#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define fi first
#define se second
const ll mod=998244353;
int n,m;
ll C[305][305];
ll dp[305][305];//ways to clear [i,j] such that i is the last cleared
int a[305];//number of + with at most i - following it
int pa[305];
int y[305];

ll dp2[305][305];//ways to fill 1-i such that the suffix j guys are cleared
int main(){
	ios::sync_with_stdio(false);cin.tie(0);
	//freopen("in.txt","r",stdin);
	cin >> n >> m;
	for(int i=0; i<=n ;i++){
		C[i][0]=1;
		for(int j=1; j<=i ;j++){
			C[i][j]=(C[i-1][j-1]+C[i-1][j])%mod;
		}
	}
	string s;cin >> s;
	int frog=0;
	for(int i=s.size()-1; i>=0 ;i--){
		if(s[i]=='-') frog++;
		else a[frog]++;
	}
	pa[0]=a[0];
	for(int i=1; i<=m ;i++) pa[i]=pa[i-1]+a[i];
	for(int i=0; i<=m ;i++)
	for(int i=1; i<=m ;i++){
		int x;cin >> x;y[x]=1;
	}
	for(int i=1; i<=n ;i++)y[i]+=y[i-1];
	for(int i=m; i>=1 ;i--){
		for(int j=i; j<=m ;j++){
			for(int k=i+1; k<=j ;k++){//2nd last guy that got killed
				ll w1=dp[i][k-1];
				ll w2=dp[k][j]*(pa[j]-pa[k-1]-(j-k))%mod;
				ll w3=C[j-i-1][j-k];
				dp[i][j]=(dp[i][j]+w1*w2%mod*w3)%mod;
			}
			if(i==j) dp[i][j]=1;
		}
	}
	for(int i=m; i>=1 ;i--){
		for(int j=i; j<=m ;j++){
			dp[i][j]=dp[i][j]*(pa[j]-pa[i-1]-(j-i))%mod;
			//cout << "hi " << i << ' ' << j << ' ' << dp[i][j] << endl;
		}
	}
	
	dp2[0][0]=1;
	for(int r=1; r<=n ;r++){
		if(y[r]==y[r-1]){//rotting in queue
			for(int j=0; j<r ;j++){
				int space=pa[j]-(r-y[r]-1)-j;
				space=max(space,0);
				dp2[r][j]=dp2[r-1][j]*space%mod;
				//cout << "dp2 " << r << ' ' << j << ' ' << dp2[r][j] << endl;
			}

			continue;
		}
		for(int j=0; j<r ;j++){
			dp2[r][j]=(dp2[r][j]+dp2[r-1][j])%mod;//not fancy
			for(int k=j+1; k<=r ;k++){//fancy
				if(y[r]<k) break;
				ll ways=C[y[r]-j-1][k-j-1]*dp[j+1][k]%mod;
				dp2[r][k]=(dp2[r][k]+dp2[r-1][j]*ways)%mod;
			}
		}
		//for(int j=0; j<=r ;j++) cout << "dp2 " << r << ' ' << j << ' ' << dp2[r][j] << endl;
	}
	cout << dp2[n][m] << '\n';
}