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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#554730 | #7748. Karshilov's Matching Problem II | 000226 | WA | 1ms | 7656kb | C++17 | 2.9kb | 2024-09-09 15:08:51 | 2024-09-09 15:08:52 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define lep(i, l, r) for(int i = (l); i <= (r); i ++)
#define rep(i, l, r) for(int i = (l); i >= (r); i --)
#define debug(...) fprintf(stderr, __VA_ARGS__)
using i64 = long long;
const int N = 1.5 * 1e5 + 5;
const int M = N << 1;
int n, m;
char s[N], t[N];
int w[N], p[N];
char S[M];
int z[M], border[N];
i64 sum[N], Tsum[N], sum_2[N];
#define ls(x) (x << 1)
#define rs(x) (x << 1 | 1)
int mx[N << 2];
void upd (int x) {
mx[x] = max (mx[ls(x)], mx[rs(x)]);
}
void build (int x, int l, int r, int *val) {
if (l == r) {
mx[x] = val[l];
return;
}
int mid = (l + r) >> 1;
build (ls(x), l, mid, val);
build (rs(x), mid + 1, r, val);
upd (x);
}
int bq(int x, int l, int r, int v) {
if (mx[x] < v) return 0;
if (l == r) return l;
int mid = (l + r) >> 1;
if (mx[ls(x)] >= v) return bq(ls(x), l, mid, v);
else return bq(rs(x), mid + 1, r, v);
}
int query(int x, int l, int r, int L, int R, int v) {
if (mx[x] < v) return 0;
if (L <= l && r <= R) return bq(x, l, r, v);
int mid = (l + r) >> 1;
if (L <= mid) {
int res = query(ls(x), l, mid, L, R, v);
if (res) return res;
}
else return query(rs(x), mid + 1, r, L, R, v);
}
int main() {
ios :: sync_with_stdio(0);
cin.tie(0); cout.tie(0);
cin >> n >> m;
cin >> (s + 1);
cin >> (t + 1);
lep (i, 1, n) cin >> w[i], sum[i] += w[i], sum[i] += sum[i - 1];
//lep (i, 1, n) sum_2[i] = sum_2[i - 1] + sum[i];
lep (i, 1, n) S[i] = s[i];
S[n + 1] = '#';
lep (i, 1, n) S[i + 1 + n] = t[i];
z[1] = n;
int l = 0, r = 0;
for (int i = 2; i <= n + n + 1; i ++) {
if (i <= r) z[i] = min (z[i - l + 1], r - i + 1);
else z[i] = 0;
while (S[z[i] + 1] == S[i + z[i]]) z[i] ++;
if (i + z[i] - 1 > r) r = i + z[i] - 1, l = i;
}
lep (i, 1, n) p[i] = z[i + 1 + n];
for (int i = 2, j = 0; i <= n; i ++) {
while (j && s[j + 1] != s[i]) j = border[j];
if (s[j + 1] == s[i]) ++ j;
border[i] = j;
}
for (int i = 1; i <= n; i ++)
sum_2[i] = sum_2[border[i]] + w[i];
lep (i, 1, n) sum_2[i] += sum_2[i - 1];
lep (i, 1, n) {
Tsum[i] = Tsum[i - 1] + sum[p[i]];
}
static int val[N];
lep (i, 1, n) val[i] = p[i] + i - 1;
build (1, 1, n, val);
//lep (i, 1, n) cerr << p[i] << ' ' ;cerr << endl;
// qry i in [L, R], s[min(r - i + 1), p[i]]
/*
p[i] <= r - i + 1
p[i] + i - 1 <= r
find left i for p[i] + i - 1 >= r
for [i, r] 是S的一个前缀
for [l, i - 1] p[i] + i - 1 < r
区间求和 sum[p[i]]
*/
while (m --) {
int l, r;
cin >> l >> r;
i64 ans = 0;
int pos = query(1, 1, n, l, r, r);
//cerr << pos << endl;
if (! pos) {
ans = Tsum[r] - Tsum[l - 1];
}
else {
ans = Tsum[pos - 1] - Tsum[l - 1];
ans += sum_2[r - pos + 1];
}
//lep (i, l, r) ans += sum[min(p[i], r - i + 1)];
cout << ans << '\n';
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 5716kb
input:
8 5 abbabaab aababbab 1 2 4 8 16 32 64 128 1 1 2 3 3 5 4 7 1 8
output:
1 3 3 16 38
result:
ok 5 lines
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 7656kb
input:
15 4 heheheheehhejie heheheheheheheh 3 1 4 1 5 9 2 6 5 3 5 8 9 7 9 2 3 4 8 2 6 1 15
output:
31 62 62 174
result:
wrong answer 1st lines differ - expected: '3', found: '31'