QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#528646#8770. ComparatorLittleCubeWA 111ms3764kbC++174.2kb2024-08-23 18:25:152024-08-23 18:25:15

Judging History

你现在查看的是最新测评结果

  • [2024-08-23 18:25:15]
  • 评测
  • 测评结果:WA
  • 用时:111ms
  • 内存:3764kb
  • [2024-08-23 18:25:15]
  • 提交

answer

#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
#define pll pair<ll, ll>
#define pdd pair<double, double>
#define F first
#define S second
#define all(x) x.begin(), x.end()
using namespace std;

int pri(char c)
{
    switch(c)
    {
        case '=':
        return 1;
        case '&':
        return 2;
        case '|':
        return 3;
        case '^':
        return 4;
        case ')':
        return 5;
        case '(':
        return 6;
    }
    return 0;
}

int eval(string s, int x, int y)
{
    vector<int> res;
    vector<char> ops;
    s = "(" + s + ")";
    for (auto c : s)
    {
        if ("xy01"s.find(c) != string::npos)
        {
            if (c == 'x')
                res.emplace_back(x);
            else if (c == 'y')
                res.emplace_back(y);
            else if (c == '0')
                res.emplace_back(0);
            else if (c == '1')
                res.emplace_back(1);
            while (ops.back() == '!')
                res.back() = !res.back(), ops.pop_back();
        }
        else if (c == '(')
            ops.emplace_back('(');
        else if ("=&|^)"s.find(c) != string::npos)
        {
            while (pri(ops.back()) <= pri(c))
            {
                int b = res.back(); res.pop_back();
                int a = res.back(); res.pop_back();
                if (ops.back() == '=')
                    res.emplace_back(a == b);
                else if (ops.back() == '&')
                    res.emplace_back(a && b);
                else if (ops.back() == '^')
                    res.emplace_back(a ^ b);
                else if (ops.back() == '|')
                    res.emplace_back(a || b);
                ops.pop_back();
            }
            if (c == ')') 
            {
                ops.pop_back(); // (
                while (!ops.empty() && ops.back() == '!')
                    res.back() = !res.back(), ops.pop_back();
            }
            else ops.emplace_back(c);
        }
        else if (c == '!')
            ops.emplace_back('!');
    }
    return res.back();
}

int N, K;
pii rule[10][10][2][2], res[1024][10][2];
bitset<1024> G[1024];

signed main()
{
    ios::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);
    cin >> N >> K;
    for (int i = 0; i < K; i++)
        for (int j = 0; j < K; j++)
            for (int x = 0; x <= 1; x++)
                for (int y = 0; y <= 1; y++)
                    rule[i][j][x][y] = pii(N + 2, -1);
    for (int i = 1; i <= N; i++)
    {
        int a, b, ret;
        string s;
        cin >> a >> b >> s >> ret;
        a--, b--;
        for (int x = 0; x <= 1; x++)
            for (int y = 0; y <= 1; y++)
                if (eval(s, x, y))
                    rule[a][b][x][y] = pii(i, ret);
    }
    int def;
    cin >> def;
    for (int i = 0; i < K; i++)
        for (int j = 0; j < K; j++)
            for (int x = 0; x <= 1; x++)
                for (int y = 0; y <= 1; y++)
                    rule[i][j][x][y] = min(rule[i][j][x][y], pii(N + 1, def));
    
    for (int i = 0; i < (1 << K); i++)
        for (int j = 0; j < K; j++)
            for (int y = 0; y <= 1; y++)
            {
                res[i][j][y] = pii(N + 1, def);
                for (int k = 0; k < K; k++)
                    res[i][j][y] = min(res[i][j][y], rule[k][j][(i >> k) & 1][y]);
            }
    
    for (int i = 0; i < (1 << K); i++)
        for (int j = 0; j < (1 << K); j++)
        {   
            pii ret = pii(N + 1, def); 
            for (int k = 0; k < K; k++)
                ret = min(ret, res[i][k][(j >> k) & 1]);
            G[i][j] = (ret.S != 0);
        }


    int bad = 0;
    for (int i = 0; i < (1 << K); i++)
        if (G[i][i]) bad++;
    cout << bad << ' ';

    bad = 0;
    for (int i = 0; i < (1 << K); i++)
        for (int j = 0; j < (1 << K); j++)
            if (G[i][j] && G[j][i]) bad++;
    cout << bad << ' ';


    bad = 0;
    for (int i = 0; i < (1 << K); i++)
        for (int j = 0; j < (1 << K); j++)
            if (G[i][j]) 
                bad += (G[j] & (~G[i])).count();
    cout << bad << '\n';
}

/*
3 2
1 1 !((!x=0)|(!y=1)) 1
1 1 (x=1)&(y=(x^x)) 0
2 2 (x=1)|(y=0) 0
1
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3580kb

input:

3 2
1 1 (x=0)&(y=1) 1
1 1 (x=1)&(y=(x^x)) 0
2 2 (x=1)|(y=0) 0
1

output:

0 0 0

result:

ok single line: '0 0 0'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3580kb

input:

4 3
2 1 x=0&(y=1) 1
1 2 !x^!!y 0
2 3 ((x|1)=y)&1&1 1
3 1 !x&!x&!x 0
1

output:

3 25 52

result:

ok single line: '3 25 52'

Test #3:

score: -100
Wrong Answer
time: 111ms
memory: 3764kb

input:

1413 3
1 3 0 0
3 3 !x 0
2 2 x=0 1
1 2 !y^0 1
2 3 (x^1) 0
3 2 ((!0)) 1
1 1 !!1=(y) 0
2 2 !(1^x)&y 1
3 2 (y)&1|!!1 0
3 1 !x=(y&y=y) 0
2 1 (((!1)^!x)) 1
2 3 !0=(0&y)=1&y 0
1 2 ((((!0)))|!1) 0
3 1 !(y=!1=x|(!x)) 0
1 1 ((((y=!y)))&!0) 0
2 3 ((y=1)^!1^!!1|0) 1
2 3 1|(!x)&!x|1|(x=1) 1
2 3 !0^!!!!y&0=(!1&!0...

output:

5 41 48

result:

wrong answer 1st lines differ - expected: '4 16 0', found: '5 41 48'