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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#532948#5668. Cell Nuclei Detectionttbchimbu999#AC ✓3610ms922860kbC++204.7kb2024-08-25 14:59:132024-08-25 14:59:14

Judging History

你现在查看的是最新测评结果

  • [2024-08-25 14:59:14]
  • 评测
  • 测评结果:AC
  • 用时:3610ms
  • 内存:922860kb
  • [2024-08-25 14:59:13]
  • 提交

answer

#include <bits/stdc++.h>
#define fi first
#define se second
#define mp make_pair
#define all(x) x.begin(), x.end()

using namespace std;
template <class X, class Y> bool minimize(X &a, Y b) {
    if (a > b) return a = b, true;
    return false;
}
template <class X, class Y> bool maximize(X &a, Y b) {
    if (a < b) return a = b, true;
    return false;
}

struct FlowEdge {
    int u, v;
    long long cap, flow = 0;
    FlowEdge(int v, int u, long long cap) :
        v(v), u(u), cap(cap) {}
};

struct Dinic {
    const long long flow_inf = 1e18;
    vector<FlowEdge> edges;
    vector<vector<int>> adj;
    int n, m = 0;
    int s, t;
    vector<int> level, ptr;
    queue<int> q;

    Dinic(int n, int s, int t) : n(n), s(s), t(t) {
        adj.resize(n);
        level.resize(n);
        ptr.resize(n);
    }

    void add_edge(int v, int u, long long cap) {
        edges.emplace_back(v, u, cap);
        edges.emplace_back(u, v, 0);
        adj[v].push_back(m);
        adj[u].push_back(m + 1);
        m += 2;
    }

    bool bfs() {
        while (!q.empty()) {
            int v = q.front();
            q.pop();
            for (int id: adj[v]) {
                if (edges[id].cap - edges[id].flow < 1) {
                    continue;
                }
                if (level[edges[id].u] != -1) {
                    continue;
                }
                level[edges[id].u] = level[v] + 1;
                q.push(edges[id].u);
            }
        }
        return level[t] != -1;
    }

    long long dfs(int v, long long pushed) {
        if (pushed == 0) 
            return 0;
        if (v == t) 
            return pushed;
        for (int &cid = ptr[v]; cid < (int) adj[v].size(); cid++) {
            int id = adj[v][cid];
            int u = edges[id].u;
            if (level[v] + 1 != level[u] || edges[id].cap - edges[id].flow < 1)
                continue;
            long long tr = dfs(u, min(pushed, edges[id].cap - edges[id].flow));
            if (tr == 0)
                continue;
            edges[id].flow += tr;
            edges[id ^ 1].flow -= tr;
            return tr;
        }
        return 0;
    }

    long long flow() {
        long long f = 0;
        while (true) {
            fill(level.begin(), level.end(), -1);
            level[s] = 0;
            q.push(s);
            if (!bfs())
                break;
            fill(ptr.begin(), ptr.end(), 0);
            while (long long pushed = dfs(s, flow_inf)) {
                f += pushed;
            }
        }
        return f;
    }
};

struct Rec_t {
    int x[2];
    int y[2];
    void input() {
        cin >> x[0] >> y[0] >> x[1] >> y[1];
        // cerr << x[0] << ' ' << y[0] << ' ' << x[1] << ' ' << y[1] << '\n';
    }
    int get_rec() {
        return (y[1] - y[0]) * (x[1] - x[0]);
    }
    friend int rec_intersect(Rec_t a, Rec_t b) {
        int u = max(a.y[0], b.y[0]);
        int d = min(a.y[1], b.y[1]);
        int l = max(a.x[0], b.x[0]);
        int r = min(a.x[1], b.x[1]);
        // cerr << u << ' ' << d << ' ' << l << ' ' << r << '\n';
        return (d - u) * (r - l);
    }
};

const int N = 50005;
const int M = 2002;
vector<int> p[M][M];
Rec_t a[N];
Rec_t b[N];

