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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#520916#6669. Mapamss0 0ms0kbC++142.5kb2024-08-15 17:27:392024-08-15 17:27:40

Judging History

你现在查看的是最新测评结果

  • [2024-08-15 17:27:40]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-08-15 17:27:39]
  • 提交

answer

#include <bits/stdc++.h>
#define p pair<ll, ll>
#define x first
#define y second

using namespace std;
using ll = long long;

const int N = 2e5+5;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9+7;
const int BAZA = 69313;

int n;
int t;
p a[N];
vector<ll> k;
vector<ll> v;
int m, q;
string s;


ll add(ll x, ll y){
	if(x + y < 0) return x + y + MOD;
	else return (x + y) % MOD;
}
ll mul(ll x, ll y){
	return (x * y) % MOD;
}

ll pot(ll baza, ll exp){
	if(exp == 0) return 1;
	ll pol = pot(baza, exp / 2);
	if(exp % 2) return mul(baza, mul(pol, pol));
	return mul(pol, pol);
}

ll _div(ll x, ll y){
	return mul(x, pot(y, MOD - 2));
}

void mulk(ll tk){
	 v.insert(v.begin(), 0);
	 for(int i = 0; i < v.size() - 1; i++){
	 	cout << "x^" << i << ": ";
	 	cout << v[i] << " + " << v[i + 1] << " * " << -tk << " = " << add(v[i], mul(v[i + 1], -tk)) << "\n";
	 	v[i] = add(v[i], mul(v[i + 1], -tk));
	 }
}

void encode(){
	for(int i = 0; i < n; i++){
		cin >> a[i].x >> a[i].y;
	}
	for(int i = 0; i< n; i++){
		k.push_back(0);
	}
	for(int i = 0; i< n; i++){
		ll konst = 1;
		int ind = 0;
		if(i != n - 1) ind = i + 1;
		v.clear();
		v.push_back(-a[ind].x);
		v.push_back(1);
		
		cout << "v: \n";
		cout << 1 << " " << -a[ind].x << "\n";
		for(int j = 0; j < n; j++){
			if(i == j || j == ind) continue;
			mulk(a[j].x);
			for(int l = 0; l < v.size(); l++){
				cout << v[l] << " ";
			}
			cout << "\n";
			
		}
		cout << "-------\n";
		for(int j = 0; j < n; j++){
			if(i != j){
				konst = mul(add(a[i].x, - a[j].x), konst);
			}
		}
		cout << "here\n";
		konst = _div(a[i].y, konst);
		cout << "here\n";
		for(int j = 0; j < v.size(); j++){
			k[j] = add(k[j], mul(v[j], konst));
		}
		cout << "here\n";
	}
	for(int i = 0; i< n; i++){
		cout << k[i] << "\n";
	}
	int uk = 0;
	cout << n * 30 << "\n";
	for(int i = 0; i< n; i++){	
		for(int j = 0; j< 30; j++){	
			bool b = k[i] & (1 << j);
			cout << b;
		}
	}
}

ll calc(ll x){
	ll r = 0;
	for(int i = 0; i < n; i++){
		r = add(r, mul(k[i], pot(x, i)));
	}
	return r;
}

void decode(){
	cin >> q >> m;
	
	cin >> s;
	for(int i = 0; i<m / 30; i++){
		int tc = 1;
		int br = 0;
		for(int j = 0; j < 30; j++){
			bool b = s[i * 30 + j] - '0';
			br += b * tc;
			tc *= 2;
		}
		k.push_back(br);
	}
	for(int i = 0; i < q; i++){
		int b;
		cin >> b;
		cout << calc(b) << "\n";
	}
}

int main(){
	//ios_base::sync_with_stdio(false); cin.tie(NULL);
	
	cin >> t;
	cin >> n;
	if(t == 1) encode();
	else decode();
	return 0;
}

詳細信息

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

1
100
495528311 963488152
269613430 443544124
700489871 792354118
151890319 506569919
180452297 13229948
684464994 543841485
978085128 903812192
238355172 441140842
28061035 783291471
530823766 718942732
936853023 439421263
201361623 226633955
304644844 778868118
864860135 461524170
88300500 6959354...

output:

v: 
1 -269613430
x^0: 0 + -269613430 * -700489871 = 478537205
x^1: -269613430 + 1 * -700489871 = 29896706
478537205 29896706 1 
x^0: 0 + 478537205 * -151890319 = 787977788
x^1: 478537205 + 29896706 * -151890319 = 298935131
x^2: 29896706 + 1 * -151890319 = 878006394
787977788 298935131 878006394 1 
x...

input:

2
100 79 0

76056186
748668825
977827900
978085128
116036067
867988891
936853023
382851074
572126679
923962179
896550946
684464994
873686539
38704825
864860135
275947064
317677889
151890319
408905047
491275816
521631260
85278475
216446252
676199581
593919557
298889276
937180891
238355172
205533698
3...

output:


result: