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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#516360#8795. Mysterious SequenceSocialPandaWA 0ms3972kbC++231.4kb2024-08-12 16:25:072024-08-12 16:25:07

Judging History

你现在查看的是最新测评结果

  • [2024-08-12 16:25:07]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3972kb
  • [2024-08-12 16:25:07]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
//#define int long long
//#define LL long long
#define double long double
//#define lf Lf
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define endl "\n"
#define PII pair<int,int>
#define Gheap priority_queue<int,vector<int>,greater<int>>
#define Lheap priority_queue<int>
#define MAXN 0x3f3f3f3f
#define MINN -0x3f3f3f3f
using namespace std;
//const int N=1e6+100,M=2*N;
//int e[N],w[M],h[M],ne[M],idx;

double aa,bb,bg,ed;
double eps = 1e-12;
int n;

bool check(double num)
{
	double preB=bg;
	double preA=num;
	for(int i=3;i<=n;i++)
	{
		double newone = preA*aa+preB*bb;
		preB=preA;
		preA=newone;
	}
	if(preA-ed>eps) return false;
	else return true;
}

void solve()
{
	unordered_map<char,double> mp;
	cin>>aa>>bb>>n>>bg>>ed;

	double ll=-10.0,rr=10.0;

	while(rr-ll>eps)
	{
		double mid = (ll+rr)/2.0;
		if(check(mid)) ll=mid;
		else rr=mid;
	}

	printf("%.9Lf\n",bg);
	printf("%.9Lf\n",ll);
	double preB=bg;
	double preA=ll;
	for(int i=3;i<n;i++)
	{
		double newone = preA*aa+preB*bb;
		preB=preA;
		preA=newone;
		printf("%.9Lf\n",newone);
	}
	printf("%.9Lf\n",ed);
    
}

int main()
{
    std::ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int tt=1;
    //cin >> tt;
    while(tt--) solve();
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3972kb

input:

1.0 1.0 10 1 10

output:

1.000000000
-0.323529412
0.676470588
0.352941176
1.029411765
1.382352941
2.411764706
3.794117647
6.205882353
10.000000000

result:

ok 10 numbers

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3912kb

input:

1 1 2 1 100

output:

1.000000000
10.000000000
100.000000000

result:

wrong answer 2nd numbers differ - expected: '100.0000000', found: '10.0000000', error = '0.9000000'