#pragma GCC optimize(2)

#include <bits/stdc++.h>
#define int long long
#define ll long double
#define pb push_back
#define lc p<<1
#define rc p<<1|1
#define st first
#define nd second
//#define pii pair<int,int>
using namespace std;
inline int read(){
	int x=0,f=1;char ch=getchar();
	for(;!isdigit(ch);ch=getchar())f^=ch=='-';
	for(;isdigit(ch);ch=getchar())x=x*10+(ch^48);
	return f?x:-x;
}
const int N=2e5+5;
const ll inf=1e12;
int n;
ll w,ans[N],T[N],S[N],P[N];
pair<ll,pair<ll,pair<ll,int>>> a[N];
struct SegmentTree{
	pair<ll,int> val[N<<2];
	ll add[N<<2],mul[N<<2];
	void pushdown(int p){
		//mul
		val[lc].st*=mul[p];	val[rc].st*=mul[p];
		add[lc]*=mul[p];	add[rc]*=mul[p];
		mul[lc]*=mul[p];	mul[rc]*=mul[p];
		mul[p]=1.000;
		//add
		val[lc].st+=add[p];	val[rc].st+=add[p];
		add[lc]+=add[p];	add[rc]+=add[p];
		add[p]=0.000;
		return;
	}
	//集体乘以x 
	void modify1(int p,int l,int r,int L,int R,ll x){
		if(L<=l&&r<=R){
			val[p].st*=x;
			add[p]*=x;
			mul[p]*=x;
			return;
		}
		pushdown(p);
		int mid=(l+r)>>1;
		if(L<=mid)modify1(lc,l,mid,L,R,x);
		if(mid<R)modify1(rc,mid+1,r,L,R,x);
		val[p]=min(val[lc],val[rc]);
	}
	//集体增加x 
	void modify2(int p,int l,int r,int L,int R,ll x){
		if(L<=l&&r<=R){
			val[p].st+=x;
			add[p]+=x;
			return;
		}
		pushdown(p);
		int mid=(l+r)>>1;
		if(L<=mid)modify2(lc,l,mid,L,R,x);
		if(mid<R)modify2(rc,mid+1,r,L,R,x);
		val[p]=min(val[lc],val[rc]);
	}
	pair<ll,int> query(int p,int l,int r,int L,int R){
		if(L<=l&&r<=R)return val[p];
		pushdown(p);
		int mid=(l+r)>>1;
		if(R<=mid)return query(lc,l,mid,L,R);
		if(mid<L)return query(rc,mid+1,r,L,R);
		return min(query(lc,l,mid,L,R),query(rc,mid+1,r,L,R));
	}
	void construct(int p,int l,int r){
		add[p]=0.0000;
		mul[p]=1.0000;
		val[p]={inf,l};
		if(l==r)return;
		int mid=(l+r)>>1;
		construct(lc,l,mid);
		construct(rc,mid+1,r);
	}
}f;
signed main(){
	n=read(),w=read();
	for(int i=1;i<=n;++i){
		ll t=read(),s=read(),p=read();
		T[i]=t;
		S[i]=s;
		P[i]=p;
		a[i]={t,{s,{p,i}}};
	}
	sort(a+1,a+n+1);
	f.construct(1,1,n);
	ll now=0.000,sump=0.000;
	int cnt=0;
	for(int i=1;i<=n;++i){
		ll t=a[i].st,s=a[i].nd.st,p=a[i].nd.nd.st;
		int pos=a[i].nd.nd.nd,idx;
		ll rate;
		pair<ll,int> x=f.query(1,1,n,1,n);
		while(cnt&&x.st<=t-now){
			--cnt;
			ll d=x.st;
			now+=x.st;
			idx=x.nd;
			ans[idx]=now;
			rate=(sump-P[idx])/sump;
			sump-=P[idx];
			f.modify2(1,1,n,1,n,-d);
			f.modify1(1,1,n,1,n,rate);
			f.modify2(1,1,n,idx,idx,inf);
			x=f.query(1,1,n,1,n);
		}
		f.modify2(1,1,n,1,n,-(t-now));
		now=t;
		x=f.query(1,1,n,pos,pos);
		f.modify2(1,1,n,pos,pos,-x.st);
		if(cnt){
			rate=(sump+p)/sump;
			f.modify1(1,1,n,1,n,rate);
		}
		sump+=p;
		ll tmd=(s/(w*(p/sump)));
		f.modify2(1,1,n,pos,pos,tmd);
		++cnt;
	}
	while(cnt){
		pair<ll,int> x=f.query(1,1,n,1,n);
		--cnt;
		ll d=x.st;
		now+=x.st;
		int idx=x.nd;
		ans[idx]=now;
		ll rate=(sump-P[idx])/sump;
		sump-=P[idx];
		f.modify2(1,1,n,1,n,-d);
		f.modify1(1,1,n,1,n,rate);
		f.modify2(1,1,n,idx,idx,inf);
	}
	for(int i=1;i<=n;++i){
		printf("%.10Lf\n",ans[i]);
	}
	return 0;
}