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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#514940#7612. Matrix InverseNeil_QianWA 242ms219684kbC++142.6kb2024-08-11 13:39:502024-08-11 13:39:50

Judging History

你现在查看的是最新测评结果

  • [2024-08-11 13:39:50]
  • 评测
  • 测评结果:WA
  • 用时:242ms
  • 内存:219684kb
  • [2024-08-11 13:39:50]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;using ll=long long;
const int N=2002,MOD=1e9+7;mt19937_64 rnd(time(0));
const int M=2e7+2;char *p1,*p2,buf[M];
#define nc() (p1==p2&&(p2=(p1=buf)+fread(buf,1,M,stdin),p1==p2)?EOF:*p1++)
inline int read(){
	register int x=0,f=1;register char ch=nc();
	while(ch<48||ch>57)ch=nc();
	while(ch>=48&&ch<=57)x=(x<<3)+(x<<1)+(ch^48),ch=nc();
	return x*f;
}
inline ll qpow(ll x,ll y=MOD-2){
	ll res=1;
	while(y){
		if(y&1)(res*=x)%=MOD;
		(x*=x)%=MOD,y>>=1;
	}
	return res;
}
struct ANS{
	ll x,y,w;
	bool operator <(const ANS b){return (x!=b.x?x<b.x:y<b.y);}
};vector<ANS> ans;
struct matrix{
	ll n,m,a[N][N];
	inline void reset(ll r,ll c,ll opt=-1){
		n=r,m=c;
		if(!opt)memset(a,0,sizeof(a));
		else if(opt==1){
			memset(a,0,sizeof(a));
			for(int i=1;i<=min(n,m);i++)a[i][i]=1;
		}
		else if(opt==2){
			for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)a[i][j]=rnd()%MOD;
		}
	}
	matrix operator *(const matrix b){
		matrix res;res.reset(n,b.m,0);
		for(int i=1;i<=n;i++)for(int j=1;j<=b.m;j++)for(int k=1;k<=m;k++)
			(res.a[i][j]+=a[i][k]*b.a[k][j]%MOD)%=MOD;
		return res;
	}
}a,b,v,va;ll n,idcol[N],idrow[N],recol[N],rerow[N],x[N][15],res[15];vector<ll> col,row;
inline void solve(){
	for(int i=1,r,tp=1;i<=(int)row.size()+1;i++){
		tp=r=tp+1;
		for(int j=tp+1;j<=n;j++)if(x[j][i]>x[r][i])r=j;
		if(r!=tp)swap(x[tp],x[r]);
		if(!x[tp][i]){tp--;continue;}
		ll one=qpow(x[tp][i]);
		for(int j=1;j<=n;j++)if(j!=tp){
			ll mul=(x[j][i]*one)%MOD;
			for(int k=1;k<=(int)row.size()+1;k++)(x[j][k]+=MOD-(x[tp][k]*mul)%MOD)%=MOD;
		}
	}
	for(int i=1;i<=(int)row.size();i++)res[i]=(x[i][row.size()+1]*qpow(x[i][i]))%MOD;
}
int main(){
	n=read(),a.reset(n,n),b.reset(n,n);
	for(int i=1;i<=n;i++)for(int j=1;j<=n;j++)a.a[i][j]=read();
	for(int i=1;i<=n;i++)for(int j=1;j<=n;j++)b.a[i][j]=read();
	v.reset(1,n,2),va=(v*a)*b;
	for(int i=1;i<=n;i++)if(v.a[1][i]!=va.a[1][i])
		col.emplace_back(i),idcol[i]=col.size(),recol[col.size()]=i;
	v.reset(n,1,2),va=b*(a*v);
	for(int i=1;i<=n;i++)if(v.a[i][1]!=va.a[i][1])
		row.emplace_back(i),idrow[i]=row.size(),rerow[row.size()]=i;
	for(ll c:col){
		for(int i=1;i<=n;i++){
			ll to=(i==c),now=0;
			for(int j=1;j<=n;j++)
				(idrow[j]?x[i][idrow[j]]=a.a[i][j]:(now+=a.a[i][j]*b.a[j][c]%MOD)%=MOD);
			x[i][row.size()+1]=(to-now+MOD)%MOD;
		}
		solve();
		for(int i=1;i<=(int)row.size();i++)
			if(b.a[rerow[i]][c]!=res[i])ans.emplace_back(ANS{rerow[i],c,res[i]});
	}
	sort(ans.begin(),ans.end()),printf("%lld\n",ans.size());
	for(ANS x:ans)printf("%lld %lld %lld\n",x.x,x.y,x.w);
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 27ms
memory: 135252kb

input:

1
953176428
107682094

output:

0

result:

ok single line: '0'

Test #2:

score: -100
Wrong Answer
time: 242ms
memory: 219684kb

input:

1995
586309310 548144807 578573993 437893403 641164340 712256053 172321263 108058526 768610920 123320669 762746291 856047593 979279376 29067913 309867338 292286426 45124325 239705174 675003623 213743652 620561338 116308277 695369179 669459894 682522334 846995555 159510341 999359657 645579085 7499563...

output:

4
827 238 0
827 499 0
1466 238 0
1466 499 0

result:

wrong answer 1st lines differ - expected: '2', found: '4'