void run_case() {
    int n, m;
    cin >> n >> m;
    for (int i = 0; i < M; i++) {
        for (int j = 0; j < M; j++) {
            p[i][j].clear();
        }
    }
    for (int i = 1; i <= n; i++) {
        a[i].input();
        // cerr << "##" << i << ": " << a[i].get_rec() << '\n';
    } 
    for (int i = 1; i <= m; i++) {
        b[i].input();
        for (int x = b[i].x[0]; x <= b[i].x[1]; x++) {
            for (int y = b[i].y[0]; y <= b[i].y[1]; y++) {
                p[x][y].push_back(i);
            }
        }
    }
    // cerr << rec_intersect(a[1], b[2]) << '\n';
    // return;
    int s = 0, t = n + m + 1;
    Dinic dinic(n + m + 3, s, t);
    for (int i = 1; i <= n; i++) {
        for (int x = a[i].x[0]; x <= a[i].x[1]; x++) {
            for (int y = a[i].y[0]; y <= a[i].y[1]; y++) {
                for (int j: p[x][y]) {
                    if (2 * rec_intersect(a[i], b[j]) >= a[i].get_rec()) {
                        // cerr << i << ' ' << j << '\n';
                        dinic.add_edge(i, j + n, 1);
                    }
                }
            }
        }
    }
    for (int i = 1; i <= n; i++) {
        dinic.add_edge(s, i, 1);
    }
    for (int i = 1; i <= m; i++) {
        dinic.add_edge(i + n, t, 1);
    }
    cout << dinic.flow() << '\n';
}

signed main() {
    cin.tie(0)->sync_with_stdio(0);
    int t; cin >> t;
    while (t --) {
        run_case();
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 13ms
memory: 3784kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 8ms
memory: 3784kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #3:

score: 0
Accepted
time: 812ms
memory: 922860kb

input:

5
50000 50000
0 0 4 4
4 0 8 4
8 0 12 4
12 0 16 4
16 0 20 4
20 0 24 4
24 0 28 4
28 0 32 4
32 0 36 4
36 0 40 4
40 0 44 4
44 0 48 4
48 0 52 4
52 0 56 4
56 0 60 4
60 0 64 4
64 0 68 4
68 0 72 4
72 0 76 4
76 0 80 4
80 0 84 4
84 0 88 4
88 0 92 4
92 0 96 4
96 0 100 4
100 0 104 4
104 0 108 4
108 0 112 4
112 ...

output:

50000
50000
0
50000
3150

result:

ok 5 lines

Test #4:

score: 0
Accepted
time: 431ms
memory: 232164kb

input:

5
50000 50000
0 0 1 1
1 0 2 1
2 0 3 1
3 0 4 1
4 0 5 1
5 0 6 1
6 0 7 1
7 0 8 1
8 0 9 1
9 0 10 1
10 0 11 1
11 0 12 1
12 0 13 1
13 0 14 1
14 0 15 1
15 0 16 1
16 0 17 1
17 0 18 1
18 0 19 1
19 0 20 1
20 0 21 1
21 0 22 1
22 0 23 1
23 0 24 1
24 0 25 1
25 0 26 1
26 0 27 1
27 0 28 1
28 0 29 1
29 0 30 1
30 0 ...

output:

50000
25050
12500
16000
8000

result:

ok 5 lines

Test #5:

score: 0
Accepted
time: 290ms
memory: 99160kb

input:

5
50000 50000
0 0 2 4
4 0 7 1
8 0 10 1
12 0 15 3
16 0 19 1
20 0 22 2
24 0 26 4
28 0 30 4
32 0 36 3
36 0 40 1
40 0 44 1
44 0 47 2
48 0 49 3
52 0 54 1
56 0 59 4
60 0 64 3
64 0 68 3
68 0 70 1
72 0 76 4
76 0 80 3
80 0 84 4
84 0 87 2
88 0 90 1
92 0 94 4
96 0 98 1
100 0 104 1
104 0 107 2
108 0 110 4
112 0...

output:

10594
10779
10618
10381
10779

result:

ok 5 lines

Test #6:

score: 0
Accepted
time: 3610ms
memory: 906268kb

input:

5
50000 50000
0 0 4 4
1 0 5 4
2 0 6 4
3 0 7 4
4 0 8 4
5 0 9 4
6 0 10 4
7 0 11 4
8 0 12 4
9 0 13 4
10 0 14 4
11 0 15 4
12 0 16 4
13 0 17 4
14 0 18 4
15 0 19 4
16 0 20 4
17 0 21 4
18 0 22 4
19 0 23 4
20 0 24 4
21 0 25 4
22 0 26 4
23 0 27 4
24 0 28 4
25 0 29 4
26 0 30 4
27 0 31 4
28 0 32 4
29 0 33 4
30...

output:

50000
50000
50000
50000
49600

result:

ok 5 lines

Test #7:

score: 0
Accepted
time: 7ms
memory: 3624kb

input:

1
4 4
1 1 3 3
2 1 4 3
1 2 3 4
2 2 4 4
2 1 4 3
3 2 5 4
1 2 3 4
2 3 4 5

output:

3

result:

ok single line: '3'