x > 1){
int p = lp[x], cur = 1;
cnt++;
while(x % p == 0){
x /= p;
cur *= p;
}
if(cur == i){
int sum = get(i);
add(sum, mod - 1ll * p * get(i / p) % mod);
// sum = (sum - p * 1ll * get(i / p) % mod + mod) % mod;
ans[i] = sum;
}else{
res = res * 1ll * ans[cur] % mod;
}
}
if(cnt > 1){
ans[i] = res * 1ll * (1 << (cnt - 1)) % mod;
}
}
for(int i = 2; i <= N; i++){
duka[i] = ans[i];
add(duka[i], 1ll * i * phi[i] % mod);
add(duka[i], duka[i - 1]);
}
for(int i = 1; i < N; i++) add(phi[i + 1], phi[i]);
int T = 1;
cin >> T;
for(int n; T--;){
cin >> n;
cout << solve(n) << '\n';
}
}
详细
Test #1:
score: 0
Wrong Answer
time: 784ms
memory: 163900kb
input:
10 1 2 3 4 5 6 7 8 9 10
output:
0 6 20 54 108 210 320 522 744 1050
result:
wrong answer 4th lines differ - expected: '62', found: '54'