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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#508816 | #7671. Metal Processing Plant | KiharaTouma | WA | 1ms | 6016kb | C++23 | 2.4kb | 2024-08-07 20:26:34 | 2024-08-07 20:26:34 |
Judging History
answer
//qoj7671
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 410;
int n, e[N][N], tot, ans = 2e9 + 10, fa[N], siz[N], col[N];
vector<int> son[N];
struct edge{
int val, x, y;
} eg[N*N];
bool cmp(edge x, edge y){
return x.val > y.val;
}
int gf(int x){
return fa[x] == x ? x : gf(fa[x]);
}
void dfs(int x, int cl){
col[x] = cl;
for(int i : son[x]){
dfs(i, 1-cl);
}
}
void mg(int x, int y){
if(siz[x] > siz[y]) swap(x, y);
son[y].push_back(x);
siz[y] += siz[x];
dfs(x, 1 - col[y]);
}
int dfn[N], low[N], scc[N], sct, cnt, ins[N], st[N], tp;
vector<int> g[N];
void add(int x, int y){
g[x].push_back(y);
}
void tg(int x){
dfn[x] = low[x] = ++ cnt;
ins[x] = 1;
st[++tp] = x;
for(int i : g[x]){
if(!dfn[i]){
tg(i);
low[x] = min(low[x], low[i]);
} else if(ins[i]){
low[x] = min(low[x], dfn[i]);
}
}
if(dfn[x] == low[x]){
++ sct;
while(st[tp] != x){
scc[st[tp]] = sct;
ins[st[tp]] = 0;
-- tp;
}
scc[st[tp]] = sct;
ins[st[tp]] = 0;
-- tp;
}
}
bool chk(int p, int q){
sct = cnt = tp = 0;
for(int i = 1; i <= n + n; ++ i){
vector<int> ().swap(g[i]);
dfn[i] = low[i] = scc[i] = ins[i] = st[i] = 0;
}
for(int i = 1; i <= tot; ++ i){
int x = eg[i].x, y = eg[i].y;
if(i == p){
add(x + n, x);
add(y + n, y);
} else if(i < p){
add(x, y + n);
add(x + n, y);
add(y, x + n);
add(y + n, x);
} else if(eg[i].val > q){
add(x + n, y);
add(y + n, x);
}
}
for(int i = 1; i <= n + n; ++ i){
if(!dfn[i]){
tg(i);
}
}
for(int i = 1; i <= n; ++ i){
if(scc[i] == scc[i+n]){
return 0;
}
}
return 1;
}
int main(){
scanf("%d", &n);
for(int i = 1; i <= n; ++ i){
fa[i] = i;
siz[i] = 1;
col[i] = 0;
for(int j = i + 1; j <= n; ++ j){
scanf("%d", &e[i][j]);
e[j][i] = e[i][j];
eg[++tot] = (edge){ e[i][j], i, j };
}
}
sort(eg + 1, eg + tot + 1, cmp);
for(int i = 1; i <= tot; ++ i){
int flg = 0;
if(gf(eg[i].x) == gf(eg[i].y)){
if(col[eg[i].x] == col[eg[i].y]){
flg = 1;
} else {
continue;
}
}
mg(eg[i].x, eg[i].y);
int l = i + 1, r = tot;
while(l < r){
int mid = l + r + 1 >> 1;
if(chk(i, eg[mid].val)){
l = mid;
} else {
r = mid - 1;
}
}
if(chk(i, l)){
ans = min(ans, eg[i].val + eg[l].val);
}
if(flg){
break;
}
}
printf("%d\n", ans);
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 6016kb
input:
5 4 5 0 2 1 3 7 2 0 4
output:
4
result:
ok single line: '4'
Test #2:
score: 0
Accepted
time: 1ms
memory: 3804kb
input:
7 1 10 5 5 5 5 5 10 5 5 5 100 100 5 5 10 5 5 98 99 3
output:
15
result:
ok single line: '15'
Test #3:
score: -100
Wrong Answer
time: 1ms
memory: 3772kb
input:
1
output:
2000000010
result:
wrong answer 1st lines differ - expected: '0', found: '2000000010'