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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#558958#7679. Master of Both IVwdwWA 28ms58292kbC++202.8kb2024-09-11 19:28:382024-09-11 19:28:39

Judging History

你现在查看的是最新测评结果

  • [2024-09-11 19:28:39]
  • 评测
  • 测评结果:WA
  • 用时:28ms
  • 内存:58292kb
  • [2024-09-11 19:28:38]
  • 提交

answer

#include<bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef double db;
#define int long long
const int N = 2e5 + 10;
const double eps = 1e-10;
#define ull unsigned long long
#define endl '\n'
using i64 = int64_t;
const int mod =998244353;
int ans = 0;int ksm(int a, int b) {
    int ans = 1;
    while (b) {
        if (b % 2 == 1) {
            ans = ans * a % mod;
        }
        b /= 2;
        a = a * a % mod;
    }
    return ans;
}

namespace binom {
    int fac[N], ifac[N];
    int __ = [] {
        fac[0] = 1;
        for (int i = 1; i <= N - 5; i++) {
            fac[i] = fac[i - 1] * i % mod;
        }
        ifac[N - 5] = ksm(fac[N - 5], mod - 2);
        for (int i = N - 5; i; i--) {
            ifac[i - 1] = ifac[i] * i % mod;
        }
        return 0;
    }();

    inline int C(int n, int m) {
        if (n < m || m < 0) return 0;
        return fac[n] * ifac[m] % mod * ifac[n - m] % mod;
    }

    inline int A(int n, int m) {
        if ((n < m || m < 0)) return 0;
        return fac[n] * ifac[n - m] % mod;
    }
}
using namespace binom;
struct node {
    int h[32];
    int cnt=0;
    //线性基增加了return true
    bool in(int x) {
        for (int i = 31; i >= 0; i--) {
            if ((1ll << i) & x) {
                if (h[i] == 0) {
                    h[i] = x;
                    cnt++;
                    return true;
                } else {
                    x ^= h[i];
                }
            }
        }
        return false;
    }

    int ma(int x,int y) {
        for (int i = 31; i >= 0; i--) {
            if(ans>max(x^h[i],y^h[i])){
                ans=max(x^h[i],y^h[i]);
                x^=h[i];
                y^=h[i];
            }
        }
        return x;
    }
}t1[N];

void solve() {
    int n;
    cin >> n ;
    int ans=0;
    int p=0;
    for(int i=0;i<=n;i++){
        for(int j=31;j>=0;j--){
            t1[i].h[j]=0;
        }
        t1[i].cnt=0;
    }
    vector<int>a(n+5),num(n+5),siz(n+5);
    for(int i=1;i<=n;i++){
        cin>>a[i];
        num[a[i]]++;
        if(!t1[0].in(a[i])){
            p++;
        }
    }
    ans+=ksm(2,p)-1;
    ans%=mod;
    for(int i=1;i<=n;i++){
        for(int j=2;j*i<=n;j++){
            siz[i*j]+=num[i];
            t1[i*j].in(i);
        }
    }
    //cout<<ans<<" ";
    for(int i=1;i<=n;i++){
        if(num[i]==0)continue;
        int c1=ksm(2,num[i]-1),c2=ksm(2,siz[i]-t1[i].cnt);
        //cout<<siz[i]<<" "<<i<<'\n';
        ans+=c1*c2%mod;
        ans%=mod;
        //cout<<ans<<" ";
    }
    cout <<ans << '\n';
}

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    // cout<<fixed<<setprecision(2);
    int T = 1;
    cin>>T;
    while (T--) solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 9ms
memory: 58216kb

input:

2
3
1 2 3
5
3 3 5 1 1

output:

4
11

result:

ok 2 number(s): "4 11"

Test #2:

score: -100
Wrong Answer
time: 28ms
memory: 58292kb

input:

40000
5
4 2 5 5 5
5
5 5 5 5 4
5
1 4 4 4 2
5
2 5 2 4 1
5
3 2 4 5 3
5
1 5 5 3 4
5
5 5 5 4 3
5
4 3 3 5 1
5
4 5 5 2 1
5
2 5 4 2 5
5
3 4 3 4 3
5
5 3 5 1 3
5
5 1 2 4 4
5
4 2 5 1 5
5
5 4 2 5 4
5
5 2 5 2 4
5
1 4 5 4 5
5
4 2 3 2 3
5
1 4 1 3 5
5
1 1 2 1 5
5
5 2 5 1 3
5
3 1 2 5 3
5
5 5 1 1 5
5
2 2 2 1 3
5
3 1 ...

output:

9
16
9
9
8
8
9
8
8
8
13
8
8
8
8
8
12
8
10
15
8
8
17
13
8
11
8
8
8
13
15
9
8
8
8
8
11
9
10
13
14
9
13
9
8
8
8
13
11
8
9
11
8
8
10
14
9
8
8
8
8
15
11
8
17
8
13
8
8
8
12
9
9
11
8
13
9
8
15
8
8
9
8
8
8
15
8
11
13
8
9
11
8
17
11
13
19
13
13
15
8
8
8
8
8
9
13
14
17
9
8
13
9
10
9
9
11
9
8
11
8
9
9
13
13
11...

result:

wrong answer 10th numbers differ - expected: '9', found: '8'