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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#549127#8179. 2D ParenthesesHuTaoWA 228ms23520kbC++142.5kb2024-09-06 09:49:542024-09-06 09:49:54

Judging History

你现在查看的是最新测评结果

  • [2024-09-06 09:49:54]
  • 评测
  • 测评结果:WA
  • 用时:228ms
  • 内存:23520kb
  • [2024-09-06 09:49:54]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int N = 4e5 + 5;

int n, m, k;
struct Point
{
    int x, y, c, id;
    inline bool operator <(const Point &w) const
    {
        return x == w.x ? y < w.y : x < w.x;
    }
}p[N];
set<pair<int, int> > s;
int res[N];
struct Segment
{
    int x, l, r;
    bool operator <(const Segment &w) const
    {
        return x < w.x;
    }
}sg[N];
struct Query
{
    int x, y, d;
    bool operator <(const Query &w) const
    {
        return x < w.x;
    }
}q[N];
int xx[N], ss;
int c[N];
long long ans;

inline void Add(int i, int d)
{
    for(; i <= ss; i += i & -i) c[i] += d;
}
inline int Sum(int i)
{
    int s = 0;
    for(; i; i &= i - 1) s += c[i];
    return s;
}

int main()
{
    scanf("%d", &n);
    for(int i = 0 + 1; i <= n * 1; i ++ ) scanf("%d%d", &p[i].x, &p[i].y), p[i].c = 0, p[i].id = i;
    for(int i = n + 1; i <= n * 2; i ++ ) scanf("%d%d", &p[i].x, &p[i].y), p[i].c = 1, p[i].id = i;
    sort(p + 1, p + n * 2 + 1);
    for(int i = n * 2; i >= 1; i -- )
        if(p[i].c == 1)
        {
            // printf("*%d %d\n", p[i].x, p[i].y);
            s.insert({p[i].y, i});
        }
        else
        {
            // printf("#%d %d\n", p[i].x, p[i].y);
            set<pair<int, int> >::iterator it = s.lower_bound({p[i].y, 0});
            if(it == s.end())
            {
                puts("No");
                return 0;
            }
            int j = it->second;
            res[p[i].id] = p[j].id - n;
            sg[ ++ m] = {p[j].x, p[i].y - 1, p[j].y};
            q[ ++ k] = {p[i].x, p[j].y, -1};
            q[ ++ k] = {p[j].x - 1, p[j].y, 1};
            xx[ ++ ss] = p[i].y, xx[ ++ ss] = p[j].y;
            s.erase(it);
        }
    
    sort(sg + 1, sg + m + 1);
    sort(q + 1, q + k + 1);
    sort(xx + 1, xx + ss + 1);
    ss = unique(xx + 1, xx + ss + 1) - xx - 1;
    for(int i = 1, j = 1; i <= k; i ++ )
    {
        while(j <= m && sg[j].x <= q[i].x)
        {
            sg[j].l = lower_bound(xx + 1, xx + ss + 1, sg[j].l) - xx;
            sg[j].r = lower_bound(xx + 1, xx + ss + 1, sg[j].r) - xx;
            Add(sg[j].l, 1), Add(sg[j].r, -1);
            j ++ ;
        }
        q[i].y = lower_bound(xx + 1, xx + ss + 1, q[i].y) - xx;
        ans += q[i].d * Sum(q[i].y);
    }

    if(ans && n <= 2) puts("No");
    else
    {
        puts("Yes");
        for(int i = 1; i <= n; i ++ ) printf("%d\n", res[i]);
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 12120kb

input:

3
0 0
2 -2
1 1
2 2
3 1
2 3

output:

Yes
3
2
1

result:

ok answer is YES, 3 tokens

Test #2:

score: 0
Accepted
time: 0ms
memory: 11992kb

input:

2
1 0
0 1
2 3
3 2

output:

No

result:

ok answer is NO

Test #3:

score: 0
Accepted
time: 0ms
memory: 5884kb

input:

1
1 1
0 0

output:

No

result:

ok answer is NO

Test #4:

score: -100
Wrong Answer
time: 228ms
memory: 23520kb

input:

199996
94702923 895749121
-830347683 823853414
-638337012 -528381915
774504965 -903560893
465975432 931026841
47062323 901390864
539345338 830099354
278774201 896803047
-445303873 568413124
80473317 828648317
804283391 -307873779
543648687 893783688
814084625 -664894626
169476937 -999435847
-8232728...

output:

Yes
82079
143937
85506
159482
29196
103293
188581
65913
156903
48765
41010
76203
137133
196363
193426
109982
116023
34701
44848
99488
40423
194556
59175
165032
44597
44935
5843
122285
62483
155862
76890
97333
46778
56089
167272
163892
142018
158865
116989
191396
183211
91317
199137
56352
10550
16401...

result:

wrong answer 1st words differ - expected: '21701', found: '82079'