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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#556485 | #7706. Rikka with Linker | ship2077# | TL | 0ms | 3740kb | C++23 | 866b | 2024-09-10 18:49:54 | 2024-09-10 18:49:54 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
int n,m,x[255],y[255];
bitset<18>res[18];
int read(){
int x=0;char ch=getchar();
while (!isdigit(ch)) ch=getchar();
while (isdigit(ch)) x=x*10+ch-48,ch=getchar();
return x;
}
void solve(){
n=read();m=read();
for (int i=0;i<m;i++)
x[i]=read()-1,y[i]=read()-1;
int ans=n;
for (int sta=0;sta<1<<n;sta++){
if (__builtin_popcount(sta)>=ans) continue;
for (int i=0;i<n;i++) res[i].reset();
for (int i=0;i<m;i++)
if (~sta>>x[i]&1)
res[x[i]].set(y[i]);
for (int k=0;k<n;k++)
for (int i=0;i<n;i++) if (res[i][k])
res[i]|=res[k];
bool flag=0;
for (int i=0;i<n;i++)
for (int j=i+1;j<n;j++)
if (res[i][j]&&res[j][i])
flag=1;
if (!flag) ans=__builtin_popcount(sta);
}
printf("%d\n",ans+n);
}
int main(){int T=read();while (T--) solve(); return 0;}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3740kb
input:
3 3 2 1 2 2 3 3 3 1 2 2 3 3 1 5 7 1 2 2 3 3 5 5 4 4 2 2 5 3 1
output:
3 4 6
result:
ok 3 number(s): "3 4 6"
Test #2:
score: -100
Time Limit Exceeded
input:
1000 18 93 1 6 1 13 2 1 2 8 3 6 4 8 5 4 5 6 5 9 5 10 5 11 5 12 5 13 5 18 6 2 6 4 6 16 7 1 7 2 7 3 7 9 7 10 7 13 7 15 8 6 8 9 9 5 9 8 9 10 9 13 9 14 10 1 10 3 10 4 10 5 10 6 10 8 10 11 10 13 11 1 11 2 11 3 11 4 11 6 11 7 11 9 11 12 11 14 11 15 12 1 12 2 12 4 12 6 12 10 12 13 12 14 12 16 12 17 12 18 1...