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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#534948 | #9224. Express Eviction | gzchenben | WA | 1ms | 4592kb | C++14 | 2.5kb | 2024-08-27 17:50:32 | 2024-08-27 17:50:33 |
Judging History
answer
#include<cstdio>
#include<vector>
#include<algorithm>
#include<queue>
using namespace std;
int n, m;
int a[55][55];
vector<pair<int, int>> ed[10005]; // to,val
int id(int x, int y, int flag) { // 0 : straight 1 : corner 0->1
if (x < 0 || x > n || y < 0 || y > m) return -1;
else return 2 * (x * (m + 1) + y) + flag;
}
int dis[10005];
bool vis[10005];
priority_queue<pair<int, int>> Q; // -dis, pos
void dijkstra() {
for (int i = 0;i <= n;i++) {
for (int j = 0;j <= m;j++) {
dis[id(i, j, 0)] = 1e9;
dis[id(i, j, 1)] = 1e9;
}
}
dis[id(0, 0, 0)] = 0;
Q.push({ 0, id(0, 0, 0) });
while (!Q.empty()) {
int cur = Q.top().second;
Q.pop();
if (vis[cur]) continue;
vis[cur] = true;
for (auto& p : ed[cur]) {
if (dis[p.first] > dis[cur] + p.second) {
dis[p.first] = dis[cur] + p.second;
Q.push({ -dis[p.first], p.first });
}
}
}
}
int main() {
scanf("%d%d", &n, &m);
for (int i = 1;i <= n;i++) {
for (int j = 1;j <= m;j++) {
char tmp;
scanf(" %c", &tmp);
if (tmp == '#') a[i][j] = 1;
}
}
for (int i = 0;i <= n;i++) {
for (int j = 0;j < m;j++) {
int cnt = 0;
for (int k = j + 1;k <= m;k++) {
cnt += a[i][k] + a[i + 1][k];
ed[id(i, j, 0)].push_back({ id(i,k,1), cnt });
ed[id(i, k, 0)].push_back({ id(i,j,1), cnt });
}
}
}
for (int i = 0;i <= m;i++) {
for (int j = 0;j < n;j++) {
int cnt = 0;
for (int k = j + 1;k <= n;k++) {
cnt += a[k][i] + a[k][i + 1];
ed[id(j, i, 0)].push_back({ id(k,i,1), cnt });
ed[id(k, i, 0)].push_back({ id(j,i,1), cnt });
}
}
}
int dx[5] = { 0,1,0,-1,0 }, dy[5] = { 1,0,-1,0,1 };
for (int i = 0;i <= n;i++) {
for (int j = 0;j <= m;j++) {
ed[id(i, j, 0)].push_back({ id(i,j,1), 0 });
int cnt = a[i][j] + a[i][j + 1] + a[i + 1][j] + a[i + 1][j + 1];
for (int d = 0;d < 4;d++) {
if (id(i + dx[d], j + dy[d], 1) == -1 || id(i + dx[d + 1], j + dy[d + 1], 1) == -1) continue;
ed[id(i + dx[d], j + dy[d], 1)].push_back({ id(i + dx[d + 1], j + dy[d + 1], 0), cnt });
}
}
}
dijkstra();
printf("%d\n", dis[id(n, m, 1)]);
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 4020kb
input:
4 6 .##... .#.... ##.... ....#.
output:
1
result:
ok 1 number(s): "1"
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 4592kb
input:
20 30 ...########################### #..########################### ...########################### ...########################### .############################# ...########################### ...########################### #..########################### ...########################### ..#...............
output:
10
result:
wrong answer 1st numbers differ - expected: '11', found: '10'