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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#539287#8217. King's DinnerliyelinWA 1ms3652kbC++142.7kb2024-08-31 14:25:342024-08-31 14:25:34

Judging History

你现在查看的是最新测评结果

  • [2024-08-31 14:25:34]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3652kb
  • [2024-08-31 14:25:34]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
#define PB push_back
#define MP make_pair
#define PII pair<int, int>
#define FOR(i, l, r) for (int i = (l); i <= (r); ++i)
#define ROF(i, r, l) for (int i = (r); i >= (l); --i)
#define FI first
#define SE second
#define SZ size()
using namespace std;
const int N = 1e2 + 5;
const int mod = 998244353;
const int inf = 1e18;
int n, T;
bool mp[N][N];
void solve(int l, int r) {
    if (l > r) {
        return;
    }
    FOR (i, l, r - 3) {
        mp[i][l] = mp[i][l + 1] = 1;
        ++i;
    }
    FOR (i, l, r - 3) {
        mp[r - 1][i] = mp[r][i] = 1;
        ++i;
    }
    ROF (i, r, l + 3) {
        mp[i][r - 1] = mp[i][r + 1] = 1;
        --i;
    }
    ROF (i, r, l + 3) {
        mp[l + 1][i] = mp[l + 2][i] = 1;
        --i;
    }
    solve(l + 3, r - 3);
}
signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin >> T;
    while (T --> 0) {
        cin >> n;
        FOR (i, 1, n) {
            FOR (j, 1, n) {
                mp[i][j] = 0;
            }
        }
        if (n & 1) {
            FOR (i, 1, n) {
                FOR (j, 1, n - 1) {
                    mp[i][j] = mp[i][j + 1] = 1;
                    j += 2;
                }
                ++i;
            }
            if (n % 6 == 3) {
                FOR (i, 1, n) {
                    FOR (j, n - 2, n) {
                        mp[i][j] = 0;
                    }
                }
                FOR (i, 1, n - 1) {
                    mp[i][n - 2] = mp[i + 1][n - 2] = mp[i][n] = mp[i + 1][n] = 1;
                    i += 2;
                }
            } else if (n % 6 == 1) {
                FOR (i, 1, n - 1) {
                    mp[i][n] = mp[i + 1][n] = 1;
                    i += 2;
                }
            }
        } else if (n % 6 == 0) {
            solve(1, n);
        } else {
            FOR (i, 1, n - 3) {
                FOR (j, 1, n - 1) {
                    mp[i][j] = mp[i][j + 1] = 1;
                    j += 2;
                }
                ++i;
            }
            FOR (i, 1, n) {
                mp[n][i] = mp[n - 1][i] = 1;
                ++i;
            }
            if (n % 6 == 4) {
                FOR (i, 1, n - 3) {
                    mp[i][n] = mp[i + 1][n] = 1;
                    i += 2;
                }
                mp[n - 1][n - 1] = 0;
                mp[n][n - 1] = mp[n][n] = 1;
            }
        }
        FOR (i, 1, n) {
            FOR (j, 1, n) {
                if (mp[i][j]) {
                    cout << '#';
                } else {
                    cout << '.';
                }
            }
            cout << '\n';
        }
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3652kb

input:

3
1
2
3

output:

.
#.
#.
#.#
#.#
...

result:

ok all tests correct (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3564kb

input:

50
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50

output:

.
#.
#.
#.#
#.#
...
##.#
...#
#...
#.##
##.##
.....
##.##
.....
##.##
##....
...#.#
##.#.#
....#.
#.#...
#.#.#.
##.##.#
......#
##.##..
......#
##.##.#
.......
##.##..
##.##.##
........
##.##.##
........
##.##.##
........
#.#.#.#.
#.#.#.#.
##.##.#.#
......#.#
##.##....
......#.#
##.##.#.#
.........
...

result:

wrong answer grid contains two dominoes that are adjacent (test case 6)