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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#546296 | #7523. Partially Free Meal | Liangsheng298 | TL | 0ms | 11876kb | C++14 | 2.5kb | 2024-09-03 22:28:35 | 2024-09-03 22:28:36 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline T read(){
T x=0;char ch=getchar();bool fl=false;
while(!isdigit(ch)){if(ch=='-')fl=true;ch=getchar();}
while(isdigit(ch)){
x=(x<<3)+(x<<1)+(ch^48);ch=getchar();
}
return fl?-x:x;
}
#define FASTIO ios::sync_with_stdio(false);cin.tie(0);
#define LL long long
#define read() read<int>()
const int maxn = 2e5 + 10;
const LL INF = 0x3f3f3f3f3f3f3f3f;
int cnt;
struct tree{
int ls,rs,sz;
LL val;
}t[maxn<<5];
#define mid ((l+r)>>1)
void build(int &p,int l,int r){
p=++cnt;
if(l==r)return ;
build(t[p].ls,l,mid);
build(t[p].rs,mid+1,r);
}
void update(int &p,int pre,int l,int r,int pos,LL val){
p=++cnt;
cerr<<p<<" "<<pre<<endl;
t[p].sz=t[pre].sz+1;
t[p].ls=t[pre].ls;t[p].rs=t[pre].rs;
t[p].val=t[pre].val+val;
if(l==r)return ;
if(pos<=mid)update(t[p].ls,t[pre].ls,l,mid,pos,val);
else update(t[p].rs,t[pre].rs,mid+1,r,pos,val);
}
LL query(int p,int l,int r,int k){
if(!k)return 0;
if(l==r){
return t[p].val/t[p].sz*k;
}
if(t[t[p].ls].sz>=k)return query(t[p].ls,l,mid,k);
LL res=t[t[p].ls].val;
res+=query(t[p].rs,mid+1,r,k-t[t[p].ls].sz);
return res;
}
int rt[maxn],n;
LL f[maxn],b[maxn],tot,mp[maxn];
pair<LL,LL> a[maxn];
inline LL w(int k,int x){
return a[x].first+mp[a[x].second]+query(rt[x-1],1,tot,k-1);
}
void DP(int l,int r,int k_l,int k_r){
assert(k_l<=k_r);
int k=max(k_l,mid);
for(int i=max(k_l,mid);i<=k_r;i++)if(w(mid,i)<w(mid,k))k=i;
f[mid]=w(mid,k);
if(l<mid)DP(l,mid-1,k_l,k);
if(r>mid)DP(mid+1,r,k,k_r);
}
int main(){
FASTIO;
cin>>n;
for(int i=1;i<=n;i++)cin>>a[i].second>>a[i].first;
sort(a+1,a+1+n);
for(int i=1;i<=n;i++)b[i]=a[i].second;
sort(b+1,b+1+n);
tot=unique(b+1,b+1+n)-(b+1);
build(rt[0],1,tot);
for(int i=1;i<=n;i++){
int pos=lower_bound(b+1,b+1+tot,a[i].second)-b;
mp[pos]=a[i].second;
a[i].second=pos;
update(rt[i],rt[i-1],1,tot,a[i].second,mp[a[i].second]);
}
DP(1,n,1,n);
for(int i=1;i<=n;i++)cout<<f[i]<<'\n';
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 11876kb
input:
3 2 5 4 3 3 7
output:
7 11 16
result:
ok 3 lines
Test #2:
score: -100
Time Limit Exceeded
input:
200000 466436993 804989151 660995237 756645598 432103296 703610564 6889895 53276988 873617076 822481192 532911431 126844295 623111499 456772252 937464699 762157133 708503076 786039753 78556972 5436013 582960979 398984169 786333369 325119902 930705057 615928139 924915828 506145001 164984329 208212435...