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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#530408#8544. Colorful Graph 2chenxinyang2006WA 146ms15884kbC++202.1kb2024-08-24 16:14:422024-08-24 16:14:43

Judging History

你现在查看的是最新测评结果

  • [2024-08-24 16:14:43]
  • 评测
  • 测评结果:WA
  • 用时:146ms
  • 内存:15884kb
  • [2024-08-24 16:14:42]
  • 提交

answer

#include <bits/stdc++.h>
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
#define uint unsigned int
#define ll long long
#define ull unsigned long long
#define db double
#define ldb long double
#define pii pair<int,int>
#define pll pair<ll,ll>
#define mkp make_pair
#define eb emplace_back
#define SZ(S) (int)S.size()
//#define mod 998244353
//#define mod 1000000007
#define inf 0x3f3f3f3f
#define linf 0x3f3f3f3f3f3f3f3f
using namespace std;

template <class T>
void chkmax(T &x,T y){
	if(x < y) x = y;
}

template <class T>
void chkmin(T &x,T y){
	if(x > y) x = y;
}

inline int popcnt(int x){
	return __builtin_popcount(x);
}

inline int ctz(int x){
	return __builtin_ctz(x);
}


/*ll power(ll p,int k = mod - 2){
	ll ans = 1;
	while(k){
		if(k % 2 == 1) ans = ans * p % mod;
		p = p * p % mod;
		k /= 2;	
	}
	return ans;
}*/
int T,n,m;
set <int> G[200005];

void add(int u,int v){
	G[u].insert(v);G[v].insert(u);
}

void del(int u,int v){
	assert(G[u].count(v));
	G[u].erase(v);G[v].erase(u);
}

int a[200005],adj[200005][2],ans[200005];
vector <int> ord,Q;
void solve(){
	scanf("%d%d",&n,&m);
	rep(u,1,n){
		G[u].clear();
		adj[u][0] = adj[u][1] = 0;
	}
	rep(i,1,n - 1) add(i,i + 1);
	add(1,n);
	rep(i,1,m){
		int u,v;
		scanf("%d%d",&u,&v);
		u++;v++;
		add(u,v);
	}
	ord.clear();Q.clear();
	rep(u,1,n) if(SZ(G[u]) <= 2) Q.eb(u);
	while(!Q.empty()){
		int u = Q.back();
		Q.pop_back();
		ord.eb(u);
		for(int v:G[u]){
			if(!adj[u][0]) adj[u][0] = v;
			else if(!adj[u][1]) adj[u][1] = v;
			else assert(0);
		}
		if(adj[u][0]) del(u,adj[u][0]);
		if(adj[u][1]) del(u,adj[u][1]);
		if(adj[u][0] && adj[u][1]) add(adj[u][0],adj[u][1]);
	}
	while(!ord.empty()){
		int u = ord.back();
		ord.pop_back();
		ans[u] = 0;
		if(!ans[adj[u][0]] || !ans[adj[u][1]]) ans[u] = 1;
	}
	rep(u,1,n){
		if(!ans[u]) printf("B");
		else printf("R");
	}
	printf("\n");
}

int main(){	
//	freopen("test.in","r",stdin);
	scanf("%d",&T);
	while(T--) solve();
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 15608kb

input:

3
3 0
4 1
1 3
6 3
0 2
2 4
4 0

output:

RRB
RRRB
RBRRBR

result:

ok ok (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 146ms
memory: 15884kb

input:

100000
9 6
2 0
4 6
3 6
0 6
0 7
2 6
3 0
5 2
2 4
2 0
6 3
1 5
4 1
2 4
9 6
3 1
6 4
8 1
3 6
1 6
8 6
3 0
7 4
3 0
4 0
6 4
3 1
7 4
5 1
5 0
3 1
1 4
4 1
1 3
6 3
2 4
4 0
2 0
6 3
3 0
1 3
5 3
7 4
0 5
2 5
5 1
3 5
8 5
4 1
5 1
5 0
1 3
5 7
3 0
8 5
0 2
4 6
0 6
0 3
4 0
8 5
5 1
1 4
5 0
3 1
5 7
3 0
10 7
0 2
9 2
5 8
3 9
...

output:

BRBBBRBBR
RRB
RRBRB
BRBRBR
BRBRBRBRR
RRB
RRBRBRB
RRBRBRB
BRBR
BRBRBR
BRBRBR
BRBRBRR
BRBRBRBR
RRB
RRBRBRBR
RRBRBRBR
RRB
RRBRBRBRRB
BRBRBRBR
RRBRBRBRRB
RRBRBRBRRB
RRBRBRBRRB
RRB
RRBRBRB
BRBRBR
BRBRBRBR
BRBR
BRBRBRB
RRBRBRBRRB
RRBRBRB
BRBRBRBR
BRBRBR
BRBRBR
RRB
RRB
BRBRBRBRR
BRBRBRB
BRBRR
RRBRBRBRRB
RR...

result:

wrong answer cycle detected (test case 1)