/*
 ██████╗ ██╗███╗   ██╗ ██████╗    ████████╗██╗ █████╗ ███╗   ██╗
██╔═══██ ██║████╗  ██║██╔════╝    ╚══██╔══╝██║██╔══██╗████╗  ██║
██║   ██║██║██╔██╗ ██║██║  ███╗      ██║   ██║███████║██╔██╗ ██║
██║▄▄ ██║██║██║╚██╗██║██║   ██║      ██║   ██║██╔══██║██║╚██╗██║
╚██████╔╝██║██║ ╚████║╚██████╔╝      ██║   ██║██║  ██║██║ ╚████║
 ╚══▀▀═╝ ╚═╝╚═╝  ╚═══╝ ╚═════╝       ╚═╝   ╚═╝╚═╝  ╚═╝╚═╝  ╚═══╝
 */
#include<bits/stdc++.h>
using namespace std;
typedef double ld;
typedef long long ll;
struct p3{
	ll x,y,z;
	friend p3 operator-(p3 a,p3 b){return {a.x+b.x,a.y+b.y,a.z+b.z};}
	friend ll operator*(p3 a,p3 b){return a.x*b.x+a.y*b.y+a.z*b.z;}
	friend p3 operator^(p3 a,p3 b){return {a.y*b.z-a.z*b.y,a.z*b.x-a.x*b.z,a.x*b.y-a.y*b.x};}
	
};
void solve(){
	p3 st,ed,vst,ved;
	cin>>st.x>>st.y>>st.z;
	cin>>vst.x>>vst.y;
	cin>>ed.x>>ed.y>>ed.z;
	cin>>ved.x>>ved.y;
	if((st-ed)*vst==0 && (st-ed)*ved==0){
		cout<<2<<'\n';
	}else{
		if(vst.x*ved.y-vst.y*ved.x==0 ){//平面平行，叉积为0
			cout<<4<<'\n';
		}else{
			cout<<3<<'\n';
		}
	}
	
	
}

int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);
	int _;cin>>_;
	while(_--) solve();
	
	return 0;
}