QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#53807#1869. Power Station of Art2022zllAC ✓158ms17076kbC++1.9kb2022-10-05 22:58:132022-10-05 22:58:14

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-10-05 22:58:14]
  • 评测
  • 测评结果:AC
  • 用时:158ms
  • 内存:17076kb
  • [2022-10-05 22:58:13]
  • 提交

answer

#include<algorithm>
#include<cstdio>
#include<cstring>
void read(int&num){
	int ch=getchar();
	num=0;
	while(ch<48||ch>57)ch=getchar();
	while(ch>=48&&ch<=57)num=(num<<3)+(num<<1)+(ch^48),ch=getchar();
}
const int maxn=1000005,maxm=1000005;
char s[maxn];
int T,n,m,head[maxn],total;
struct Edge{
	int to,next;
}e[maxm<<1];
void add(int u,int v){
	e[++total]=Edge{v,head[u]};
	head[u]=total;
}
int col[maxn],inv[2][maxn],inc[2][maxn];
int flag,vis_cnt;
struct Data{
	int first,second;
}st[2][maxn];
bool operator<(const Data a,const Data b){
	return a.first!=b.first?a.first<b.first:a.second<b.second;
}
bool operator!=(const Data a,const Data b){
	return a.first!=b.first||a.second!=b.second;
}
void dfs(int u){
	vis_cnt++;
	for(int op=0;op<=1;op++)st[op][vis_cnt]=Data{inv[op][u],inc[op][u]^col[u]};
	for(int i=head[u];i;i=e[i].next){
		int v=e[i].to;
		if(col[v]==-1){
			col[v]=col[u]^1;
			dfs(v);
		}else if(col[u]==col[v])flag=1;
	}
}
bool work(int task){
	read(n),read(m);
	memset(col+1,-1,sizeof(int)*n);
	if(task>1){
		memset(head+1,0,sizeof(int)*n);
		total=0;
	}
	for(int i=1,u,v;i<=m;i++){
		read(u),read(v);
		add(u,v),add(v,u);
	}
	for(int op=0;op<=1;op++){
		for(int i=1;i<=n;i++)read(inv[op][i]);
		scanf("%s",s+1);
		for(int i=1;i<=n;i++)inc[op][i]=(s[i]=='R');
	}
	for(int i=1;i<=n;i++)
		if(col[i]==-1){
			flag=vis_cnt=0;
			col[i]=0;
			dfs(i);
			for(int op=0;op<=1;op++)std::sort(st[op]+1,st[op]+vis_cnt+1);
			if(flag){
				int tmp=0;
				for(int op=0;op<=1;op++)
					for(int i=1;i<=vis_cnt;i++)
						tmp^=st[op][i].second;
				if(tmp)return false;
				for(int i=1;i<=vis_cnt;i++)
					if(st[0][i].first!=st[1][i].first)
						return false;
			}else{
				for(int i=1;i<=vis_cnt;i++)
					if(st[0][i]!=st[1][i])
						return false;
			}
		}
	return true;
}
int main(){
	read(T);
	for(int i=1;i<=T;i++)puts(work(i)?"YES":"NO");
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 2024kb

input:

3
2 1
1 2
3 4
RR
4 3
BB
3 2
1 2
2 3
1 1 1
RBR
1 1 1
BBB
3 3
1 2
2 3
3 1
1 1 1
RBR
1 1 1
BBB

output:

YES
NO
YES

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 158ms
memory: 17076kb

input:

25054
5 10
4 5
4 2
4 3
4 1
5 2
5 3
5 1
2 3
2 1
3 1
12 2 9 10 7
RRRBB
10 2 9 7 12
RRBRB
1 0
4
R
4
R
8 4
4 3
1 5
8 5
6 5
7 2 11 10 9 6 3 5
RBRBBRBR
7 2 10 11 6 5 3 9
RBRBBRBR
7 4
7 2
5 1
5 6
5 4
12 5 9 14 5 12 12
RRBRBRR
14 12 9 5 12 12 5
RBBRBRB
10 1
4 6
5 3 2 9 7 3 11 11 6 8
RRRBRRBBBR
5 3 2 3 7 9 1...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
NO
NO
YES
YES
YES
NO
YES
NO
YES
YES
NO
YES
YES
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
NO
YES
NO
NO...

result:

ok 25054 lines