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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#547245#9104. Zayin and Forestwzxtsl#RE 0ms0kbC++171.0kb2024-09-04 19:36:342024-09-04 19:36:35

Judging History

你现在查看的是最新测评结果

  • [2024-09-04 19:36:35]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-09-04 19:36:34]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int N=1e6+7;
#define lowbit(x) (x&(-x))
int a[500005];
int d[N]={0};//d[i]的值,d[i]表示第i和i-1个数的差值
int c[N];
int n,m;
//区间修改
int update(int pos,int k){//pos表示修改点的位置,K表示修改的值也即+K操作
    int cnt=1;
    for(int i=pos;i<=n;i+=lowbit(i)){
        c[i]+=cnt*k;
        cnt++;
    }
    return 0;
}
//单点查询
int ask_qujian(int pos){//返回区间pos到1的总和,由于是使用差分数组维护因此使用前缀和
    int ans=0;
    for(int i=pos;i;i-=lowbit(i)){
        ans+=c[i];
    }
    return ans;
}
signed main(){
    cin>>n>>m;
    a[0]=0;
    for(int i=1;i<=n;i++){
        a[i]=0;
        d[i]=a[i]-a[i-1];
        update(i,d[i]);
    }
    while(m--){
        int a;
        int x,y;
        cin>>a;
        if(a==1){
            cin>>x>>y;
            update(x,y);
        }else{
            cin>>x>>y;
            cout<<ask_qujian(y)-ask_qujian(x-1)<<endl;
        }
    }
}

Details

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Test #1:

score: 0
Runtime Error

input:

1000000000 20000
2 384578735 526547442
1 64211261 592970906
1 512065247 448267721
1 44993150 127180320
1 880319036 927623947
1 170536687 572121854
1 896600029 804033011
1 666246328 754201635
1 654066651 179982083
2 240989825 984888006
2 372004567 858916479
2 76127818 98606736
1 181794163 902842353
1...

output:


result: