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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#541838#9224. Express EvictionXY_ElevenWA 1ms3972kbC++234.6kb2024-08-31 21:06:382024-08-31 21:06:41

Judging History

你现在查看的是最新测评结果

  • [2024-08-31 21:06:41]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3972kb
  • [2024-08-31 21:06:38]
  • 提交

answer

#include <bits/stdc++.h>
// #include <bits/extc++.h>
// using namespace __gnu_pbds;
using namespace std;
//#pragma GCC optimize(3)
#define DB double
#define LL long long
#define ULL unsigned long long
#define in128 __int128
#define cint const int
#define cLL const LL
#define For(z,e1,e2) for(int z=(e1);z<=(e2);z++)
#define Rof(z,e1,e2) for(int z=(e2);z>=(e1);z--)
#define For_(z,e1,e2) for(int z=(e1);z<(e2);z++)
#define Rof_(z,e1,e2) for(int z=(e2);z>(e1);z--)
#define inint(e) scanf("%d",&e)
#define inll(e) scanf("%lld",&e)
#define inpr(e1,e2) scanf("%d%d",&e1,&e2)
#define in3(e1,e2,e3) scanf("%d%d%d",&e1,&e2,&e3)
#define outint(e) printf("%d\n",e)
#define outint_(e) printf("%d%c",e," \n"[i==n])
#define outint2_(e,e1,e2) printf("%d%c",e," \n"[(e1)==(e2)])
#define outll(e) printf("%lld\n",e)
#define outll_(e) printf("%lld%c",e," \n"[i==n])
#define outll2_(e,e1,e2) printf("%lld%c",e," \n"[(e1)==(e2)])
#define exc(e) if(e) continue
#define stop(e) if(e) break
#define ret(e) if(e) return
#define ll(e) (1ll*(e))
#define pb push_back
#define ft first
#define sc second
#define pii pair<int,int> 
#define pli pair<LL,int> 
#define vct vector 
#define clean(e) while(!e.empty()) e.pop()
#define all(ev) ev.begin(),ev.end()
#define sz(ev) ((int)ev.size())
#define debug(x) printf("%s=%d\n",#x,x)
#define x0 __xx00__
#define y1 __yy11__
#define ffo fflush(stdout)
cLL mod=998244353,G=404;
// cLL mod[2]={1686688681ll,1666888681ll},base[2]={166686661ll,188868881ll};
template <typename Type> void get_min(Type &w1,const Type w2) { if(w2<w1) w1=w2; } template <typename Type> void get_max(Type &w1,const Type w2) { if(w2>w1) w1=w2; }
template <typename Type> Type up_div(Type w1,Type w2) { return (w1/w2+(w1%w2?1:0)); }
template <typename Type> Type gcd(Type X_,Type Y_) { Type R_=X_%Y_; while(R_) { X_=Y_; Y_=R_; R_=X_%Y_; } return Y_; } template <typename Type> Type lcm(Type X_,Type Y_) { return (X_/gcd(X_,Y_)*Y_); }
template <typename Type> Type md(Type w1,const Type w2=mod) { w1%=w2; if(w1<0) w1+=w2; return w1; } template <typename Type> Type md_(Type w1,const Type w2=mod) { w1%=w2; if(w1<=0) w1+=w2; return w1; }
void ex_gcd(LL &X_,LL &Y_,LL A_,LL B_) { if(!B_) { X_=1ll; Y_=0ll; return ; } ex_gcd(Y_,X_,B_,A_%B_); X_=md(X_,B_); Y_=(1ll-X_*A_)/B_; } LL inv(LL A_,LL B_=mod) { LL X_=0ll,Y_=0ll; ex_gcd(X_,Y_,A_,B_); return X_; }
template <typename Type> void add(Type &w1,const Type w2,const Type M_=mod) { w1=md(w1+w2,M_); } void mul(LL &w1,cLL w2,cLL M_=mod) { w1=md(w1*md(w2,M_),M_); } template <typename Type> Type pw(Type X_,Type Y_,Type M_=mod) { Type S_=1; while(Y_) { if(Y_&1) mul(S_,X_,M_); Y_>>=1; mul(X_,X_,M_); } return S_; }
template <typename Type> Type bk(vector <Type> &V_) { auto T_=V_.back(); V_.pop_back(); return T_; } template <typename Type> Type tp(stack <Type> &V_) { auto T_=V_.top(); V_.pop(); return T_; } template <typename Type> Type frt(queue <Type> &V_) { auto T_=V_.front(); V_.pop(); return T_; }
template <typename Type> Type bg(set <Type> &V_) { auto T_=*V_.begin(); V_.erase(V_.begin()); return T_; } template <typename Type> Type bk(set <Type> &V_) { auto T_=*prev(V_.end()); V_.erase(*prev(V_.end())); return T_; }
mt19937 gen(time(NULL)); int rd() { return abs((int)gen()); }
int rnd(int l,int r) { return rd()%(r-l+1)+l; }
void main_init()
{

}
cint N=53;
int n,m;
int a[N][N],d1[N][N],d2[N][N];
char s[N];
int dis[N][N];
cint inf=1e9;
void main_solve()
{
    inpr(n,m);
    For(i,1,n)
    {
        scanf("%s",s+1);
        For(j,1,m)
        {
            exc(s[j]=='.');
            For(k1,-1,0) For(k2,-1,0)
                a[i+k1][j+k2]++;
            d1[i-1][j]++,d1[i-1][j-1]++;
            d2[i][j-1]++,d2[i-1][j-1]++;
        }
    }
    For(i,0,n) For(j,0,m) dis[i][j]=inf;
    dis[0][0]=a[0][0];
    For(_,0,n*m)
    {
        For_(i,0,n) For(j,0,m)
        {
            get_min(dis[i+1][j],dis[i][j]-d1[i][j]+a[i+1][j]);
            get_min(dis[i][j],dis[i+1][j]-d1[i][j]+a[i][j]);
        }
        For(i,0,n) For_(j,0,m)
        {
            get_min(dis[i][j+1],dis[i][j]-d2[i][j]+a[i][j+1]);
            get_min(dis[i][j],dis[i][j+1]-d2[i][j]+a[i][j]);
        }
    }
    // For(i,0,n)
    // {
    //     For(j,0,m) printf("%d ",dis[i][j]);
    //     printf("\n");
    // }
    outint(dis[n][m]);
}
int main()
{
    // ios::sync_with_stdio(0); cin.tie(0);
    // freopen("in.txt","r",stdin);
    // freopen("out1.txt","w",stdout);
    // srand(time(NULL));
    main_init();
    // int _; inint(_); For(__,1,_) // T>1 ?
        // printf("\n------------\n\n"),
        main_solve();
    return 0;
}
/*

*/

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3964kb

input:

4 6
.##...
.#....
##....
....#.

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3972kb

input:

20 30
...###########################
#..###########################
...###########################
...###########################
.#############################
...###########################
...###########################
#..###########################
...###########################
..#...............

output:

12

result:

wrong answer 1st numbers differ - expected: '11', found: '12'