QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#55662 | #4500. Loop | lqhsmash | AC ✓ | 186ms | 9504kb | C++ | 972b | 2022-10-14 22:07:58 | 2022-10-14 22:07:59 |
Judging History
answer
#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int N = 5e5 + 50;
int T = 1;
int stk[N], tp;
int n, a[N], b[N], k, cnt;
void solve () {
scanf ("%d%d", &n, &k);
cnt = 0, tp = 0;
for (int i = 1; i <= n; i ++)
scanf ("%d", &a[i]);
for (int i = 1; i <= n; i ++) {
while (tp && a[stk[tp]] < a[i] && k)
b[++ cnt] = a[stk[tp --]], k --;
stk[++ tp] = i;
}
sort (b + 1, b + cnt + 1);
vector<int> g;
for (int i = tp, j = 1; i >= 1; i --) {
for (; j <= cnt && a[stk[i]] >= b[j]; j ++)
g.push_back (b[j]);
g.push_back (a[stk[i]]);
}
for (int i = n - 1; i >= 0; i --)
printf("%d ", g[i]);
printf("\n");
}
int main () {
#ifdef LOCAL
freopen ("in.in", "r", stdin);
freopen ("out.out", "w", stdout);
#endif
scanf ("%d", &T);
while (T --) {
solve ();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 186ms
memory: 9504kb
input:
100 300000 300000 1 1 300000 153456 153456 1 153456 153456 300000 1 300000 1 300000 300000 300000 1 300000 300000 300000 1 300000 300000 300000 300000 300000 1 300000 153456 300000 1 153456 153456 1 300000 153456 300000 300000 1 300000 1 1 153456 153456 300000 153456 153456 153456 153456 1 300000 30...
output:
300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000 300000...
result:
ok 100 lines