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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#509750#9156. 百万富翁ewrilan#15 611ms25432kbC++202.3kb2024-08-08 18:15:412024-08-08 18:15:42

Judging History

你现在查看的是最新测评结果

  • [2024-08-08 18:15:42]
  • 评测
  • 测评结果:15
  • 用时:611ms
  • 内存:25432kb
  • [2024-08-08 18:15:41]
  • 提交

answer

//
#ifndef __SIZEOF_INT128__
  #define __SIZEOF_INT128__
#endif
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace chrono;
using namespace __gnu_pbds;
template <typename T> using oset =  tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define rep(i, p, k) for(int i(p); i < (k); ++i)
#define per(i, p, k) for(int i(p); i > (k); --i)
#define sz(x) (int)(x).size()
#define sc static_cast
typedef long long ll;
typedef long double ld;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef __int128_t lll;
//#define int ll
template <typename T = int> using par = std::pair <T, T>;
#define fi first
#define se second
#define test int _number_of_tests(in()); while(_number_of_tests--)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb emplace_back
struct Timer {
    string name{""};
    time_point<high_resolution_clock> end, start{high_resolution_clock::now()};
    duration<float, std::milli> dur;
    Timer() = default;
    Timer(string nm): name(nm) {}
    ~Timer() {
        end = high_resolution_clock::now(); dur= end - start;
        cout << "@" << name << "> " << dur.count() << " ms" << '\n';
    }
};
template <typename T = int> inline T in()
{
    static T x;
    std::cin >> x;
    return x;
}
std::string yn(bool b)
{
    if(b) return "YES\n";
    else return "NO\n";
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par);
template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector <T>& wek)
{
    for(const auto& i : wek)out << i << ' ';
    return out;
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par)
{
    out << '{'<<par.first<<", "<<par.second<<"}";
    return out;
}
#define show(x) cerr << #x << " = " << x << '\n';
#include "richest.h"
int richest(int n, int t ,int s)
{
    // if(t == 1){
        vector <int> a, b;
        rep(i, 0, n)rep(j, i+1, n){
            a.pb(i);
            b.pb(j);
        }
        vector <int> o(ask(a, b));
        vector <int> l(n);
        for(auto i: o)++l[i];
        rep(i, 0, n)if(l[i] == n-1)return i;
    // }
}

详细


Pretests

Pretest #1:

score: 15
Accepted
time: 608ms
memory: 25432kb

input:

1000 1 499500 957319859

output:

Correct
7127326332295218295
1.000000
1331569654267968081

result:

points 1.0 Correct

Pretest #2:

score: 0
Time Limit Exceeded

input:

1000000 20 2000000 29091473

output:

Unauthorized output

result:



Final Tests

Test #1:

score: 15
Accepted
time: 611ms
memory: 25336kb

input:

1000 1 499500 957319857

output:

Correct
7127326332295218295
1.000000
1331569654267968081

result:

points 1.0 Correct

Test #2:

score: 0
Memory Limit Exceeded

input:

1000000 20 2000000 29091471

output:

Unauthorized output

result: