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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#534182#6136. AirdropTomato_FishAC ✓474ms14128kbC++142.0kb2024-08-26 21:46:152024-08-26 21:46:15

Judging History

你现在查看的是最新测评结果

  • [2024-08-26 21:46:15]
  • 评测
  • 测评结果:AC
  • 用时:474ms
  • 内存:14128kb
  • [2024-08-26 21:46:15]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

const int N=1e5+100;
struct node{
    int x,y;
}g[N];

map<int,int> B,C;
int qz1[N],qz2[N],Type[N],Las[N];

bool cmp(node n1,node n2) {return (n1.x<n2.x);}

int main()
{

    int T;
    scanf("%d",&T);
    while(T--){
        int n,y0;
        scanf("%d%d",&n,&y0);
        for(int i=1;i<=n;i++) scanf("%d%d",&g[i].x,&g[i].y);

        sort(g+1,g+n+1,cmp);

        B.clear();qz1[0]=0;
        int cnt1=0,cnt2=0;
        for(int i=1;i<=n;i++){
            int tmp=abs(g[i].y-y0)-g[i].x;
            if(B[tmp]==0) B[tmp]=++cnt1;
            tmp=B[tmp];
            if(Type[tmp]==0){
                if(Las[tmp]!=g[i].x)
                    Type[tmp]=1,qz1[i]=qz1[i-1];
                else
                    qz1[i]=qz1[i-1]+1;
            }
            else{
                Type[tmp]=0;
                Las[tmp]=g[i].x;
                qz1[i]=qz1[i-1]+2;
            }
        }
        for(int i=1;i<=cnt1;i++) Type[i]=Las[i]=0;

        C.clear();qz2[n+1]=0;
        for(int i=n;i>=1;i--){
            int tmp=abs(g[i].y-y0)+g[i].x;
            if(C[tmp]==0) C[tmp]=++cnt2;
            tmp=C[tmp];
            if(Type[tmp]==0){
                if(Las[tmp]!=g[i].x)
                    Type[tmp]=1,qz2[i]=qz2[i+1];
                else
                    qz2[i]=qz2[i+1]+1;
            }
            else{
                Type[tmp]=0;
                Las[tmp]=g[i].x;
                qz2[i]=qz2[i+1]+2;
            }
        }
        for(int i=1;i<=cnt2;i++) Type[i]=Las[i]=0;


        int las=0,mx=qz2[1],mn=qz2[1];
        for(int i=1;i<=n;i++)
            if(i==n||g[i].x!=g[i+1].x){
                mx=max(mx,qz1[las]+qz2[i+1]);
                mn=min(mn,qz1[las]+qz2[i+1]);
                if(i==n||g[i+1].x-1>g[i].x){
                    mx=max(mx,qz1[i]+qz2[i+1]);
                    mn=min(mn,qz1[i]+qz2[i+1]);
                }
                las=i;
            }

        printf("%d %d\n",n-mx,n-mn);
    }

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3912kb

input:

3
3 2
1 2
2 1
3 5
3 3
2 1
2 5
4 3
2 3
1 3
4 3

output:

1 3
0 3
2 2

result:

ok 6 numbers

Test #2:

score: 0
Accepted
time: 474ms
memory: 14128kb

input:

3508
6 1
7 1
1 1
9 1
10 1
3 1
4 1
3 8
8 9
8 7
1 8
9 5
10 1
10 8
10 2
5 1
9 9
5 9
10 9
6 4
4 7
6 7
10 5
3 8
9 5
9 9
7 5
4 7
10 5
6 9
9 5
6 6
9 3
3 2
5 1
3 8
6 4
5 9
10 2
2 9
10 10
10 8
4 1
7 1
6 1
3 1
5 1
2 4
9 3
3 3
4 5
3 8
9 6
9 9
6 3
9 5
9 3
2 9
9 1
9 2
4 1
5 4
5 6
6 5
9 8
4 1
2 1
5 1
7 1
3 1
9 10...

output:

6 6
1 3
1 5
2 6
2 6
0 2
4 4
2 2
4 4
4 7
4 4
9 9
4 6
0 3
2 6
2 2
2 6
10 10
9 9
1 3
2 4
0 2
2 4
4 7
6 6
9 9
2 2
2 2
3 5
1 4
2 2
1 1
3 5
4 7
3 6
1 1
5 7
5 5
1 3
2 2
1 7
1 1
4 6
2 4
2 6
2 4
1 7
2 4
9 9
0 3
1 1
3 8
2 2
2 2
9 9
3 7
4 4
4 6
2 5
0 2
2 5
3 3
0 4
4 4
2 4
2 2
4 6
6 6
6 6
0 2
2 6
2 4
2 6
2 5
1 ...

result:

ok 7016 numbers