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ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#508494	#7660. Investigating Frog Behaviour on Lily Pad Patterns	Poknik	TL	102ms	15676kb	C++20	951b	2024-08-07 16:29:50	2024-08-07 16:29:51

Judging History

This is the latest submission verdict.

[2024-08-07 16:29:51]
Judged

Verdict: TL
Time: 102ms
Memory: 15676kb

Show

[2024-08-07 16:29:50]
Submitted

answer

#include<bits/stdc++.h>
#define INF 250100
#define maxx 100000007
#define pi 3.14159265359
using namespace std;
typedef long long LL;
set<int> emptypos;
int pos[INF]={0};
int qing[INF]={0};
int main()
{
//    ios::sync_with_stdio(false);
//    cin.tie(0);
//    cout.tie(0);
	//freopen("in.txt","r",stdin);
	int n;
	scanf("%d",&n);
	int x;
	for(int i=1;i<=n;i++)
	{
		scanf("%d",&x);
		pos[x]=i;
		qing[i]=x;
	}
	for(int i=1;i<=qing[n];i++)
	{
		if(pos[i]==0)
			emptypos.insert(i);
	}
//    set<int>::iterator it;
//    for(it=emptypos.begin();it!=emptypos.end();it++)
//        cout<<*it<<" ";
	for(int i=qing[n]+1;i<=INF;i++)
		emptypos.insert(i);
	int t;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d",&x);
		int xx=qing[x];
		int y=*upper_bound(emptypos.begin(),emptypos.end(),xx);
		printf("%d\n",y);
		emptypos.erase(y);
		emptypos.insert(xx);
		pos[y]=x;
		pos[xx]=0;
		qing[x]=y;
	}
	return 0;
}

源文件, 语言: C++20

详细

Test #1:

score: 100

Accepted

time: 43ms

memory: 15676kb

input:

output:

4
6
8

result:

ok 3 lines

Test #2:

score: 0

Accepted

time: 54ms

memory: 15528kb

input:

output:

result:

ok 4 lines

Test #3:

score: 0

Accepted

time: 102ms

memory: 15608kb

input:

output:

result:

ok 20 lines

Test #4:

score: -100

Time Limit Exceeded

input:

10
2 4 6 7 8 9 10 12 13 14
1000
4
5
4
6
2
5
2
9
6
10
6
2
1
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7
3
9
5
2
10
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4
4
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6
1
10
9
10
3
7
10
5
9
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1
7
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6
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7
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8
1
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2
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2
7
2
2
1
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3
3
10
5
4
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5
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1
8
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2
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3...

output: