QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#554146#9255. Python ProgramMiniLongAC ✓10ms3692kbC++174.3kb2024-09-09 07:51:222024-09-09 07:51:22

Judging History

你现在查看的是最新测评结果

  • [2024-09-09 07:51:22]
  • 评测
  • 测评结果:AC
  • 用时:10ms
  • 内存:3692kb
  • [2024-09-09 07:51:22]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    char ibuf[50007],*p1 = ibuf, *p2 = ibuf;
    #ifdef ONLINE_JUDGE
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 50007, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
string s, ch;
ll solve(int i){
    int d = 0, e = 0, f = 1, x = 0;
    int pos = 19;
    if(s[pos] == ch[4]) d = i, pos += 2;
    else{
        int cur = 0;
        _rep(j, pos, s.size() - 1){
            if(s[j] == ',') break;
            x = x * 10 + s[j] - '0', cur = j;
        }
        d = x, pos = cur + 2;
    }
    if(s[pos] == ch[4]) e = i, pos += 2;
    else{
        int cur = 0; x = 0;
        _rep(j, pos, s.size() - 1){
            if(s[j] == ',' || s[j] == ')') break;
            x = x * 10 + s[j] - '0', cur = j;
        }
        e = x, pos = cur + 2;
    }
    if(s[pos] == ':') f = 1;
    else{
        if(s[pos] == ch[4]) f = i;
        else{
            int cur = 0, op = 1; x = 0;
            _rep(j, pos, s.size() - 1){
                if(s[j] == ')') break;
                if(s[j] == '-') op = -op;
                else x = x * 10 + s[j] - '0', cur = j;
            }
            f = x * op;
        }
    }
    // debug("i:%d d:%d e:%d f:%d\n", i, d, e, f);
    ll sum = 0;
    if(f > 0){
        if(e > d){
            ll k = (e - d - 1) / f;
            sum = d * (k + 1) + (1 + k) * k / 2 * f;
        }
    }else{
        if(e < d){
            ll k = (d - (e + 1)) / (-f);
            sum = d * (k + 1) + (1 + k) * k / 2 * f;
        }
    }
    return sum;
}
int main(){
    getline(cin, s);
    getline(cin, s);
    int x = 0, a = 0, b = 0, c = 1, cnt = 0;
    int op = 1;
    int pos = 15;
    _rep(i, pos, s.size() - 1){
        if(s[i] == '-'){op = -1; continue;}
        if(!(s[i] >= '0' && s[i] <= '9')){
            if(!cnt) a = x * op;
            if(cnt == 1) b = x * op;
            if(cnt == 2 && x) c = x * op;
            cnt++, x = 0, op = 1;
        }else x = x * 10 + s[i] - '0';
    }
    ch = s;
    getline(cin, s);
    ll ans = 0;
    if(c > 0){
        for(int i = a; i < b; i += c){
            ans += solve(i);
        }
    }else{
        for(int i = a; i > b; i += c){
            ans += solve(i);
        }
    }
    writeln(ans);
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3648kb

input:

ans=0
for a in range(1,3):
    for b in range(5,1,-2):
        ans+=b
print(ans)

output:

16

result:

ok single line: '16'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3692kb

input:

ans=0
for q in range(100,50,-1):
    for i in range(q,77,20):
        ans+=i
print(ans)

output:

2092

result:

ok single line: '2092'

Test #3:

score: 0
Accepted
time: 7ms
memory: 3636kb

input:

ans=0
for i in range(1,1000000):
    for j in range(i,1,-1):
        ans+=j
print(ans)

output:

166666666665500001

result:

ok single line: '166666666665500001'

Test #4:

score: 0
Accepted
time: 2ms
memory: 3656kb

input:

ans=0
for i in range(31,321983,2):
    for j in range(313,382193):
        ans+=j
print(ans)

output:

11756963404587200

result:

ok single line: '11756963404587200'

Test #5:

score: 0
Accepted
time: 10ms
memory: 3636kb

input:

ans=0
for i in range(1,1000000):
    for j in range(i,114514,-1):
        ans+=j
print(ans)

output:

160610445975856765

result:

ok single line: '160610445975856765'

Extra Test:

score: 0
Extra Test Passed