QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#515812#9168. Square Locatorucup-team3695WA 192ms10692kbPython3809b2024-08-12 08:39:062024-08-12 08:39:06

Judging History

你现在查看的是最新测评结果

  • [2024-08-12 08:39:06]
  • 评测
  • 测评结果:WA
  • 用时:192ms
  • 内存:10692kb
  • [2024-08-12 08:39:06]
  • 提交

answer

a,b,c,d=map(int,input().split())
base=(0,int(round(a**0.5)))

def add(p,q):
	return p[0]+q[0],p[1]+q[1]

def dist(q):
	return q[0]**2+q[1]**2

def eval(x,y):
	delt=(x,y)
	rot=(y,-x)
	return max(abs(dist(add(base,delt))-b),abs(dist(add(base,add(delt,rot)))-c),abs(dist(add(base,rot))-d))

def evalx(x):
	loy=-10**9
	hiy=10**9
	for _ in range(200):
		m1=loy+(hiy-loy)/3
		m2=loy+2*(hiy-loy)/3
		if eval(x,m1)<eval(x,m2):hiy=m2
		else:loy=m1
	y=(loy+hiy)/2
	return eval(x,y),y

lox=-10**9
hix=10**9
for _ in range(200):
	m1=lox+(hix-lox)/3
	m2=lox+2*(hix-lox)/3
	if evalx(m1)[0]<evalx(m2)[0]:hix=m2
	else:lox=m1
x=int(round((lox+hix)/2))
score,y=evalx(x)
y=int(round(y))
A=base
B=add(base,(x,y))
C=add(base,(x+y,y-x))
D=add(base,(y,-x))
print(A[1],*B,*C,*D)
# print(score)

详细

Test #1:

score: 100
Accepted
time: 182ms
memory: 10640kb

input:

36 5 10 41

output:

6 2 1 -3 -1 -5 4

result:

ok Answer is correct

Test #2:

score: 0
Accepted
time: 176ms
memory: 10688kb

input:

1 1 1 1

output:

1 0 1 0 1 0 1

result:

ok Answer is correct

Test #3:

score: 0
Accepted
time: 192ms
memory: 10584kb

input:

1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000

output:

1000000000 0 1000000000 0 1000000000 0 1000000000

result:

ok Answer is correct

Test #4:

score: 0
Accepted
time: 169ms
memory: 10640kb

input:

4 10 8 2

output:

2 1 3 2 2 1 1

result:

ok Answer is correct

Test #5:

score: -100
Wrong Answer
time: 180ms
memory: 10692kb

input:

4 50 104 58

output:

2 -5 -3 -10 2 -5 7

result:

wrong answer Squared distances are incorrect