QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#562204 | #7693. Convex Hull Extension | sha7dow | WA | 0ms | 3524kb | C++14 | 6.0kb | 2024-09-13 15:43:42 | 2024-09-13 15:43:42 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
using ll = long long;
using db = double;
using ldb = long double;
#define _T template <class T>
#define _FT template<class T, class FT = typename common_type<T, double>::type>
#define _F(X, Y) using X = Y<T, FT>; using F##X = Y<FT>
_T constexpr T eps = 0;
template<> constexpr double eps<double> = 1e-9;
template<> constexpr long double eps<long double> = 1e-11;
_T int sign(T x) {
return (x > eps<T>) - (x < -eps<T>);
}
_T int cmp(T x, T y) {
return sign(x - y);
}
_FT struct Point {
_F(P, Point);
T x, y;
Point() = default;
Point(T x, T y) : x(x), y(y) {}
T det(const P& p) const { return x * p.y - y * p.x; }
P operator+(const P& p) const { return {x + p.x, y + p.y}; }
P operator-(const P& p) const { return {x - p.x, y - p.y}; }
P operator*(T d) const { return {x * d, y * d}; }
P operator-() const { return {-x, -y}; }
P rotateCc2() const { return {-y, x}; }
T abs2() const { return x * x + y * y; }
T distTo2(const P& p) const { return (*this - p).abs2(); }
FT abs() const { return sqrt(FT(abs2())); }
FT distTo(const P& p) const { return (*this - p).abs(); }
friend istream& operator>>(istream& is, P& p) {
return is >> p.x >> p.y;
}
friend ostream& operator<<(ostream& os, const P& p) {
return os << p.x << ' ' << p.y;
}
};
_FT struct Line {
_F(L, Line);
_F(P, Point);
P u, v;
Line() = default;
Line(P u, P v) : u(u), v(v) {}
T cross(const P& p) const { // uv.det(up)
return (v.x - u.x) * (p.y - u.y) - (p.x - u.x) * (v.y - u.y);
}
int toLeft(const P& p) const { return sign(cross(p)); }
FT distTo(const P& p) const {
return fabs((v - u).det(p - u) / u.distTo(v));
}
};
_T T floor(T x, T y) {
return x >= 0 ? x / y : (x + 1) / y - 1;
}
_T T ceil(T x, T y) {
return x <= 0 ? x / y : (x - 1) / y + 1;
}
_T T exgcd(T a, T b, T& x, T& y) {
if (b == 0) {
x = 1, y = 0;
return a;
}
ll d = exgcd(b, a % b, y, x);
y -= a / b * x;
return d;
}
_T T euclid(T a, T b, T c, T n)
{
if (n < 0) return -euclid(-a, b - a, c, -n);
T p = floor(a, c), q = floor(b, c);
if (p || q)
return n * (n - 1) / 2 * p + n * q +
euclid(a - p * c, b - q * c, c, n);
T m = a * n + b;
return m < c ? 0 : euclid(c, m % c, a, m / c);
}
_T T countLine(T A, T B, T C, T x1, T x2, T y1, T y2) {
if (x1 > x2 || y1 > y2) return 0;
C = -C;
assert(A || B);
if (A < 0) tie(x1, x2) = make_pair(-x2, -x1), A = -A;
if (B < 0) tie(y1, y2) = make_pair(-y2, -y1), B = -B;
T x, y;
T d = exgcd(A, B, x, y);
if (C % d != 0) {
return 0;
}
if (!A) return x2 - x1 + 1;
if (!B) return y2 - y1 + 1;
A /= d, B /= d, C /= d;
x = x * (C % B) % B;
y = (C - A * x) / B;
T l = max(ceil(x1 - x, B), ceil(y - y2, A));
T r = min(floor(x2 - x, B), floor(y - y1, A));
return max(T(0), r - l + 1);
}
_T T count(const vector<Line<T>>& l) {
T s = 0;
vector<T> a, b, c;
for (auto [u, v] : l)
{
a.emplace_back(v.y - u.y);
b.emplace_back(u.x - v.x);
c.emplace_back(u.x * -a.back() + u.y * -b.back());
}
for (int i = 0; i < l.size(); i++)
{
int u = i - 1 >= 0 ? i - 1 : l.size() - 1,
v = i + 1 < l.size() ? i + 1 : 0;
T ux = b[u] * c[i] - b[i] * c[u],
uy = c[u] * a[i] - c[i] * a[u],
un = a[u] * b[i] - a[i] * b[u],
vx = b[i] * c[v] - b[v] * c[i],
vy = c[i] * a[v] - c[v] * a[i],
vn = a[i] * b[v] - a[v] * b[i];
T x1, x2, y1, y2;
if (a[i] > 0) {
y1 = ceil(uy, un), y2 = floor(vy, vn);
} else {
y1 = ceil(vy, vn), y2 = floor(uy, un);
}
if (b[i] < 0) {
x1 = ceil(ux, un), x2 = floor(vx, vn);
s -= euclid(a[i], c[i] - 1, -b[i], x2 + 1) -
euclid(a[i], c[i] - 1, -b[i], x1);
} else {
x1 = ceil(vx, vn), x2 = floor(ux, un);
if (b[i] > 0) {
s += euclid(-a[i], -c[i], b[i], x2 + 1) -
euclid(-a[i], -c[i], b[i], x1);
}
}
s -= countLine(a[i], b[i], c[i], x1, x2, y1, y2);
if (ux % un == 0 && uy % un == 0) s++;
if (b[i] < 0 && b[u] < 0 && ux % un == 0)
s += ceil(uy, un) - 1;
if (b[i] > 0 && b[v] > 0 && vx % vn == 0)
s -= floor(vy, vn);
}
return s;
}
using P = Point<long long>;
using L = Line<long long>;
void solve() {
int n;
cin >> n;
vector<P> p(n);
for (int i = 0; i < n; i++) {
cin >> p[i];
}
long long ans = 0;
for (int i = 0; i < n; i++) {
P a = p[i % n], b = p[(i + 1) % n], c = p[(i + 2) % n], d = p[(i + 3) % n];
cout << i << endl;
if ((b - a).det(d - c) < 0) {
cout << "infinitely many" << endl;
return;
} else if ((b - a).det(d - c) == 0) {
if (cmp(L(a, b).distTo(c), 1.0) > 0) {
cout << "infinitely many" << endl;
return;
}
cout << "ok" << endl;
if (a.x == b.x || a.y == b.y) continue;
if (b.x == c.x) {
if (abs(a.x - b.x) == 1) continue;
}
if (b.y == c.y) {
if (abs(a.y - b.y) == 1) continue;
}
cout << "infinitely many" << endl;
return;
} else {
vector<L> l;
l.push_back({a, b});
l.push_back({c, d});
l.push_back({c, b});
ans += count(l);
}
}
cout << ans << endl;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int tc = 1;
// cin >> tc;
while (tc--) {
solve();
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3524kb
input:
5 0 2 -2 0 -1 -3 1 -3 2 1
output:
0 1 2 3 4 23
result:
wrong answer 1st lines differ - expected: '23', found: '0'