QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#535797#9114. Black or White 2synonymRE 0ms0kbC++173.1kb2024-08-28 14:57:292024-08-28 14:57:31

Judging History

你现在查看的是最新测评结果

  • [2024-08-28 14:57:31]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-08-28 14:57:29]
  • 提交

answer

#include "bits/stdc++.h"
using namespace std;
#define int long long
#define all(x) begin(x), end(x)
#define sz(x) (int) (x).size()

const int mxn=2e3;
void check();

int n,m,k,fl,nm;
int g[mxn][mxn];

void solve2() {
	if (k%2) {
		for (int i=0; i<m; i++) {
			if (k==0) break;
			g[0][i] = 1; k--; if (k==0) break;
			g[1][i] = 1; k--; if (k==0) break;
		}
	} else {
		if (k==0) return;
		g[0][m-1] = 1; k--;
		for (int i=0; i<m; i++) {
			if (k==0) break;
			g[0][i] = 1; k--; if (k==0) break;
			g[1][i] = 1; k--; if (k==0) break;
		}
	}
}

void solve3() {
	if (k%3==0 && k) {
		g[0][m-1] = 1; k--;
	}
	int ok = k;
	for (int i=0; k; i++) {
		if (!k) break;
		if (ok%3==1) {
			g[1][i] = 1; k--;
			if (!k) break;
			g[0][i] = 1; k--;
			g[2][i] = 1; k--;
			if (!k) break;
		} else {
			g[0][i] = 1; k--;
			g[2][i] = 1; k--;
			if (!k) break;
			g[1][i] = 1; k--;
			if (!k) break;
		}
		
	}
}

void solvek2() {
	g[0][0] = g[n-1][m-1] = 1;
}

void solven() {
//	swap(n,m); nm = !nm;
	for (int i=0; i<=n; i++) {
		for (int j=0; j<=m; j++) {
			g[i][j] = 0;
		}
	}
	int c = 0;
	while (k >= 2*n) {
		for (int i=0; i<n; i++) {
			g[i][c] = 1; k--;
		}
		c++;
	}
	if (k >= n) {
		for (int i=0; i<n; i+=2) {
			g[i][c] = 1; k--;
		}
	}
	
	if (2*k <= n) {
		for (int i=0; k; i+=2) {
			g[i][m-1] = 1; k--;
		}
		return;
	}
	int fff = 0;
	if (k%3==2) {
		fff = 1; k--;
	}
	int sp = 0;
	if (k%3==1) {
		g[0][m-1] = 1; sp=1; k--;
	}
	for (int i=sp; k; i++) {
		g[i][m-1] = 1; k--;
		if (!k) break;
		if (i%2==sp%2) {
			g[i][m-2] = 1; k--;
		}
	}
	if (fff) {
		for (int i=0; i<n; i++) {
			for (int j=0; j<m; j++) {
				if (g[i][j]) continue;
				int su=0;
				su += g[i+1][j+1]+g[i+1][j]+(j?g[i+1][j-1]:0);
				su += g[i][j+1]+g[i][j+1]+(j?g[i][j-1]:0);
				if (i) su += g[i-1][j+1]+g[i-1][j]+(j?g[i-1][j-1]:0);
				if (!su) {
//					cout<<i<<" "<<j<<" "<<su<<endl;
					fff = 0;
					g[i][j] = 1;
					return;
				}
			}
		}
	}
}

void solve() {
	cin>>n>>m>>k;
//	cout<<n<<" "<<m<<" "<<k<<endl;
	if (2*k > n*m) {
		fl = 1;
		k = n*m-k;
	} else fl = 0;
	if (n>m) {
		nm = 1;
		swap(n,m);
	} else nm = 0;
	
	for (int i=0; i<n; i++) {
		for (int j=0; j<m; j++) g[i][j]=0;
	}
	
	if (n==3 && m==3 && k==4) {
		g[0][0] = g[0][1] = g[0][2] = g[1][1] = 1;
	} else {
	
	if (n==2) {
		solve2();
	} else if (n==3) {
		solve3();
	} else if (k==2) {
		solvek2();
	} else {
		solven();
	}
	}
	if (fl) {
		for (int i=0; i<n; i++) {
			for (int j=0; j<m; j++) {
				g[i][j] = 1-g[i][j];
			}
		}
	}
	check();
	if (nm) {
		for (int j=0; j<m; j++) {
			for (int i=0; i<n; i++) {
				cout<<g[i][j]<<"";
			}
			cout<<"\n";
		}
	} else {
		for (int i=0; i<n; i++) {
			for (int j=0; j<m; j++) {
				cout<<g[i][j]<<"";
			}
			cout<<"\n";
		}
	}
	cout<<"\n";
}

void check() {
	for (int i=0; i<n-1; i++) {
		for (int j=0; j<m-1; j++) {
			if (g[i][j]+g[i][j+1]+g[i+1][j]+g[i+1][j+1]==2) {
				assert(0);
			}
		}
	}
}

signed main() {
	ios::sync_with_stdio(false); cin.tie(nullptr);
	
	int t; cin>>t;
	for (int i=0; i<t; i++) {
		solve();
	}
	
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 0
Runtime Error

input:

2
2 2 2
2 3 0

output:


result: