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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#515442 | #2265. Short Coding | Cheek_support# | WA | 0ms | 3816kb | C++20 | 3.8kb | 2024-08-11 17:50:17 | 2024-08-11 17:50:17 |
Judging History
answer
#pragma GCC optimize("Ofast")
#pragma GCC optimize("inline")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#define DEBUG_VAR(x) { cerr << "* "#x" = " << x << endl; }
#define DEBUG_ARR(arr, l, r) { \
cerr << "* "#arr"[" << l << ", " << r << "]:"; \
for(auto it = l, itr = r; it <= itr; it++) \
cerr << arr[it] << ", "; \
cerr << endl; \
}
#define DEBUG_FMT(...) { cerr << "* "; fprintf(stderr, __VA_ARGS__); }
#define DEBUG_HERE { DEBUG_FMT("Passing [%s] in LINE %d\n", __FUNCTION__, __LINE__); }
using namespace std;
using LL = long long;
using ULL = unsigned long long;
const int N = 1024, M = 11;
int n, m;
char a[N][N];
struct Command
{
int type;
int l;
};
Command c[N], ans[N];
bool vis[11][11][4][10];
const int dx[] = {-1, 0, 1, 0}, dy[] = {0, 1, 0, -1}; // -> right
int sx, sy;
void print(int len)
{
cout << len << endl;
for(int i = 1; i <= len; i++) {
if(c[i].type == 1) {
cout << "GOTO " << c[i].l << endl;
} else if(c[i].type == 2) {
cout << "IF-OPEN " << c[i].l << endl;
} else if(c[i].type == 3) {
cout << "FORWARD" << endl;
} else if(c[i].type == 4) {
cout << "LEFT" << endl;
} else {
cout << "RIGHT" << endl;
}
}
}
void check(int len)
{
memset(vis, 0, sizeof vis);
int pc = 1;
int x = sx, y = sy;
int d = 2;
while(true) {
if(vis[x][y][d][pc]) return;
vis[x][y][d][pc] = true;
if(a[x][y] == 'G') break;
Command com = c[pc];
if(com.type == 1) { // GOTO
pc = com.l;
} else if(com.type == 2) { // IF-OPEN
int nx = x + dx[d], ny = y + dy[d];
bool is_open = true;
if(nx < 1 || nx > n || ny < 1 || ny > m) {
is_open = false;
} else if(a[nx][ny] == '#') {
is_open = false;
}
if(is_open) {
pc = com.l;
} else {
if(pc == len) pc = 1;
else pc++;
}
} else if(com.type == 3) { // FORWARD
int nx = x + dx[d], ny = y + dy[d];
bool is_open = true;
if(nx < 1 || nx > n || ny < 1 || ny > m) {
is_open = false;
} else if(a[nx][ny] == '#') {
is_open = false;
}
if(is_open) {
x = nx, y = ny;
}
if(pc == len) pc = 1;
else pc++;
} else if(com.type == 4) { // LEFT
d = (d + 4 - 1)%4;
if(pc == len) pc = 1;
else pc++;
} else {
d = (d + 1)%4;
if(pc == len) pc = 1;
else pc++;
}
}
print(len);
exit(0);
}
void dfs(int step, int max_step)
{
if(step > max_step) {
check(max_step);
return;
}
for(int i = 1; i <= 5; i++) {
c[step].type = i;
if(i == 1 || i == 2) {
for(int j = 1; j <= max_step; j++) {
c[step].l = j;
}
}
dfs(step + 1, max_step);
}
}
int main()
{
// freopen("1.in", "r", stdin);
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i++) {
scanf("%s", a[i] + 1);
}
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= m; j++) {
if(a[i][j] == 'S') {
sx = i, sy = j;
}
}
}
for(int i = 1; i <= 5; i++) {
dfs(1, i);
}
// c[1].type = 4;
// c[2].type = 2; c[2].l = 5;
// c[3].type = 5;
// c[4].type = 1; c[4].l = 2;
// c[5].type = 3;
// print(5);
// check(5);
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3632kb
input:
4 2 S# .# .# G.
output:
1 FORWARD
result:
ok correct answer!
Test #2:
score: 0
Accepted
time: 0ms
memory: 3764kb
input:
3 6 ##S..# #..##. .G..#.
output:
2 FORWARD RIGHT
result:
ok correct answer!
Test #3:
score: 0
Accepted
time: 0ms
memory: 3780kb
input:
3 7 ....S## .#.#... ##.#.G#
output:
2 FORWARD LEFT
result:
ok correct answer!
Test #4:
score: 0
Accepted
time: 0ms
memory: 3764kb
input:
4 8 ...S.#.# ##..#.#. ###...#. #.#.#G.#
output:
3 FORWARD FORWARD LEFT
result:
ok correct answer!
Test #5:
score: 0
Accepted
time: 0ms
memory: 3816kb
input:
3 5 .S#.. ..... ..#G.
output:
3 FORWARD LEFT FORWARD
result:
ok correct answer!
Test #6:
score: -100
Wrong Answer
time: 0ms
memory: 3620kb
input:
10 10 .....S#... ...#...... ....##.... .#.....#.. ....#..... ..#....... ...#...... .......... .#...#.... G.#..#...#
output:
4 LEFT FORWARD FORWARD FORWARD
result:
wrong answer wrong answer. the length of your program is 3 but the optimal one is 4.