QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#563772 | #5414. Stop, Yesterday Please No More | xinlengweishang | TL | 9ms | 35800kb | C++20 | 2.5kb | 2024-09-14 15:51:39 | 2024-09-14 15:51:41 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
map<char,int> gox,goy;
int mp[2020][2020],f[2020][2020];
void slove(){
for(int i=0;i<2020;i++) for(int q=0;q<2020;q++) mp[i][q]=0,f[i][q]=0;
char s[100010];
int n,m,k,ln,lm;
scanf("%d%d%d",&n,&m,&k);
scanf("%s",s);
ln=n;
lm=m;
int len=strlen(s);
int fx=1010,fy=1010,dx=1010,dy=1010;
int maxx=1010,minx=1010,miny=1010,maxy=1010;
mp[dy][dx]=1;
for(int i=0;i<len;i++){
char c=s[i];
fx+=gox[c],fy+=goy[c];
dx-=gox[c],dy-=goy[c];
maxx=max(fx,maxx);
minx=min(fx,minx);
maxy=max(fy,maxy);
miny=min(fy,miny);
if(dx>=0&&dx<=2010&&dy>=0&&dy<=2010)
mp[dy][dx]=1;
}
m-=(maxx-1010)+(1010-minx);
n-=(maxy-1010)+(1010-miny);
m=max(0,m);
n=max(0,n);
maxx=min(2010,maxx);
maxy=min(2010,maxy);
minx=max(10,minx);
miny=max(10,miny);
int ans=n*m-k;
// printf("%d\n",ans);
// printf("m=%d n=%d\n",m,n);
// printf("minx %d maxx %d miny %d maxy %d\n",minx,maxx,miny,maxy);
if(ans<0){
for(int i=2020-maxy;i<=2020-miny;i++){
for(int q=2020-maxx;q<=2020-minx;q++){
mp[i][q]=0;
}
}
printf("0\n");
return ;
}
if(ans==0){
for(int i=2020-maxy;i<=2020-miny;i++){
for(int q=2020-maxx;q<=2020-minx;q++){
mp[i][q]=0;
}
}
printf("%d\n",ln*lm);
return ;
}
/*
printf("%d %d %d %d\n",maxy-1010,miny-1010,maxx-1010,minx-1010);
for(int i=2020-maxy;i<=2020-miny;i++){
for(int q=2020-maxx;q<=2020-minx;q++){
printf("%d %d mp:%d\n",i-1010,q-1010,mp[i][q]);
}
}*/
for(int i=max(0,2020-maxy-2);i<=min(2010,2020-miny+n+2);i++){
f[i][max(0,2020-maxy-2)]=0;
}
for(int q=max(0,2020-maxy-2);q<=min(2010,2020-minx+m+2);q++){
f[max(0,2020-maxy-2)][q]=0;
}
for(int i=max(1,2020-maxy-1);i<=min(2010,2020-miny+n+2);i++){
for(int q=max(1,2020-maxy-1);q<=min(2010,2020-minx+m+2);q++){
f[i][q]=f[i-1][q]+f[i][q-1]-f[i-1][q-1];
if(mp[i][q]) f[i][q]++,mp[i][q]=0;
// printf(" %d %d %d\n",i-1010,q-1010,f[i][q]);
}
}
int tt=0;
for(int i=max(n,2020-maxy-1);i<=min(2010,2020-miny+n+2);i++){
for(int q=max(m,2020-maxx-1);q<=min(2010,2020-minx+m+2);q++){
// printf("%d %d %d\n",i-1010,q-1010,f[i][q]-f[i-n][q]-f[i][q-m]+f[i-n][q-m]);
if(f[i][q]-f[i-n][q]-f[i][q-m]+f[i-n][q-m]==ans) tt++;
}
}
printf("%d\n",tt);
return ;
}
int main(){
gox['U']=0,goy['U']=1;
gox['D']=0,goy['D']=-1;
gox['L']=-1,goy['L']=0;
gox['R']=1,goy['R']=0;
int T;
if(T>=20) T=20;
scanf("%d",&T);
while(T--) slove();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 9ms
memory: 35800kb
input:
3 4 5 3 ULDDRR 4 5 0 UUUUUUU 4 5 10 UUUUUUU
output:
2 20 0
result:
ok 3 number(s): "2 20 0"
Test #2:
score: -100
Time Limit Exceeded
input:
1060 19 12 0 UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL 11 1 0 UR 3 18 33 UDRLR 17 11 132 RLDRDLDRUU 6 10 13 UULUDDLRDLUUDLDD 1 15 0 D 6 20 50 D...