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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#563572#9224. Express Evictionarnold518#WA 1ms4552kbC++174.3kb2024-09-14 13:55:342024-09-14 13:55:35

Judging History

你现在查看的是最新测评结果

  • [2024-09-14 13:55:35]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:4552kb
  • [2024-09-14 13:55:34]
  • 提交

answer

#include <bits/stdc++.h>
#define ff first
#define ss second
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const int MAXN = 60;
const int INF = 1e9;

int N, M;
int A[MAXN+10][MAXN+10];

const int dy[]={0, -1, 0, 1};
const int dx[]={1, 0, -1, 0};

bool in(int y, int x) { return (0<=y && y<=N && 0<=x && x<=M); }

int f(int y, int x, int d)
{
    assert(in(y, x));
    if(d==0) return A[y][x+1]+A[y+1][x+1];
    if(d==1) return A[y][x]+A[y][x+1];
    if(d==2) return A[y][x]+A[y+1][x];
    if(d==3) return A[y+1][x]+A[y+1][x+1];
}
int f2(int y, int x)
{
    assert(in(y, x));
    return f(y, x, 0)+f(y, x, 2);
}

struct UF
{
    int par[MAXN*MAXN+10];
    void init()
    {
        for(int i=0; i<(N+1)*(M+1); i++) par[i]=i;
    }
    int g(int y, int x)
    {
        if(!in(y, x)) return -1;
        return y*(M+1)+x;
    }
    int Find(int x)
    {
        if(x==par[x]) return x;
        return par[x]=Find(par[x]);
    }
    void Union(int x, int y)
    {
        x=Find(x); y=Find(y);
        par[x]=y;
    }
    bool same(int x, int y)
    {
        x=Find(x); y=Find(y);
        return x==y;
    }
}uf;

struct Queue
{
    int y, x, d, w;
    bool operator < (const Queue &ot) const { return w>ot.w; }
};

vector<array<int, 4>> adj[MAXN+10][MAXN+10][4];
vector<int> V[2][2];
int dist[MAXN+10][MAXN+10][4];

int main() {
    cin.tie(0); ios_base::sync_with_stdio(0);

    V[0][0]={0, 3};
    V[0][1]={2, 3};
    V[1][0]={0, 1};
    V[1][1]={1, 2};

    cin >> N >> M;
    for(int i=1; i<=N; i++)
    {
        string S;
        cin >> S;
        for(int j=0; j<M; j++) A[i][j+1]=(S[j]=='#');
    }
    // for(int i=1; i<=N; i++) { for(int j=1; j<=M; j++) printf("%d ", A[i][j]); printf("\n"); }
    uf.init();
    for(int i=0; i<=N; i++) for(int j=0; j<=M; j++)
    {
        if(f2(i, j)) continue;
        for(int k=0; k<4; k++)
        {
            int ny=i+dy[k], nx=j+dx[k];
            if(!in(ny, nx)) continue;
            if(f2(ny, nx)) continue;
            uf.Union(uf.g(i, j), uf.g(ny, nx));
        }   
    }

    for(int i=0; i<=N; i++)
    {
        for(int j=0; j<=M; j++)
        {
            for(int d=0; d<4; d++)
            {
                for(int k=0; k<4; k++)
                {
                    int ny=i+dy[k], nx=j+dx[k];
                    if(!in(ny, nx)) continue;
                    adj[i][j][d].push_back({ny, nx, k, f(ny, nx, k)});
                    // printf("EDGE %d %d %d => %d %d %d with weight %d\n", i, j, d, ny, nx, k, f(ny, nx, k));
                }
            }
        }
    }
    
    for(int y=1; y<=N; y++)
    {
        for(int x=1; x<=M; x++)
        {
            if(!A[y][x]) continue;

            for(int i : {0, 1})
            {
                for(int j : {0, 1})
                {
                    int a=y-1+i, b=x-1+j;
                    int c=y-1+1-i, d=x-1+1-j;
                    
                    for(int p : {0, 1})
                    {
                        int dd1=V[i][j][p], dd2=V[i][j][1-p];
                        int a2=a-dy[dd2]*2, b2=b-dx[dd2]*2;
                        int c2=c+dy[dd1]*2, d2=d+dx[dd1]*2;
                        if(in(a2, b2) && in(c2, d2))
                        {
                            if(uf.same(uf.g(a2, b2), uf.g(c2, d2)))
                            {
                                adj[a][b][dd1].push_back({c, d, (dd1+2)%4, f2(c, d)-1});
                                // printf("EDGE %d %d %d => %d %d %d with weight %d\n", a, b, dd1, c, d, (dd1+2)%4, f2(c, d)-1);
                                // printf("%d %d %d %d\n", a2, b2, c2, d2);
                            }
                        }
                    }
                }
            }
        }
    }

    priority_queue<Queue> PQ;
    for(int i=0; i<=N; i++) for(int j=0; j<=M; j++) for(int k=0; k<4; k++) dist[i][j][k]=INF;
    PQ.push({0, 0, 2, 0}); dist[0][0][2]=0;
    PQ.push({0, 0, 1, 0}); dist[0][0][1]=0;

    while(!PQ.empty())
    {
        auto [y, x, d, w] = PQ.top(); PQ.pop();
        if(dist[y][x][d]!=w) continue;
        // printf("%d %d %d : %d\n", y, x, d, w);
        for(auto [ny, nx, nd, nw] : adj[y][x][d])
        {
            if(dist[ny][nx][nd]>w+nw)
            {
                dist[ny][nx][nd]=w+nw;
                PQ.push({ny, nx, nd, w+nw});
            }
        }
    }

    cout << min(dist[N][M][3], dist[N][M][0])+A[1][1] << "\n";
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 4056kb

input:

4 6
.##...
.#....
##....
....#.

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: 0
Accepted
time: 1ms
memory: 4276kb

input:

20 30
...###########################
#..###########################
...###########################
...###########################
.#############################
...###########################
...###########################
#..###########################
...###########################
..#...............

output:

11

result:

ok 1 number(s): "11"

Test #3:

score: -100
Wrong Answer
time: 1ms
memory: 4552kb

input:

35 35
....###########...#########........
##..#######################..#####.
....#######################..#####.
...#.....##################..#####.
.##......##################.....##.
.##..##..#############.....#....##.
.....##..#############......##..##.
....#....#############..##..##..##.
####.....

output:

21

result:

wrong answer 1st numbers differ - expected: '16', found: '21'